WCF：我必须为哪种属性类型调用 SetLink

Question

我想做一个非常通用的 class 来将对象保存到 WCF 服务。我得到任何类型的对象并通过反射分析对象属性。将对象保存到服务上下文中时，我需要知道是否必须为属性调用 DataServiceContext 的 SetLink(...) 方法。

因此我需要一种方法来确定是否必须调用 SetLink(...)。我已经尝试过自己做:

private bool IsLinkedProperty(PropertyInfo propertyInfo)
{
    return (propertyInfo != null) && propertyInfo.PropertyType.IsClass;
}

但是这个函数不适用于字符串属性，也许对其他属性也不起作用。有人有合适的功能吗？

Answer 1

我最终得到了以下解决方案。我在 qestion of Nathan Ridley:

中找到了提示

/// <summary>
/// Helper class for analyzing a type.
/// </summary>
public static class TypeAnalyzer
{
    /// <summary>
    /// Calculates if the given type is a "simple" type.
    /// </summary>
    /// <param name="type">Type to be checked for simplicity.</param>
    /// <returns>True, if the type is "simple";false otherwise.</returns>
    /// <remarks>
    ///   The following types are assumed to be simple:
    ///   <list type="*">
    ///     <item>string</item>
    ///     <item>int</item>
    ///     <item>decimal</item>
    ///     <item>float</item>
    ///     <item><see cref="StringComparison"/> (enum type)</item>
    ///     <item>int? (nullable simple types)</item> 
    ///   </list>
    ///   The following types are not simple:
    ///   <list type="*">
    ///     <item>Point (struct)</item>
    ///     <item>Point? (nullable struct)</item>
    ///     <item>StringBuilder (class)</item>
    ///   </list>
    /// </remarks>
    public static bool IsSimple(this Type type)
    {
        if (IsNullableType(type))
            return IsNestedTypeSimple(type);

        return type.IsPrimitive
          || type.IsEnum
          || type.Equals(typeof(string))
          || type.Equals(typeof(decimal))
          || type.Equals(typeof(DateTime))
          || type.Equals(typeof(Guid));
    }

    private static bool IsNestedTypeSimple(Type type)
    {
        var nestedType = Nullable.GetUnderlyingType(type);
        return IsSimple(nestedType);
    }

    private static bool IsNullableType(Type type)
    {
        return Nullable.GetUnderlyingType(type) != null;
    }
}

用 NUnit 编写的测试用例是：

[TestFixture]
public class TypeAnalyzerTests
{
    [TestCase(typeof(string), true)]
    [TestCase(typeof(int), true)]
    [TestCase(typeof(decimal), true)]
    [TestCase(typeof(float), true)]
    [TestCase(typeof(StringComparison), true)]
    [TestCase(typeof(int?), true)]
    [TestCase(typeof(decimal?), true)]
    [TestCase(typeof(StringComparison?), true)]
    [TestCase(typeof(object), false)]
    [TestCase(typeof(Point), false)]
    [TestCase(typeof(Point?), false)]
    [TestCase(typeof(StringBuilder), false)]
    [TestCase(typeof(DateTime), true)]
    [TestCase(typeof(Guid), true)]
    [TestCase(typeof(Guid?), true)]
    public void IsSimple_WhenCalledForType_ReturnsExpectedResult(Type type, bool expectedResult)
    {
        var isSimple = TypeAnalyzer.IsSimple(type);

        Assert.That(isSimple, Is.EqualTo(expectedResult));
    }
}

最后我把问题中提到的方法改成了：

private bool IsLinkedProperty()
{ 
    return (_propertyInfo != null) && !_propertyInfo.PropertyType.IsSimple();
}

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