在翻译动画中是否可以获取 ImageView 的实时坐标?
Is it possible to get real time coordinates of an ImageView while it is in Translate animation?
我在执行翻译动画的 ImageView 中有一个子弹图像。
我需要显示实时坐标以实时显示它与目标的距离。
ImageView myimage = (ImageView)findViewById(R.id.myimage);
Animation animation = new TranslateAnimation(100, 200, 300, 400);
animation.setDuration(1000);
myimage.startAnimation(animation);
animation.setRepeatCount(Animation.INFINITE);
是否可以在执行 TranslateAnimation 时获取图像的实时 x 和 y 坐标?
如果无法使用 TranslateAnimation,是否有任何其他方法可以在运动时给出图像的实时坐标?
我试过了-
int x = myimage.getLeft();
int y = myimage.getTop();
和
int[] firstPosition = new int[2];
myimage.measure(View.MeasureSpec.EXACTLY, View.MeasureSpec.EXACTLY);
myimage.getLocationOnScreen(firstPosition);
int x = firstPosition[0];
int y = firstPosition[1];
但在这两种方式中,它都给出了 ImageView 的初始静态坐标。
您可以使用 ObjectAnimator
(API 11+):
ImageView iv = (ImageView)findViewById(R.id.markerRed);
// Create animators for x and y axes
ObjectAnimator oax = ObjectAnimator.ofFloat(iv, "translationX", 0f, 100f);
ObjectAnimator oay = ObjectAnimator.ofFloat(iv, "translationY", 0f, 100f);
oax.setRepeatCount(Animation.INFINITE);
oay.setRepeatCount(Animation.INFINITE);
// Combine Animators and start them together
AnimatorSet set = new AnimatorSet();
set.setDuration(1000);
set.playTogether(oax, oay);
set.start();
然后像这样获取动画值:
Log.e("TAG", "X: " + oax.getAnimatedValue() + " Y:" + oay.getAnimatedValue());
如果将这些值添加到初始 ImageView
的坐标中,您将获得当前位置。
我有这样的想法:您可以扩展标准的 TranslateAnimation 并通过覆盖 applyTransformation
方法来拦截动画的每一步。
看看这个 incomplete/untested 片段:
private class ObservableTranslateAnimation extends TranslateAnimation{
private float matrixValues[] = new float[9];
private float actualDx;
private float actualDy;
public ObservableTranslateAnimation(Context context, AttributeSet attrs) {
super(context, attrs);
}
// ... more constructors
@Override
protected void applyTransformation(float interpolatedTime, Transformation t) {
super.applyTransformation(interpolatedTime, t);
//After that super is called, the matrix gets updated!
//get the current matrix and extract what you need
t.getMatrix().getValues(matrixValues);
actualDx = matrixValues[Matrix.MTRANS_X];
actualDy = matrixValues[Matrix.MTRANS_Y];
/*
Notify someone here (a listener?), or just read the values of actualDx, actualDy from outside
You can also play around with the other Matrix values.
*/
}
}
这是一个基于 user3249477 和 Vikram 所说的完整示例:
final TextView positionTextView = (TextView)findViewById(R.id.positionTextView);
ImageView myimage = (ImageView)findViewById(R.id.imageView);
ObjectAnimator translateXAnimation= ObjectAnimator.ofFloat(myimage, "translationX", 0f, 100f);
ObjectAnimator translateYAnimation= ObjectAnimator.ofFloat(myimage, "translationY", 0f, 100f);
translateXAnimation.setRepeatCount(ValueAnimator.INFINITE);
translateYAnimation.setRepeatCount(ValueAnimator.INFINITE);
AnimatorSet set = new AnimatorSet();
set.setDuration(1000);
set.playTogether(translateXAnimation, translateYAnimation);
set.start();
translateXAnimation.addUpdateListener(new AnimatorUpdateListener() {
@Override
public void onAnimationUpdate(ValueAnimator animation) {
imageXPosition = (Float)animation.getAnimatedValue();
}
});
translateYAnimation.addUpdateListener(new AnimatorUpdateListener() {
@Override
public void onAnimationUpdate(ValueAnimator animation) {
imageYPosition = (Float)animation.getAnimatedValue();
String position = String.format("X:%d Y:%d", (int)imageXPosition, (int)imageYPosition);
positionTextView.setText(position);
}
});
我在执行翻译动画的 ImageView 中有一个子弹图像。
我需要显示实时坐标以实时显示它与目标的距离。
ImageView myimage = (ImageView)findViewById(R.id.myimage);
Animation animation = new TranslateAnimation(100, 200, 300, 400);
animation.setDuration(1000);
myimage.startAnimation(animation);
animation.setRepeatCount(Animation.INFINITE);
是否可以在执行 TranslateAnimation 时获取图像的实时 x 和 y 坐标?
如果无法使用 TranslateAnimation,是否有任何其他方法可以在运动时给出图像的实时坐标?
我试过了-
int x = myimage.getLeft();
int y = myimage.getTop();
和
int[] firstPosition = new int[2];
myimage.measure(View.MeasureSpec.EXACTLY, View.MeasureSpec.EXACTLY);
myimage.getLocationOnScreen(firstPosition);
int x = firstPosition[0];
int y = firstPosition[1];
但在这两种方式中,它都给出了 ImageView 的初始静态坐标。
您可以使用 ObjectAnimator
(API 11+):
ImageView iv = (ImageView)findViewById(R.id.markerRed);
// Create animators for x and y axes
ObjectAnimator oax = ObjectAnimator.ofFloat(iv, "translationX", 0f, 100f);
ObjectAnimator oay = ObjectAnimator.ofFloat(iv, "translationY", 0f, 100f);
oax.setRepeatCount(Animation.INFINITE);
oay.setRepeatCount(Animation.INFINITE);
// Combine Animators and start them together
AnimatorSet set = new AnimatorSet();
set.setDuration(1000);
set.playTogether(oax, oay);
set.start();
然后像这样获取动画值:
Log.e("TAG", "X: " + oax.getAnimatedValue() + " Y:" + oay.getAnimatedValue());
如果将这些值添加到初始 ImageView
的坐标中,您将获得当前位置。
我有这样的想法:您可以扩展标准的 TranslateAnimation 并通过覆盖 applyTransformation
方法来拦截动画的每一步。
看看这个 incomplete/untested 片段:
private class ObservableTranslateAnimation extends TranslateAnimation{
private float matrixValues[] = new float[9];
private float actualDx;
private float actualDy;
public ObservableTranslateAnimation(Context context, AttributeSet attrs) {
super(context, attrs);
}
// ... more constructors
@Override
protected void applyTransformation(float interpolatedTime, Transformation t) {
super.applyTransformation(interpolatedTime, t);
//After that super is called, the matrix gets updated!
//get the current matrix and extract what you need
t.getMatrix().getValues(matrixValues);
actualDx = matrixValues[Matrix.MTRANS_X];
actualDy = matrixValues[Matrix.MTRANS_Y];
/*
Notify someone here (a listener?), or just read the values of actualDx, actualDy from outside
You can also play around with the other Matrix values.
*/
}
}
这是一个基于 user3249477 和 Vikram 所说的完整示例:
final TextView positionTextView = (TextView)findViewById(R.id.positionTextView);
ImageView myimage = (ImageView)findViewById(R.id.imageView);
ObjectAnimator translateXAnimation= ObjectAnimator.ofFloat(myimage, "translationX", 0f, 100f);
ObjectAnimator translateYAnimation= ObjectAnimator.ofFloat(myimage, "translationY", 0f, 100f);
translateXAnimation.setRepeatCount(ValueAnimator.INFINITE);
translateYAnimation.setRepeatCount(ValueAnimator.INFINITE);
AnimatorSet set = new AnimatorSet();
set.setDuration(1000);
set.playTogether(translateXAnimation, translateYAnimation);
set.start();
translateXAnimation.addUpdateListener(new AnimatorUpdateListener() {
@Override
public void onAnimationUpdate(ValueAnimator animation) {
imageXPosition = (Float)animation.getAnimatedValue();
}
});
translateYAnimation.addUpdateListener(new AnimatorUpdateListener() {
@Override
public void onAnimationUpdate(ValueAnimator animation) {
imageYPosition = (Float)animation.getAnimatedValue();
String position = String.format("X:%d Y:%d", (int)imageXPosition, (int)imageYPosition);
positionTextView.setText(position);
}
});