运行全部成功或全部失败的多个查询

Question

我需要将 2 行更新为 2 个不同的 table，然后将新行插入到另一个不同的 table 中，必须这样做，这样它们要么全部成功，要么全部失败。（我认为这个词是原子的？）。我进行了一些搜索，但似乎只能找到与对一个 table.

进行多次插入或更新相关的问题

以下是我需要运行:

的 3 个查询

UPDATE submission SET status='a' WHERE idgreg = 119 AND status='p' AND userid = 126;

UPDATE greg SET iscomplete=1 WHERE idgreg = 119;

INSERT INTO completion (idperson, idgreg, datecompleted, idsubmission, mediaid, description, 
privatestatus, contenttype, totalamount)  
SELECT s.idperson, s.idgreg, s.datesubmitted, s.idsubmission, COALESCE(s.youtubeid, s.contentid) AS mediaidid, g.description, g.privatestatus, 
g.contenttype, COALESCE(SUM(amount),0) AS totalamount 
FROM submission s 
INNER JOIN greg g on s.idgreg = g.idgreg 
INNER JOIN contribution c on s.idgreg = c.idgreg 
WHERE s.idsubmission = 36 AND c.ispaid = 1;

Answer 1

您应该将查询包装在 MySQL 事务中，以确保它们以原子方式执行。但首先，声明错误处理程序，它将 ROLLBACK 在发生错误时进行所有更改：

CREATE PROCEDURE runYourQueries()

BEGIN

DECLARE EXIT HANDLER FOR SQLEXCEPTION ROLLBACK;
DECLARE EXIT HANDLER FOR SQLWARNING ROLLBACK;

START TRANSACTION;

UPDATE submission SET status='a' WHERE idgreg = 119 AND status='p' AND userid = 126;

UPDATE greg SET iscomplete=1 WHERE idgreg = 119;

INSERT INTO completion (idperson, idgreg, datecompleted, idsubmission, mediaid, description,
    privatestatus, contenttype, totalamount)  
SELECT s.idperson, s.idgreg, s.datesubmitted, s.idsubmission,
    COALESCE(s.youtubeid, s.contentid) AS mediaidid, g.description, g.privatestatus,
    g.contenttype, COALESCE(SUM(amount),0) AS totalamount 
FROM submission s 
INNER JOIN greg g on s.idgreg = g.idgreg 
INNER JOIN contribution c on s.idgreg = c.idgreg 
WHERE s.idsubmission = 36 AND c.ispaid = 1;

COMMIT;

END

运行全部成功或全部失败的多个查询

Run multiple queries where all succeed or all fail

mysql

atomic

sql-update

sql-insert

运行 全部成功或全部失败的多个查询

Run multiple queries where all succeed or all fail

mysql

atomic

sql-update

sql-insert

运行全部成功或全部失败的多个查询