How to fix Error: this class is not key value coding-compliant for the key tableView.'

How to fix Error: this class is not key value coding-compliant for the key tableView.'

我用 Table ViewSegmented Control 制作了一个应用程序,这是我的第一次。我正在使用一些代码和一些教程,但它不起作用。当我 运行 我的应用程序崩溃时,它在日志中显示此错误:

MyApplication[4928:336085] * Terminating app due to uncaught exception 'NSUnknownKeyException', reason: '[ setValue:forUndefinedKey:]: this class is not key value coding-compliant for the key tableView.' * First throw call stack: ( 0 CoreFoundation 0x000000010516fd85 __exceptionPreprocess + 165 1 libobjc.A.dylib 0x0000000105504deb objc_exception_throw + 48 2 CoreFoundation 0x000000010516f9c9 -[NSException raise] + 9 3 Foundation 0x000000010364e19b -[NSObject(NSKeyValueCoding) setValue:forKey:] + 288 4 UIKit 0x0000000103c37d0c -[UIViewController setValue:forKey:] + 88 5 UIKit 0x0000000103e6e7fb -[UIRuntimeOutletConnection connect] + 109 6 CoreFoundation 0x00000001050a9890 -[NSArray makeObjectsPerformSelector:] + 224 7 UIKit 0x0000000103e6d1de -[UINib instantiateWithOwner:options:] + 1864 8 UIKit 0x0000000103c3e8d6 -[UIViewController _loadViewFromNibNamed:bundle:] + 381 9 UIKit 0x0000000103c3f202 -[UIViewController loadView] + 178 10 UIKit 0x0000000103c3f560 -[UIViewController loadViewIfRequired] + 138 11 UIKit 0x0000000103c3fcd3 -[UIViewController view] + 27 12 UIKit 0x000000010440b024 -[_UIFullscreenPresentationController _setPresentedViewController:] + 87 13 UIKit 0x0000000103c0f5ca -[UIPresentationController initWithPresentedViewController:presentingViewController:] + 133 14 UIKit 0x0000000103c525bb -[UIViewController _presentViewController:withAnimationController:completion:] + 4002 15 UIKit 0x0000000103c5585c -[UIViewController _performCoordinatedPresentOrDismiss:animated:] + 489 16 UIKit 0x0000000103c5536b -[UIViewController presentViewController:animated:completion:] + 179 17 UIKit 0x00000001041feb8d __67-[UIStoryboardModalSegueTemplate newDefaultPerformHandlerForSegue:]_block_invoke + 243 18 UIKit 0x00000001041ec630 -[UIStoryboardSegueTemplate _performWithDestinationViewController:sender:] + 460 19 UIKit 0x00000001041ec433 -[UIStoryboardSegueTemplate _perform:] + 82 20 UIKit 0x00000001041ec6f7 -[UIStoryboardSegueTemplate perform:] + 156 21 UIKit 0x0000000103aa6a8d -[UIApplication sendAction:to:from:forEvent:] + 92 22 UIKit 0x0000000103c19e67 -[UIControl sendAction:to:forEvent:] + 67 23 UIKit 0x0000000103c1a143 -[UIControl _sendActionsForEvents:withEvent:] + 327 24 UIKit 0x0000000103c19263 -[UIControl touchesEnded:withEvent:] + 601 25 UIKit 0x0000000103b1999f -[UIWindow _sendTouchesForEvent:] + 835 26 UIKit 0x0000000103b1a6d4 -[UIWindow sendEvent:] + 865 27 UIKit 0x0000000103ac5dc6 -[UIApplication sendEvent:] + 263 28 UIKit 0x0000000103a9f553 _UIApplicationHandleEventQueue + 6660 29 CoreFoundation 0x0000000105095301 _CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION_ + 17 30 CoreFoundation 0x000000010508b22c __CFRunLoopDoSources0 + 556 31 CoreFoundation 0x000000010508a6e3 __CFRunLoopRun + 867 32 CoreFoundation 0x000000010508a0f8 CFRunLoopRunSpecific + 488 33 GraphicsServices 0x000000010726dad2 GSEventRunModal + 161 34 UIKit 0x0000000103aa4f09 UIApplicationMain + 171 35 Dhikr 0x0000000101f26282 main + 114 36 libdyld.dylib 0x00000001064c392d start + 1 ) libc++abi.dylib: terminating with uncaught exception of type NSException

我使用的代码是:

class ViewController: UIViewController, UITableViewDataSource, UITableViewDelegate {

let foodList:[String] = ["Bread", "Meat", "Pizza", "Other"]
let drinkList:[String] = ["Water", "Soda", "Juice", "Other"]

@IBOutlet weak var mySegmentedControl: UISegmentedControl!
@IBOutlet weak var myTableView: UITableView!

override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view.
}

func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {

    var returnValue = 0

    switch(mySegmentedControl.selectedSegmentIndex) {
    case 0:
        returnValue = foodList.count
        break
    case 1:
        returnValue = drinkList.count
        break
    default:
        break
    }

    return returnValue
}

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    let myCell = tableView.dequeueReusableCellWithIdentifier("myCells", forIndexPath: indexPath)

    switch(mySegmentedControl.selectedSegmentIndex) {
    case 0:
        myCell.textLabel!.text = foodList[indexPath.row]
        break
    case 1:
        myCell.textLabel!.text = drinkList[indexPath.row]
        break
    default:
        break
    }

    return myCell
}

@IBAction func segmentedControlActionChanged(sender: AnyObject) {
    myTableView.reloadData()  
}

这里是main.Storyboard

我检查了很多次代码,但它不起作用。首先我不得不只使用 Table View,看着这个教程 (https://www.youtube.com/watch?v=ABVLSF3Vqdg) 我认为它会像教程中那样使用 Segmented Control。但还是不行。相同的代码,相同的错误。 有人可以帮助我吗?

您是否曾将 table 视图的名称从 "tableView" 更改为 "myTableView"?

您已将故事板设置为期待一个名为 tableView 的出口,但实际出口名称为 myTableView

如果删除情节提要中的连接并重新连接到正确的变量名,应该可以解决问题。