Python，在一个文件中，有逗号分隔的值，如何检查行之间的重复值并删除重复的行？

Question

我有一个这种格式的 txt 文件：

01，西班牙
02，美国
03，印度
01，意大利
01，葡萄牙
04，巴西

我需要检查号码是否重复，例如在这个例子中，号码“01”有西班牙、意大利和葡萄牙。如果两行或多行具有相同的数字，我只需要保留重复数字的第一个出现并摆脱其他 apparitions.It 将在文件中显示：

01，西班牙
02，美国
03，印度
04，巴西

Answer 1

import sets
seen = sets.Set()
with open('in.txt', 'r'), open('out.txt', 'w') as fr, fw:
    for line in fr:
        row = line.split(',')
        if row[0] not in seen:
            fw.write(line)
            seen.add(row[0])

Answer 2

import os
with open("file.txt", "r") as infile:
    numbers = set()
    f = open("_file.txt", "w")
    for line in infile:
        tokens = line.split(',')
        if int(tokens[0]) not in numbers:
            numbers.add(int(tokens[0]))
            f.write(line)
    f.close()
os.remove("file.txt")
os.rename("_file.txt", "file.txt")

Answer 3

# Read your entire file into memory.
my_file = 'my_file.txt'
with open(my_file) as f_in:
    content = f_in.readlines()

# Keep track of the numbers that have already appeared
# while rewriting the content back to your file.
numbers = []
with open(my_file, 'w') as f_out:
    for line in content:
        number, country = line.split(',')
        if not number in numbers:
            f_out.write(line)
            numbers.append(number)

我希望这是最容易理解的。

Python，在一个文件中，有逗号分隔的值，如何检查行之间的重复值并删除重复的行？

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