从 postgres sql 中的同一查询中提取水平列中的年份列和显示年份列
Extract out Year column and Display Year column in Horizontal column from the same query in postgres sql
我有这个查询 returns 对我来说是正确的结果。
SELECT distinct(companies.name),
date_part('year', scopes.time_stamp) as fy,
count(def.dp_code)as answ_count
FROM companies companies,
scopes scopes,
values dp,
definition def,
content cd
where scopes.company_id = companies.company_id
and scopes.scope_id=dp.scope_id
and dp.content_id=cd.definition_id
and def.definition_id=cd.definition_id
group by companies.name, date_part('year',scopes.time_stamp)
ORDER BY companies.name
下面是上面查询的结果。
name fy count
3M Co 2002 200
3M Co 2003 100
3M Co 2004 150
3M Co 2005 160
3M Co 2006 169
AB SKF 2002 212
AB SKF 2003 214
AB SKF 2004 215
AB SKF 2005 237
AB SKF 2006 456
3i Group plc 2002 546
3i Group plc 2003 214
3i Group plc 2004 215
3i Group plc 2005 237
3i Group plc 2006 456
我需要像这样水平显示结果:
name 2002 2003 2004 2005 2006
3M Co 200 100 150 160 169
AB SKF
3i Group plc 546 214 215 237 456
已修改查询,但我没有得到正确的 count.I 不知道如何计算 ans_count.Please 帮助我。
SELECT
distinct(companies.name),
count(CASE WHEN date_part('year', scopes.time_stamp) = 2002 THEN answ_count end) AS Year1,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2003 THEN answ_count end) AS Year2,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2004 THEN answ_count end) AS Year3,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2005 THEN answ_count end) AS Year4,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2006 THEN answ_count end) AS Year5,
count(CASE WHEN date_part('year',scopes.time_stamp) = 2007 THEN answ_count end) AS Year6,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2008 THEN answ_count end) AS Year7,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2009 THEN answ_count end) AS Year8,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2010 THEN answ_count end) AS Year9,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2011 THEN answ_count end) AS Year10,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2012 THEN answ_count end) AS Year11,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2013 THEN answ_count end) AS Year12,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2014 THEN answ_count end) AS Year13,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2015 THEN answ_count end) AS Year14,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2016 THEN answ_count end) AS Year16
FROM
companies companies,value_scopes value_scopes,dp_values dp,dp_definition def,dp_content_definition cd
where
value_scopes.company_id = companies.company_id
and value_scopes.value_scope_id=dp.value_scope_id
and dp.dp_content_definition_id=cd.dp_content_definition_id
and def.dp_definition_id=cd.dp_definition_id
and value_scopes.is_partial='f'
group by companies.name
ORDER BY companies.name;
现代的、明确的 JOIN
派生的 table:
select name,
count(case when year = 2002 then 1 end) as Year2002,
count(case when year = 2003 then 1 end) as Year2003,
...
count(case when year = 2016 then 1 end) as Year2016
FROM
(
SELECT companies.name,
date_part('year', scopes.time_stamp) AS Year
FROM companies companies
JOIN value_scopes value_scopes ON value_scopes.company_id = companies.company_id
JOIN dp_values dp ON value_scopes.value_scope_id = dp.value_scope_id
JOIN dp_content_definition cd ON dp.dp_content_definition_id = cd.dp_content_definition_id
JOIN dp_definition def ON def.dp_definition_id=cd.dp_definition_id
WHERE value_scopes.is_partial = 'f'
) dt
group by name
ORDER BY name
我有这个查询 returns 对我来说是正确的结果。
SELECT distinct(companies.name),
date_part('year', scopes.time_stamp) as fy,
count(def.dp_code)as answ_count
FROM companies companies,
scopes scopes,
values dp,
definition def,
content cd
where scopes.company_id = companies.company_id
and scopes.scope_id=dp.scope_id
and dp.content_id=cd.definition_id
and def.definition_id=cd.definition_id
group by companies.name, date_part('year',scopes.time_stamp)
ORDER BY companies.name
下面是上面查询的结果。
name fy count
3M Co 2002 200
3M Co 2003 100
3M Co 2004 150
3M Co 2005 160
3M Co 2006 169
AB SKF 2002 212
AB SKF 2003 214
AB SKF 2004 215
AB SKF 2005 237
AB SKF 2006 456
3i Group plc 2002 546
3i Group plc 2003 214
3i Group plc 2004 215
3i Group plc 2005 237
3i Group plc 2006 456
我需要像这样水平显示结果:
name 2002 2003 2004 2005 2006
3M Co 200 100 150 160 169
AB SKF
3i Group plc 546 214 215 237 456
已修改查询,但我没有得到正确的 count.I 不知道如何计算 ans_count.Please 帮助我。
SELECT
distinct(companies.name),
count(CASE WHEN date_part('year', scopes.time_stamp) = 2002 THEN answ_count end) AS Year1,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2003 THEN answ_count end) AS Year2,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2004 THEN answ_count end) AS Year3,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2005 THEN answ_count end) AS Year4,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2006 THEN answ_count end) AS Year5,
count(CASE WHEN date_part('year',scopes.time_stamp) = 2007 THEN answ_count end) AS Year6,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2008 THEN answ_count end) AS Year7,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2009 THEN answ_count end) AS Year8,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2010 THEN answ_count end) AS Year9,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2011 THEN answ_count end) AS Year10,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2012 THEN answ_count end) AS Year11,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2013 THEN answ_count end) AS Year12,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2014 THEN answ_count end) AS Year13,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2015 THEN answ_count end) AS Year14,
count(CASE WHEN date_part('year', scopes.time_stamp) = 2016 THEN answ_count end) AS Year16
FROM
companies companies,value_scopes value_scopes,dp_values dp,dp_definition def,dp_content_definition cd
where
value_scopes.company_id = companies.company_id
and value_scopes.value_scope_id=dp.value_scope_id
and dp.dp_content_definition_id=cd.dp_content_definition_id
and def.dp_definition_id=cd.dp_definition_id
and value_scopes.is_partial='f'
group by companies.name
ORDER BY companies.name;
现代的、明确的 JOIN
派生的 table:
select name,
count(case when year = 2002 then 1 end) as Year2002,
count(case when year = 2003 then 1 end) as Year2003,
...
count(case when year = 2016 then 1 end) as Year2016
FROM
(
SELECT companies.name,
date_part('year', scopes.time_stamp) AS Year
FROM companies companies
JOIN value_scopes value_scopes ON value_scopes.company_id = companies.company_id
JOIN dp_values dp ON value_scopes.value_scope_id = dp.value_scope_id
JOIN dp_content_definition cd ON dp.dp_content_definition_id = cd.dp_content_definition_id
JOIN dp_definition def ON def.dp_definition_id=cd.dp_definition_id
WHERE value_scopes.is_partial = 'f'
) dt
group by name
ORDER BY name