如何避免使用覆盆子轮询?
How to avoid to use polling with raspberry?
我正在 Java 中用 Raspberry 做一个项目,我使用 Pi4j 库。
我不会使用轮询,所以例如我使用此代码:
public class ListenGpioExample {
public static void main(String args[]) throws InterruptedException {
System.out.println("<--Pi4J--> GPIO Listen Example ... started.");
// create gpio controller
final GpioController gpio = GpioFactory.getInstance();
// provision gpio pin #02 as an input pin with its internal pull down resistor enabled
final GpioPinDigitalInput myButton = gpio.provisionDigitalInputPin(RaspiPin.GPIO_02, PinPullResistance.PULL_DOWN);
// create and register gpio pin listener
myButton.addListener(new GpioPinListenerDigital() {
@Override
public void handleGpioPinDigitalStateChangeEvent(GpioPinDigitalStateChangeEvent event) {
// display pin state on console
System.out.println(" --> GPIO PIN STATE CHANGE: " + event.getPin() + " = " + event.getState());
}
});
System.out.println(" ... complete the GPIO #02 circuit and see the listener feedback here in the console.");
// keep program running until user aborts (CTRL-C)
for (;;) {
Thread.sleep(500);
}
// stop all GPIO activity/threads by shutting down the GPIO controller
// (this method will forcefully shutdown all GPIO monitoring threads and scheduled tasks)
// gpio.shutdown(); <--- implement this method call if you wish to terminate the Pi4J GPIO controller
}}
我的问题是:
事实上,无限循环仍然是一种轮询形式?
因为我不明白死循环到底有没有必要
不,这不是投票。此示例使用事件侦听器,一旦 GPIO Pin
中发生状态更改,该侦听器就会启动
正如您在 Pi4J library page 上看到的那样:
The listener implementation is based on GPIO hardware interrupts not
state polling.
for(;;)
旨在使程序保持活动状态,直到用户将其停止(您可以在评论中阅读)
我正在 Java 中用 Raspberry 做一个项目,我使用 Pi4j 库。 我不会使用轮询,所以例如我使用此代码:
public class ListenGpioExample {
public static void main(String args[]) throws InterruptedException {
System.out.println("<--Pi4J--> GPIO Listen Example ... started.");
// create gpio controller
final GpioController gpio = GpioFactory.getInstance();
// provision gpio pin #02 as an input pin with its internal pull down resistor enabled
final GpioPinDigitalInput myButton = gpio.provisionDigitalInputPin(RaspiPin.GPIO_02, PinPullResistance.PULL_DOWN);
// create and register gpio pin listener
myButton.addListener(new GpioPinListenerDigital() {
@Override
public void handleGpioPinDigitalStateChangeEvent(GpioPinDigitalStateChangeEvent event) {
// display pin state on console
System.out.println(" --> GPIO PIN STATE CHANGE: " + event.getPin() + " = " + event.getState());
}
});
System.out.println(" ... complete the GPIO #02 circuit and see the listener feedback here in the console.");
// keep program running until user aborts (CTRL-C)
for (;;) {
Thread.sleep(500);
}
// stop all GPIO activity/threads by shutting down the GPIO controller
// (this method will forcefully shutdown all GPIO monitoring threads and scheduled tasks)
// gpio.shutdown(); <--- implement this method call if you wish to terminate the Pi4J GPIO controller
}}
我的问题是: 事实上,无限循环仍然是一种轮询形式?
因为我不明白死循环到底有没有必要
不,这不是投票。此示例使用事件侦听器,一旦 GPIO Pin
中发生状态更改,该侦听器就会启动正如您在 Pi4J library page 上看到的那样:
The listener implementation is based on GPIO hardware interrupts not state polling.
for(;;)
旨在使程序保持活动状态,直到用户将其停止(您可以在评论中阅读)