试图在 coronasdk 上创建一个退出库存按钮

Question

我目前正在开发一款需要库存系统的游戏。我不知道如何为我创建的显示对象制作退出按钮。

这是我的代码：

local Choose_slot = display.newImage("Images/choose_slot.png")
 Choose_slot.x = centerX + 96
 Choose_slot.y = 45

function choose_slot:tap ( event )
  Inventory_Screen = display.newRect( centerX, centerY, 1500, 1500 )
  Inventory_Screen:setFillColor( 0.3, 0.3, 0.3 )
end

local Exit_Button = display.newImageRect( "Images/Exit_Image.png", 32, 32)
Exit_Button.x = centerX + 255
Exit_Button.y = centerY - 135

function Exit_Inventory:tap ( event )
    Inventory_Screen:remove()
    Exit_Button:remove()
end

Exit_Inventory:addEventListener( "tap", Exit_Button)

Choose_slot:addEventListener( "tap", choose_slot)

仅供参考，"Choose_slot" 是一张显示库存的图片。我想做到这一点，当 "Inventory_Screen" 出现时， "Exit_Inventory" 按钮会弹出，当你点击它时，它会从屏幕上删除 "Inventory_Screen" 和 "Exit_Button" 并且返回到点击清单之前所在的屏幕！

Answer 1

在显示组中这样做会更容易，因此您可以使用行命令删除组中的所有对象。

将按钮和函数添加到您的代码中，如下所示：

local function exitFunc(event)
    Choose_slot:removeSelf() -- add whatever you want to remove
    exitB:removeSelf() -- can use object.isVisible = false if you wanted but they maybe touchable still
end 

exitB= widget.newButton
{
  width=135,
  height=60,
  defaultFile = "whatever.png",
  overFile = "whateverOver.png",
  label = "Exit",
  onPress = exitFunc,
}

Answer 2

图片是我把你的代码改成这样后剩下的：

function Choose_slot:tap ( event )  

        Inventory_Screen = display.newRect( centerX, centerY, 1500, 1500 )
        Inventory_Screen:setFillColor( 0.3, 0.3, 0.3 )

        local function handleExitBEvent( event )   -- ERROR IS BELOW! 

    if ( "ended" == event.phase ) then
        print( "Button was pressed and released" )
        print( "Removing Inventory!" )
        Choose_slot:removeSelf() -- This is not removing -- 
        ExitB:removeSelf()
        Inventory_Screen:removeSelf()
        Inventory_Slot1:removeSelf()
    end
end

试图在 coronasdk 上创建一个退出库存按钮

Trying to make an exit inventory button on coronasdk

lua

inventory

coronasdk