#warning:C 风格的 for 语句已弃用,将在 Swift 的未来版本中删除
#warning: C-style for statement is deprecated and will be removed in a future version of Swift
我刚刚下载了一个新的 Xcode (7.3) 和 swift 2.2.
它有一个警告:
C-style for statement is deprecated and will be removed in a future version of Swift.
如何修复此警告?
删除 for init; comparison; increment {}
并轻松删除 ++
和 --
。并使用 Swift 漂亮的 for-in 循环
// WARNING: C-style for statement is deprecated and will be removed in a future version of Swift
for var i = 1; i <= 10; i += 1 {
print("I'm number \(i)")
}
Swift 2.2:
// new swift style works well
for i in 1...10 {
print("I'm number \(i)")
}
用于递减索引
for index in 10.stride(to: 0, by: -1) {
print(index)
}
或者您可以像
一样使用 reverse()
for index in (0 ..< 10).reverse() { ... }
对于浮点型 (there is no need to define any types to index)
for index in 0.stride(to: 0.6, by: 0.1) {
print(index) //0.0 ,0.1, 0.2,0.3,0.4,0.5
}
Swift 3.0:
从Swift3.0
开始,Strideable上的stride(to:by:)
方法已经替换为一个自由函数,stride(from:to:by:)
for i in stride(from: 0, to: 10, by: 1){
print(i)
}
对于Swift 3.0
中的递减索引,可以使用reversed()
for i in (0 ..< 5).reversed() {
print(i) // 4,3,2,1,0
}
除了for each
和stride()
,您可以使用While Loops
var i = 0
while i < 10 {
i += 1
print(i)
}
Repeat-While Loop:
var a = 0
repeat {
a += 1
print(a)
} while a < 10
中的控制流
我在这段代码中遇到了同样的错误:
for (var i = 1; i != video.getAll().count; i++) {
print("show number \(i)")
}
当你尝试用 Xcode 修复它时,你没有运气......所以你需要使用新的 swift 样式(for in loop):
for i in 1...video.getAll().count {
print("show number \(i)")
}
Blockquote
改用这个
if(myarr.count)
{
for i in 1...myarr?.count {
print(" number is \(i)")
}
}
对于这种"for"循环:
for var i = 10; i >= 0; --i {
print(i)
}
你可以这样写:
for i in (0...10).reverse() {
print(i)
}
我刚刚下载了一个新的 Xcode (7.3) 和 swift 2.2.
它有一个警告:
C-style for statement is deprecated and will be removed in a future version of Swift.
如何修复此警告?
删除 for init; comparison; increment {}
并轻松删除 ++
和 --
。并使用 Swift 漂亮的 for-in 循环
// WARNING: C-style for statement is deprecated and will be removed in a future version of Swift
for var i = 1; i <= 10; i += 1 {
print("I'm number \(i)")
}
Swift 2.2:
// new swift style works well
for i in 1...10 {
print("I'm number \(i)")
}
用于递减索引
for index in 10.stride(to: 0, by: -1) {
print(index)
}
或者您可以像
一样使用reverse()
for index in (0 ..< 10).reverse() { ... }
对于浮点型 (there is no need to define any types to index)
for index in 0.stride(to: 0.6, by: 0.1) {
print(index) //0.0 ,0.1, 0.2,0.3,0.4,0.5
}
Swift 3.0:
从Swift3.0
开始,Strideable上的stride(to:by:)
方法已经替换为一个自由函数,stride(from:to:by:)
for i in stride(from: 0, to: 10, by: 1){
print(i)
}
对于Swift 3.0
中的递减索引,可以使用reversed()
for i in (0 ..< 5).reversed() {
print(i) // 4,3,2,1,0
}
除了for each
和stride()
,您可以使用While Loops
var i = 0
while i < 10 {
i += 1
print(i)
}
Repeat-While Loop:
var a = 0
repeat {
a += 1
print(a)
} while a < 10
中的控制流
我在这段代码中遇到了同样的错误:
for (var i = 1; i != video.getAll().count; i++) {
print("show number \(i)")
}
当你尝试用 Xcode 修复它时,你没有运气......所以你需要使用新的 swift 样式(for in loop):
for i in 1...video.getAll().count {
print("show number \(i)")
}
Blockquote
改用这个
if(myarr.count)
{
for i in 1...myarr?.count {
print(" number is \(i)")
}
}
对于这种"for"循环:
for var i = 10; i >= 0; --i {
print(i)
}
你可以这样写:
for i in (0...10).reverse() {
print(i)
}