在 Sequelize ORM 中加入 table 的条件

Question

我想通过 sequelize ORM 获得这样的查询：

SELECT "A".*,      
FROM "A" 
LEFT OUTER JOIN "B" ON "A"."bId" = "B"."id"
LEFT OUTER JOIN "C" ON "A"."cId" = "C"."id"
WHERE ("B"."userId" = '100'
       OR "C"."userId" = '100')

问题是续集不允许我在 where 子句中引用 "B" 或 "C" table。以下代码

A.findAll({
    include: [{
        model: B,
        where: {
            userId: 100
        },
        required: false

    }, {
        model: C,
        where: {
            userId: 100
        },
        required: false
    }]
]

给我

SELECT "A".*,      
FROM "A" 
LEFT OUTER JOIN "B" ON "A"."bId" = "B"."id" AND "B"."userId" = 100
LEFT OUTER JOIN "C" ON "A"."cId" = "C"."id" AND "C"."userId" = 100

这是完全不同的查询，

的结果

A.findAll({
    where: {
        $or: [
            {'"B"."userId"' : 100},
            {'"C"."userId"' : 100}
        ]
    },
    include: [{
        model: B,
        required: false

    }, {
        model: C,
        required: false
    }]
]

甚至不是一个有效的查询：

SELECT "A".*,      
FROM "A" 
LEFT OUTER JOIN "B" ON "A"."bId" = "B"."id"
LEFT OUTER JOIN "C" ON "A"."cId" = "C"."id"
WHERE ("A"."B.userId" = '100'
       OR "A"."C.userId" = '100')

是否可以使用 sequelize 进行首次查询，或者我应该坚持使用原始查询？

Answer 1

包装在$$

中引用连接表的列

A.findAll({
    where: {
        $or: [
            {'$B.userId$' : 100},
            {'$C.userId$' : 100}
        ]
    },
    include: [{
        model: B,
        required: false

    }, {
        model: C,
        required: false
    }]
});

Answer 2

在 include 和 join 中添加 where 条件。

    {
       model: C,
       where: {
        id: 1
       }
   }

在 Sequelize ORM 中加入 table 的条件

Where condition for joined table in Sequelize ORM

javascript

sql

postgresql

orm

sequelize.js