需要帮助，无法转换类型 '(NSURLRequest!, NSHTTPURLResponse!, UIImage!) 的值

Question

我收到一条错误消息

Cannot convert value of type (NSURLRequest!, NSHTTPURLResponse!, UIImage!) -> Void' to expected argument type '((NSURLRequest, NSHTTPURLResponse?, UIImage) -> Void)?

这是代码

import UIKit

class RoutineCell: UITableViewCell {

@IBOutlet weak var bannerImageView: UIImageView!
@IBOutlet weak var routineTitleLabel: UILabel!
@IBOutlet weak var shortDescriptionLabel: UILabel!

var routine: Routine! {
    didSet {
        routineTitleLabel.text = routine.title
        shortDescriptionLabel.text = routine.shortDescription
        bannerImageView.setImageWithURL(NSURL(string: routine.bannerImageUrl)!)
        bannerImageView.setImageWithURLRequest(NSURLRequest(URL: NSURL(string: routine.bannerImageUrl)!), placeholderImage: nil, success: { (request: NSURLRequest!, response: NSHTTPURLResponse!, image: UIImage!) -> Void in
            self.bannerImageView.alpha = 0.0
            self.bannerImageView.image = image
            UIView.animateWithDuration(0.2, animations: { () -> Void in
                self.bannerImageView.alpha = 1.0
            })
        }, failure: nil)
    }
}

override func awakeFromNib() {
    self.selectionStyle = UITableViewCellSelectionStyle.None
    super.awakeFromNib()
}

override func prepareForReuse() {
    bannerImageView.image = nil
}

override func setSelected(selected: Bool, animated: Bool) {
    super.setSelected(selected, animated: animated)

    // Configure the view for the selected state
}

}

感谢

Answer 1

您对 bannerImageView.setImageWithURLRequest 回调的声明是错误的

(request: NSURLRequest!, response: NSHTTPURLResponse!, image: UIImage!)

您需要使用以下内容

(request: NSURLRequest, response: NSHTTPURLResponse?, image: UIImage)

需要帮助，无法转换类型 '(NSURLRequest!, NSHTTPURLResponse!, UIImage!) 的值

Need help, Cannot convert value of type '(NSURLRequest!, NSHTTPURLResponse!, UIImage!)

nsurlconnection

nsurlrequest

ios

swift