Python 中的 Stripe 未抛出充电错误

Question

我正在使用 Python 中的条带库进行信用卡收费。我将 customerID 用于收费目的而不是令牌，因为我想重新使用该卡而不需要每次都询问它。成功过程工作得很好，但是，如果我创建错误条件，则永远不会抛出 "except"。我正在使用无效的客户 ID 测试失败状态。

服务器日志显示以下错误："InvalidRequestError: Request req_8949iJfEmeX39p: No such customer: 22" 但同样未在 try/except 中处理。

class ChargeCustomerCard(webapp2.RequestHandler):
def post(self):
    stripe.api_key = stripeApiKey
    customerID = self.request.get("cust")
    amount = self.request.get("amt")

    try:
        charge = stripe.Charge.create(amount=int(amount),currency="usd",customer=customerID,description=customerID)
    except stripe.error.CardError, e:
        output = {"result":e}
    else:
        output = {"result":"1"}

    self.response.out.write(json.dumps(output))

Answer 1

根据 https://stripe.com/docs/api?lang=python#errors，您没有处理条带库提供的所有可能 errors/exceptions。处理财务数据理应更加谨慎，因此您确实至少需要做以下事情：

class ChargeCustomerCard(webapp2.RequestHandler):
    def post(self):
        stripe.api_key = stripeApiKey
        customerID = self.request.get("cust")
        amount = self.request.get("amt")

        try:
            charge = stripe.Charge.create(amount=int(amount),currency="usd",customer=customerID,description=customerID)
        except stripe.error.CardError, e:
            output = {"result":e}
        except Exception as e:
            # handle this e, which could be stripe related, or more generic
            pass
        else:
            output = {"result":"1"}

        self.response.out.write(json.dumps(output))

或者甚至基于官方文档，更全面的文档如：

try:
    # Use Stripe's library to make requests...
    pass
except stripe.error.CardError, e:
    # Since it's a decline, stripe.error.CardError will be caught
    body = e.json_body
    err  = body['error']

    print "Status is: %s" % e.http_status
    print "Type is: %s" % err['type']
    print "Code is: %s" % err['code']
    # param is '' in this case
    print "Param is: %s" % err['param']
    print "Message is: %s" % err['message']
except stripe.error.RateLimitError, e:
    # Too many requests made to the API too quickly
    pass
except stripe.error.InvalidRequestError, e:
    # Invalid parameters were supplied to Stripe's API
    pass
except stripe.error.AuthenticationError, e:
    # Authentication with Stripe's API failed
    # (maybe you changed API keys recently)
    pass
except stripe.error.APIConnectionError, e:
    # Network communication with Stripe failed
    pass
except stripe.error.StripeError, e:
    # Display a very generic error to the user, and maybe send
    # yourself an email
    pass
except Exception, e:
    # Something else happened, completely unrelated to Stripe
    pass

Answer 2

我认为官方文档可以提供更完整的样板文件。这就是我最终得到的：

except stripe.error.RateLimitError, e:
    # Too many requests made to the API too quickly
    err = e.json_body['error']
    lg.error("Stripe RateLimitError: %s" % (err))
    ...
except stripe.error.InvalidRequestError, e:
    # Invalid parameters were supplied to Stripe's API
    err = e.json_body['error']
    lg.error("Stripe InvalidRequestError: %s" % (err))
    ...

这让您更清楚如何处理 e 来记录一些有用的错误。

Python 中的 Stripe 未抛出充电错误

Stripe not Throwing Charging Error in Python

python

stripe-payments