Groovy 中 SOAP 响应的正则表达式

Question

我在 matching/extracting UserToken 的值（即 "bb14MY"）上使用 Groovy 中的正则表达式做错了吗？

@Grab(group='com.github.groovy-wslite', module='groovy-wslite', version='1.1.0')
import wslite.soap.*
import wslite.http.auth.*
import java.util.regex.*      
import groovy.xml.*
import groovy.util.*
import java.lang.*

...
...
...

def soapResponse = connection.content.text;

String str = println "$soapResponse";

Pattern pattern = Pattern.compile("^\s*UserToken=&quot;(.*?)&quot;", Pattern.DOTALL);
Matcher matcher = pattern.matcher(str);
if (matcher.find()) {
          println(matcher.group(1));
}

$soapResponse 的输出如下所示。

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/"
    ContactAddress_Key=&quot;&quot; ImageFile=&quot;&quot; LocaleCode=&quot;en_US_EST&quot;
    UserToken=&quot;bb14MY&quot;
</loginReturn></p561:loginResponse></soapenv:Body></soapenv:Envelope>

Answer 1

使用以下模式获取您的用户令牌。我正在使用捕获组来获取它。

UserToken=.+;(\w+).+;

演示 here.

不用说，您的正则表达式对象必须处理多行。

Answer 2

这里使用 ^ 是错误的，因为 DOTALL 只是使换行符与常规字符匹配。我想你想要 MULTILINE，但它也可以在没有它的情况下工作。例如

def soap="""\
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/"
    ContactAddress_Key=&quot;&quot; ImageFile=&quot;&quot; LocaleCode=&quot;en_US_EST&quot;
    UserToken=&quot;bb14MY&quot;
</loginReturn></p561:loginResponse></soapenv:Body></soapenv:Envelope>"""
def pattern
def matcher

// stick with `Pattern.DOTALL` (`(?s)`), but get rid of handling for the start of the line:
pattern = /(?s)UserToken=&quot;(.*?)&quot;/
matcher = soap =~ pattern
assert matcher
assert matcher.group(1)=="bb14MY"

// or use `Pattern.MULTILINE` (`(?m)`) with your `^\s*`:
pattern = /(?m)^\s*UserToken=&quot;(.*?)&quot;/
matcher = soap =~ pattern
assert matcher
assert matcher.group(1)=="bb14MY"

Answer 3

def soapResponse = connection.content.text;

Pattern pattern = Pattern.compile(/(?s)UserToken=&quot;(.*?)&quot;/, Pattern.DOTALL);
Matcher matcher = pattern.matcher(soapResponse);
if (matcher.find()) {
          println(matcher.group(1));
}

这就是我解决问题的方法。

Groovy 中 SOAP 响应的正则表达式

Regular Expression for SOAP Response in Groovy

regex

groovy

soap

演示 here.