为什么我的程序 link pam_* 不能调用

Question

我正在尝试编译和构建以下非常简单直接的 C 程序：

#include <security/pam_appl.h>
#include <security/pam_misc.h>
#include <stdio.h>
#include <string.h>

// Define custom PAM conversation function
int custom_conversation(int num_msg, const struct pam_message** msg, struct pam_response** resp, void* appdata_ptr)
{
    // Provide password for the PAM conversation response that was passed into appdata_ptr
    struct pam_response* reply = (struct pam_response* )malloc(sizeof(struct pam_response));
    reply[0].resp = (char*)appdata_ptr;
    reply[0].resp_retcode = 0;

    *resp = reply;

    return PAM_SUCCESS;
}

int main (int argc, char* argv[]) 
{
    if (argc > 2)
    {
        // Set up a custom PAM conversation passing in authentication password
        char* password = (char*)malloc(strlen(argv[2]) + 1);
        strcpy(password, argv[2]);        
        struct pam_conv pamc = { custom_conversation, password };
        pam_handle_t* pamh; 
        int retval;

        // Start PAM - just associate with something simple like the "whoami" command
        if ((retval = pam_start("whoami", argv[1], &pamc, &pamh)) == PAM_SUCCESS)
        {
            // Authenticate the user
            if ((retval = pam_authenticate(pamh, 0)) == PAM_SUCCESS) 
                fprintf(stdout, "OK\n"); 
            else 
                fprintf(stderr, "FAIL: pam_authentication failed.\n"); 

            // All done
            pam_end(pamh, 0); 
            return retval; 
        }
        else
        {
            fprintf(stderr, "FAIL: pam_start failed.\n"); 
            return retval;
        }
    }

    fprintf(stderr, "FAIL: expected two arguments for user name and password.\n"); 
    return 1; 
}

我在 google 的某处找到了它。问题是它没有找到主要的 pam_* 符号：

X@Y:~$ gcc -o checkpwd -lpam -lpam_misc checkpwd.c
/tmp/ccjIBywU.o: In Funktion `main': 
checkpwd.c:(.text+0xcf): Nicht definierter Verweis auf `pam_start'  
checkpwd.c:(.text+0xe9): Nicht definierter Verweis auf `pam_authenticate'
checkpwd.c:(.text+0x141): Nicht definierter Verweis auf `pam_end' 
collect2: error: ld returned 1 exit status

对不起德国人，它的意思是 "missing symbol"。这就是我的问题：为什么找不到符号？我需要包含哪些库？当我在 libpam.a 上执行 nm 时，我可以找到所有符号：

X@Y:~$ nm /usr/lib/x86_64-linux-gnu/libpam.a | grep pam_start
             U _pam_start_timer
    0000000000000010 T _pam_start_timer
    0000000000001930 T _pam_start_handlers
             U _pam_start_timer
pam_start.o:
    0000000000000000 T pam_start
             U _pam_start_handlers
kai@KTEC32:~$ nm /usr/lib/x86_64-linux-gnu/libpam.a | grep pam_authenticate
    0000000000000000 T pam_authenticate

谁能看出这里出了什么问题？

感谢任何提示。

Answer 1

您必须将源文件和目标文件放在库文件之前：

gcc -o checkpwd checkpwd.c -lpam -lpam_misc

参见：Why does the order of '-l' option in gcc matter?

为什么我的程序 link pam_* 不能调用

Why can't my program link pam_* calls

c

pam