'++' 已弃用：它将在 Swift 3 中删除
'++' is deprecated: it will be removed in Swift 3
更新到 Xcode 7.3 后，我的项目中出现了一堆警告。
'++' is deprecated: it will be removed in Swift 3
有解决此警告的想法吗？ ++ 和 -- 将来会被弃用的任何原因？
从 Swift 2.2 开始，您应该改用 += 1 或 -= 1。
并且在查看了Swift的演变后，有一些删除这些运算符的原因：
These operators increase the burden to learn Swift as a first programming language - or any other case where you don't already know these operators from a different language.
Their expressive advantage is minimal - x++ is not much shorter than x += 1.
Swift already deviates from C in that the =, += and other assignment-like operations returns Void (for a number of reasons). These operators are inconsistent with that model.
Swift has powerful features that eliminate many of the common reasons you'd use ++i in a C-style for loop in other languages, so these are relatively infrequently used in well-written Swift code. These features include the for-in loop, ranges, enumerate, map, etc.
Code that actually uses the result value of these operators is often confusing and subtle to a reader/maintainer of code. They encourage "overly tricky" code which may be cute, but difficult to understand.
While Swift has well defined order of evaluation, any code that depended on it (like foo(++a, a++)) would be undesirable even if it was well-defined.
These operators are applicable to relatively few types: integer and floating point scalars, and iterator-like concepts. They do not apply to complex numbers, matrices, etc.
Finally, these fail the metric of "if we didn't already have these, would we add them to Swift 3?"
请查看 Swift evolution 了解更多信息。
更新到 Xcode 7.3 后，我的项目中出现了一堆警告。
'++' is deprecated: it will be removed in Swift 3
有解决此警告的想法吗？ ++ 和 -- 将来会被弃用的任何原因？
从 Swift 2.2 开始，您应该改用 += 1 或 -= 1。
并且在查看了Swift的演变后，有一些删除这些运算符的原因：
These operators increase the burden to learn Swift as a first programming language - or any other case where you don't already know these operators from a different language.
Their expressive advantage is minimal - x++ is not much shorter than x += 1.
Swift already deviates from C in that the =, += and other assignment-like operations returns Void (for a number of reasons). These operators are inconsistent with that model.
Swift has powerful features that eliminate many of the common reasons you'd use ++i in a C-style for loop in other languages, so these are relatively infrequently used in well-written Swift code. These features include the for-in loop, ranges, enumerate, map, etc.
Code that actually uses the result value of these operators is often confusing and subtle to a reader/maintainer of code. They encourage "overly tricky" code which may be cute, but difficult to understand.
While Swift has well defined order of evaluation, any code that depended on it (like foo(++a, a++)) would be undesirable even if it was well-defined.
These operators are applicable to relatively few types: integer and floating point scalars, and iterator-like concepts. They do not apply to complex numbers, matrices, etc.
Finally, these fail the metric of "if we didn't already have these, would we add them to Swift 3?"
请查看 Swift evolution 了解更多信息。