SQL 计算相同的两行之间的日期时间差异的语句 Table

Question

我在表 1 中有 2 列：Time_Stamp 和 RunTimeMinute。如何从对应于 RunTimeMinute=1 的 Time_Stamp 值中减去 RunTimeMinute=0 的 Time_Stamp 值（这将给我获得机器运行所花费的时间）？

Time_Stamp                      RunTimeMinute
    2016-03-01 04:32:10.0000000 1
    2016-03-01 04:33:11.0000000 2
    2016-03-01 04:34:13.0000000 3
    2016-03-01 04:35:15.0000000 4
    2016-03-01 04:36:16.0000000 5
    2016-03-01 04:37:18.0000000 6
    2016-03-01 04:38:20.0000000 7
    2016-03-01 04:39:22.0000000 8
    2016-03-01 04:40:23.0000000 9
    2016-03-01 04:41:16.0000000 0
    2016-03-01 04:45:36.0000000 10

Answer 1

SELECT DATEDIFF(mi,(cast(Time_STAMP) as Datetime),RunTime)

Answer 2

要完成您所描述的任务（前提是 Time_Stamp 字段是 DateTime 类型且 RunTimeMinute 是整数），您可以使用 SQL SELECT Query/Subquery 技术和 DATEDIFF() 函数如下例所示：

SELECT [YourTable].Time_Stamp AS t1,
(SELECT YourTable.Time_Stamp FROM YourTable WHERE YourTable.RunTimeMinute=1) AS t0, 
DateDiff("n",[t0],[t1]) AS ElapsedTimeMin
FROM YourTable
WHERE ([YourTable].RunTimeMinute)=0;

ElapsedTimeMin 将以分钟为单位显示结果。您可以将 DATEDIFF() 函数的 "datepart" 指定为 "s" 以在几秒钟内获得结果。

希望这可能有所帮助。

Answer 3

例如我们有这样一个示例：

CREATE TABLE Table1 (
  Time_Stamp datetime,
  RunTimeMinute int
)
INSERT INTO Table1 VALUES                                         
('2016-03-01 04:32:10.000', 1),
('2016-03-01 04:33:11.000', 2),
('2016-03-01 04:34:13.000', 3),
('2016-03-01 04:35:15.000', 4),
('2016-03-01 04:36:16.000', 5),
('2016-03-01 04:37:18.000', 6),
('2016-03-01 04:38:20.000', 7),
('2016-03-01 04:39:22.000', 8),
('2016-03-01 04:40:23.000', 9),
('2016-03-01 04:41:16.000', 0),
('2016-03-01 04:45:36.000', 10),
('2016-03-01 05:31:10.000', 1),
('2016-03-01 05:35:11.000', 2),
('2016-03-01 05:37:13.000', 3),
('2016-03-01 05:39:15.000', 4),
('2016-03-01 05:41:16.000', 5),
('2016-03-01 05:46:18.000', 6),
('2016-03-01 05:48:20.000', 7),
('2016-03-01 05:51:22.000', 8),
('2016-03-01 05:53:23.000', 9),
('2016-03-01 05:55:16.000', 0),
('2016-03-01 05:57:36.000', 10),
('2016-03-02 05:34:09.000', 1),
('2016-03-02 05:35:14.000', 2),
('2016-03-02 05:36:11.000', 3),
('2016-03-02 05:37:18.000', 4),
('2016-03-02 05:38:20.000', 5),
('2016-03-02 05:39:38.000', 6),
('2016-03-02 05:40:40.000', 7),
('2016-03-02 05:41:12.000', 8),
('2016-03-02 05:42:32.000', 9),
('2016-03-02 05:44:11.000', 0),
('2016-03-02 05:47:38.000', 10)

然后我们做这个：

;WITH cte AS (
    SELECT  Time_Stamp,
            RunTimeMinute,
            ROW_NUMBER() OVER (PARTITION BY RunTimeMinute ORDER BY Time_Stamp) AS rnum
    FROM Table1
    WHERE RunTimeMinute IN (0,1)
  )

SELECT  MIN(Time_Stamp) as StartTime,
        DATEDIFF(minute, MIN(Time_Stamp), MAX(Time_Stamp)) AS ElapsedTimeMin
FROM cte
GROUP BY rnum

得到这个：

|               StartTime | ElapsedTimeMin |
|-------------------------|----------------|
| March, 01 2016 04:32:10 |              9 |
| March, 01 2016 05:31:10 |             24 |
| March, 02 2016 05:34:09 |             10 |

SQL 计算相同的两行之间的日期时间差异的语句 Table

SQL Statement to Calculate DateTime Difference between Two Rows of the same Table

sql

sql-server

subquery

datediff