在函数中返回带有参数的两个值

Returning two values with arguments in the function

### The formulas for the area and perimeter.
def area(a, b, c):
    # calculate the sides
    s = (a + b + c) / 2
    # calculate the area
    areaValue = (s*(s-a)*(s-b)*(s-c)) ** 0.5
    # returning the output

    # Calculate the perimeter
    perimValue = a + b + c
    # returning the output.

    return areaValue,perimValue

areaV, perimeterV = area(a, b, c)

### The main function for the prompts and output.
def main():
    # The prompts. 
    a = int(input('Enter first side: '))
    b = int(input('Enter second side: '))
    c = int(input('Enter third side: '))

    # The output statements. 
    print ("The area is:", format(areaV(a, b, c),',.1f'),"and the perimeter is:", format(perimeterV(a, b, c), ',.1f'))

### Calling msin
main()

我正在尝试 return area 函数的两个值,但是当我尝试这样做时,我收到一条错误消息,指出当我尝试调用该函数时 a b 和 c 未定义。

注意:我的老师告诉我们,面积和周长只需要在一个函数中计算。他们不能分开。

有什么方法可以阻止该错误的发生?

你需要把

areaV, perimeterV = area(a, b, c) 

在用户输入后的主体中。因为a,b,c定义在main函数

的范围内

应该是这样的:

def main():
    # The prompts. 
    a = int(input('Enter first side: '))
    b = int(input('Enter second side: '))
    c = int(input('Enter third side: '))
    areaV, perimeterV = area(a, b, c)
    # The output statements. 
    print ("The area is:", format(areaV,',.1f'),"and the perimeter is:", format(perimeterV, ',.1f'))

在为 a, b, c 赋值之前不能调用 areaV, perimeterV = area(a, b, c)