如何在 Kotlin 中创建没有访问器的 属性？
How to create a property without accessors in Kotlin?
我正在使用来自 Java 代码的 Kotlin class。我的 Kotlin class 看起来像：
class Something {
var a = 0
}
我希望能够从 Java 代码访问 a，例如
s = new Something();
s.a = 5;
然而，我只有s.getA()和s.setA(5)。有什么方法可以让 属性 直接从 Java 设置和获取吗？显然在这种情况下我们不能自定义 getter 和 setter。
您可以使用 @JvmField annotation 注释 属性 以将其公开为 Java 字段。
If you need to expose a Kotlin property as a field in Java, you need to annotate it with the @JvmField annotation. The field will have the same visibility as the underlying property. You can annotate a property with @JvmField if it has a backing field, is not private, does not have open, override or const modifiers, and is not a delegated property.
我正在使用来自 Java 代码的 Kotlin class。我的 Kotlin class 看起来像：
class Something {
var a = 0
}
我希望能够从 Java 代码访问 a，例如
s = new Something();
s.a = 5;
然而，我只有s.getA()和s.setA(5)。有什么方法可以让 属性 直接从 Java 设置和获取吗？显然在这种情况下我们不能自定义 getter 和 setter。
您可以使用 @JvmField annotation 注释 属性 以将其公开为 Java 字段。
If you need to expose a Kotlin property as a field in Java, you need to annotate it with the @JvmField annotation. The field will have the same visibility as the underlying property. You can annotate a property with @JvmField if it has a backing field, is not private, does not have open, override or const modifiers, and is not a delegated property.