Objc Regex - 用组解析字符串

Question

我正在尝试解析“:”前后的文本文件和组信息，这样我就可以知道什么与什么相关。

我正在使用以下

//NSString *pattern = @"\[(.*?)\]"; //[]
//NSString *pattern = @"(\w+:)"; //word:
NSString *pattern =@"(\w+:)\[(.*?)\]";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern options:NSRegularExpressionCaseInsensitive error:nil];
NSString *input = contents; //contents being the value taken from the text file

NSMutableArray *matches = [NSMutableArray arrayWithCapacity:[myArray count]];
for (NSTextCheckingResult *match in myArray) {
    //NSUInteger numberOfRanges = [match numberOfRanges];
    //NSLog(@"%lu", (unsigned long)numberOfRanges);
    NSRange matchRange = [match rangeAtIndex:1];
    [matches addObject:[input substringWithRange:matchRange]];
    NSLog(@"%@", [matches lastObject]);
}

“[]”有效，"word:" 有效，但当我将它们结合在一起时，我什么也得不到。

括号（输出）

2016-03-26 09:20:36.302 LevelBuilder[14658:550234] 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1
...
2016-03-26 09:20:36.304 LevelBuilder[14658:550234] 17,1

字（输出）

2016-03-26 09:18:18.189 LevelBuilder[14464:543898] tiles:
2016-03-26 09:18:18.189 LevelBuilder[14464:543898] boxes:
2016-03-26 09:18:18.189 LevelBuilder[14464:543898] goals:
2016-03-26 09:18:18.189 LevelBuilder[14464:543898] start:

我在模式中遗漏了什么

NSString *pattern =@"(\w+:)\[(.*?)\]";

数据为例

tiles:
    [
         [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1]
        ,[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,1]
        ,[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,1]
        ,[0,0,0,0,0,1,1,1,1,1,1,1,1,1,0,1,0,0,1]
        ,[1,1,1,1,1,1,0,0,0,0,0,0,0,1,1,1,0,0,1]
        ,[1,0,0,0,0,0,0,1,1,1,0,0,0,0,0,0,0,0,1]
        ,[1,0,0,0,0,0,0,1,1,1,0,0,1,1,1,0,0,0,1]
        ,[1,0,0,0,0,0,0,0,0,0,0,0,1,0,1,0,0,0,1]
        ,[1,0,0,1,1,1,1,1,1,1,1,1,1,0,1,0,0,0,1]
        ,[1,0,0,0,1,0,0,0,0,0,0,0,0,0,1,1,1,1,1]
        ,[1,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
        ,[1,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
        ,[1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
    ],
    boxes: [
            [5,6],[6,5],[10,5],[11,5],[16,4],[16,5],[16,6],[16,7]
            ],
    goals: [
            [1,8],[1,9],[1,10],[1,11],[2,10],[2,11],[3,10],[3,11]
            ],
    start: [17,1]

Answer 1

由于您需要匹配每个 "word" 后跟相应的 [...]，您可以使用包含 2 个捕获组的正则表达式模式和一个前瞻性 "temper" 惰性点匹配图案：

@"(?s)(\w+):\s*\[(.*?)\](?=,\r?\n\s*\w+:|$)"

见regex demo

模式匹配：

(?s)- 使 . 匹配换行符
(\w+): - 匹配并捕获到第 1 组一个或多个字母数字字符，然后匹配 :
\s* - 0+ 个空白字符
\[(.*?)\] - 匹配 [...] 如果最后 ]...
(?=,\r?\n\s*\w+:|$) - 后跟字符串结尾 ($) 或逗号后跟换行符后跟 0+ 空格符号后跟 "word" 后跟 :.

Objc Regex - 用组解析字符串

Objc Regex - Parse string with groups

objective-c

regex

nsregularexpression