想要索引表视图并引用回源数组

Question

在 iOS/Swift 中，我根据客户端 class 中的 clientName 属性创建了一个索引 "client" UITableView。我创建了一本以 A 到 Z 为部分的字典。索引表视图效果很好。但是，我试图找出一种方法来确定它在原始源数组中的哪一行，当用户选择一行时。我正在考虑构建某种类型的交叉引用数组，除了字典最终排序以匹配部分，所以我不知道哪个 section/row 组合匹配哪个原始数组条目。是否有处理此问题的通用方法？

试图澄清...

class Client {
    var clientId             : Int!
    var firstName            : String!
    var lastName             : String!
    var email                : String!
    var phone                : String!
    ...

    init() {

    }
}

var clients: [Client] = []

// clients array loaded from web service
...

// Create dictionary to be source for indexed tableview
func createClientDict() {
    clientDict          = [String: [String]]()
    clientSectionTitles = [String]()

    var clientNames:[String] = []
    for i in 0..<clients.count {
        let client = clients[i]

        let clientName = "\(client.lastName), \(client.firstName)"
        clientNames.append(clientName)
    }

    for name in clientNames {
        var client: Client  = Client()

        // Get the first letter of the name and build the dictionary
        let clientKey = name.substringToIndex(name.startIndex.advancedBy(1))
        if var clientValues = clientDict[clientKey] {
            clientValues.append(name)
            clientDict[clientKey] = clientValues
        } else {
            clientDict[clientKey] = [name]
        }
    }

    // Get the section titles from the dictionary's keys and sort them in ascending order
    clientSectionTitles = [String](clientDict.keys)
    clientSectionTitles = clientSectionTitles.sort { [=10=] <  }
}

现在，当用户点击表视图中的一行时，我可以获得部分和行 (indexPath)。但是，假设可能有重复的名称，我如何确定 clients 数组中的哪一行是匹配的？有什么方法可以动态创建映射到源数组中行的索引 section/row 的交叉引用吗？我打算在构建字典时尝试这样做，除了字典在之后排序，所以没有任何匹配。也许我应该以某种方式包括源行号 in/with 字典??

这是表格视图代码：

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCellWithIdentifier("Cell") as! ClientCell

    let clientKey = clientSectionTitles[indexPath.section]
    if let clientValues = clientDict[clientKey] {
        cell.clientName.text = clientValues[indexPath.row]
    }

    return cell
}

func numberOfSectionsInTableView(tableView: UITableView) -> Int {
    return clientSectionTitles.count
}

func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    let clientKey = clientSectionTitles[section]
    if let clientValues = clientDict[clientKey] {
        return clientValues.count
    }

    return 0
}

func tableView(tableView: UITableView, titleForHeaderInSection section: Int) -> String? {
    return clientSectionTitles[section]
}

func sectionIndexTitlesForTableView(tableView: UITableView) -> [String]? {
    return clientIndexTitles
}

func tableView(tableView: UITableView, sectionForSectionIndexTitle title: String, atIndex index: Int) -> Int {

    guard let index = clientSectionTitles.indexOf(title) else {
        return -1
    }

    return index
}

func tableView(tableView: UITableView, heightForHeaderInSection section: Int) -> CGFloat {
    return 20
}

func tableView(tableView: UITableView, willDisplayHeaderView view: UIView, forSection section: Int) {
    let headerView   = view as! UITableViewHeaderFooterView

    headerView.contentView.backgroundColor = UIColor ( red: 0.0, green: 0.3294, blue: 0.6392, alpha: 1.0 )
    headerView.textLabel?.textColor = UIColor.greenColor()
    headerView.textLabel?.font = UIFont(name: "Noteworthy-bold", size: 15.0)
}

func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
    selectedIndex = indexPath

    // In the following prepare for segue, I need to somehow use the selected indexpath to find the correct entry
    // in the clients array and pass it along.

    performSegueWithIdentifier("clientDetailSegue", sender: self)
}

Answer 1

我明白了。我没有意识到（直到我最近尝试过）您可以在字典中嵌套任何 class 的数组。当我更改我的字典以在其中嵌套我的客户数组时，一切都解决了。我改变了我的功能，如下所示。

func createClientDict() {
    // Declared for view controller. Re-initialized here.
    clientDict          = [String: [Client]]()
    clientSectionTitles = [String]()

    clients.sortInPlace ({ [=10=].lastName < .lastName })

    for c in clients {
        let clientName = "\(c.lastName), \(c.firstName)"

        // Get the first letter of the name and build the dictionary
        let clientKey = clientName!.substringToIndex(clientName!.startIndex.advancedBy(1))
        if var clientValues = clientDict[clientKey] {
            clientValues.append(c)
            clientDict[clientKey] = clientValues
        } else {
            clientDict[clientKey] = [c]
        }
    }

    // Get the section titles from the dictionary's keys and sort them in ascending order
    clientSectionTitles = [String](clientDict.keys)
    clientSectionTitles = clientSectionTitles.sort { [=10=] <  }
}

然而，这一行是解决问题的关键：

let clientDict = [String: [Client]]()

想要索引表视图并引用回源数组

Want indexed tableview with reference back to source array

arrays

indexed

uitableview

ios

swift