How to fix Error: this class is not key value coding-compliant for the key tableView.'
How to fix Error: this class is not key value coding-compliant for the key tableView.'
我用 Table View
和 Segmented Control
制作了一个应用程序,这是我的第一次。我正在使用一些代码和一些教程,但它不起作用。当我 运行 我的应用程序崩溃时,它在日志中显示此错误:
MyApplication[4928:336085] * Terminating app due to uncaught exception 'NSUnknownKeyException', reason: '[ setValue:forUndefinedKey:]: this class is not key value coding-compliant for the key tableView.'
* First throw call stack:
(
0 CoreFoundation 0x000000010516fd85 __exceptionPreprocess + 165
1 libobjc.A.dylib 0x0000000105504deb objc_exception_throw + 48
2 CoreFoundation 0x000000010516f9c9 -[NSException raise] + 9
3 Foundation 0x000000010364e19b -[NSObject(NSKeyValueCoding) setValue:forKey:] + 288
4 UIKit 0x0000000103c37d0c -[UIViewController setValue:forKey:] + 88
5 UIKit 0x0000000103e6e7fb -[UIRuntimeOutletConnection connect] + 109
6 CoreFoundation 0x00000001050a9890 -[NSArray makeObjectsPerformSelector:] + 224
7 UIKit 0x0000000103e6d1de -[UINib instantiateWithOwner:options:] + 1864
8 UIKit 0x0000000103c3e8d6 -[UIViewController _loadViewFromNibNamed:bundle:] + 381
9 UIKit 0x0000000103c3f202 -[UIViewController loadView] + 178
10 UIKit 0x0000000103c3f560 -[UIViewController loadViewIfRequired] + 138
11 UIKit 0x0000000103c3fcd3 -[UIViewController view] + 27
12 UIKit 0x000000010440b024 -[_UIFullscreenPresentationController _setPresentedViewController:] + 87
13 UIKit 0x0000000103c0f5ca -[UIPresentationController initWithPresentedViewController:presentingViewController:] + 133
14 UIKit 0x0000000103c525bb -[UIViewController _presentViewController:withAnimationController:completion:] + 4002
15 UIKit 0x0000000103c5585c -[UIViewController _performCoordinatedPresentOrDismiss:animated:] + 489
16 UIKit 0x0000000103c5536b -[UIViewController presentViewController:animated:completion:] + 179
17 UIKit 0x00000001041feb8d __67-[UIStoryboardModalSegueTemplate newDefaultPerformHandlerForSegue:]_block_invoke + 243
18 UIKit 0x00000001041ec630 -[UIStoryboardSegueTemplate _performWithDestinationViewController:sender:] + 460
19 UIKit 0x00000001041ec433 -[UIStoryboardSegueTemplate _perform:] + 82
20 UIKit 0x00000001041ec6f7 -[UIStoryboardSegueTemplate perform:] + 156
21 UIKit 0x0000000103aa6a8d -[UIApplication sendAction:to:from:forEvent:] + 92
22 UIKit 0x0000000103c19e67 -[UIControl sendAction:to:forEvent:] + 67
23 UIKit 0x0000000103c1a143 -[UIControl _sendActionsForEvents:withEvent:] + 327
24 UIKit 0x0000000103c19263 -[UIControl touchesEnded:withEvent:] + 601
25 UIKit 0x0000000103b1999f -[UIWindow _sendTouchesForEvent:] + 835
26 UIKit 0x0000000103b1a6d4 -[UIWindow sendEvent:] + 865
27 UIKit 0x0000000103ac5dc6 -[UIApplication sendEvent:] + 263
28 UIKit 0x0000000103a9f553 _UIApplicationHandleEventQueue + 6660
29 CoreFoundation 0x0000000105095301 _CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION_ + 17
30 CoreFoundation 0x000000010508b22c __CFRunLoopDoSources0 + 556
31 CoreFoundation 0x000000010508a6e3 __CFRunLoopRun + 867
32 CoreFoundation 0x000000010508a0f8 CFRunLoopRunSpecific + 488
33 GraphicsServices 0x000000010726dad2 GSEventRunModal + 161
34 UIKit 0x0000000103aa4f09 UIApplicationMain + 171
35 Dhikr 0x0000000101f26282 main + 114
36 libdyld.dylib 0x00000001064c392d start + 1
)
libc++abi.dylib: terminating with uncaught exception of type NSException
我使用的代码是:
class ViewController: UIViewController, UITableViewDataSource, UITableViewDelegate {
let foodList:[String] = ["Bread", "Meat", "Pizza", "Other"]
let drinkList:[String] = ["Water", "Soda", "Juice", "Other"]
@IBOutlet weak var mySegmentedControl: UISegmentedControl!
@IBOutlet weak var myTableView: UITableView!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
}
func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
var returnValue = 0
switch(mySegmentedControl.selectedSegmentIndex) {
case 0:
returnValue = foodList.count
break
case 1:
returnValue = drinkList.count
break
default:
break
}
return returnValue
}
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let myCell = tableView.dequeueReusableCellWithIdentifier("myCells", forIndexPath: indexPath)
switch(mySegmentedControl.selectedSegmentIndex) {
case 0:
myCell.textLabel!.text = foodList[indexPath.row]
break
case 1:
myCell.textLabel!.text = drinkList[indexPath.row]
break
default:
break
}
return myCell
}
@IBAction func segmentedControlActionChanged(sender: AnyObject) {
myTableView.reloadData()
}
这里是main.Storyboard
我检查了很多次代码,但它不起作用。首先我不得不只使用 Table View
,看着这个教程 (https://www.youtube.com/watch?v=ABVLSF3Vqdg) 我认为它会像教程中那样使用 Segmented Control
。但还是不行。相同的代码,相同的错误。
有人可以帮助我吗?
您是否曾将 table 视图的名称从 "tableView" 更改为 "myTableView"?
您已将故事板设置为期待一个名为 tableView
的出口,但实际出口名称为 myTableView
。
如果删除情节提要中的连接并重新连接到正确的变量名,应该可以解决问题。
我用 Table View
和 Segmented Control
制作了一个应用程序,这是我的第一次。我正在使用一些代码和一些教程,但它不起作用。当我 运行 我的应用程序崩溃时,它在日志中显示此错误:
MyApplication[4928:336085] * Terminating app due to uncaught exception 'NSUnknownKeyException', reason: '[ setValue:forUndefinedKey:]: this class is not key value coding-compliant for the key tableView.' * First throw call stack: ( 0 CoreFoundation 0x000000010516fd85 __exceptionPreprocess + 165 1 libobjc.A.dylib 0x0000000105504deb objc_exception_throw + 48 2 CoreFoundation 0x000000010516f9c9 -[NSException raise] + 9 3 Foundation 0x000000010364e19b -[NSObject(NSKeyValueCoding) setValue:forKey:] + 288 4 UIKit 0x0000000103c37d0c -[UIViewController setValue:forKey:] + 88 5 UIKit 0x0000000103e6e7fb -[UIRuntimeOutletConnection connect] + 109 6 CoreFoundation 0x00000001050a9890 -[NSArray makeObjectsPerformSelector:] + 224 7 UIKit 0x0000000103e6d1de -[UINib instantiateWithOwner:options:] + 1864 8 UIKit 0x0000000103c3e8d6 -[UIViewController _loadViewFromNibNamed:bundle:] + 381 9 UIKit 0x0000000103c3f202 -[UIViewController loadView] + 178 10 UIKit 0x0000000103c3f560 -[UIViewController loadViewIfRequired] + 138 11 UIKit 0x0000000103c3fcd3 -[UIViewController view] + 27 12 UIKit 0x000000010440b024 -[_UIFullscreenPresentationController _setPresentedViewController:] + 87 13 UIKit 0x0000000103c0f5ca -[UIPresentationController initWithPresentedViewController:presentingViewController:] + 133 14 UIKit 0x0000000103c525bb -[UIViewController _presentViewController:withAnimationController:completion:] + 4002 15 UIKit 0x0000000103c5585c -[UIViewController _performCoordinatedPresentOrDismiss:animated:] + 489 16 UIKit 0x0000000103c5536b -[UIViewController presentViewController:animated:completion:] + 179 17 UIKit 0x00000001041feb8d __67-[UIStoryboardModalSegueTemplate newDefaultPerformHandlerForSegue:]_block_invoke + 243 18 UIKit 0x00000001041ec630 -[UIStoryboardSegueTemplate _performWithDestinationViewController:sender:] + 460 19 UIKit 0x00000001041ec433 -[UIStoryboardSegueTemplate _perform:] + 82 20 UIKit 0x00000001041ec6f7 -[UIStoryboardSegueTemplate perform:] + 156 21 UIKit 0x0000000103aa6a8d -[UIApplication sendAction:to:from:forEvent:] + 92 22 UIKit 0x0000000103c19e67 -[UIControl sendAction:to:forEvent:] + 67 23 UIKit 0x0000000103c1a143 -[UIControl _sendActionsForEvents:withEvent:] + 327 24 UIKit 0x0000000103c19263 -[UIControl touchesEnded:withEvent:] + 601 25 UIKit 0x0000000103b1999f -[UIWindow _sendTouchesForEvent:] + 835 26 UIKit 0x0000000103b1a6d4 -[UIWindow sendEvent:] + 865 27 UIKit 0x0000000103ac5dc6 -[UIApplication sendEvent:] + 263 28 UIKit 0x0000000103a9f553 _UIApplicationHandleEventQueue + 6660 29 CoreFoundation 0x0000000105095301 _CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION_ + 17 30 CoreFoundation 0x000000010508b22c __CFRunLoopDoSources0 + 556 31 CoreFoundation 0x000000010508a6e3 __CFRunLoopRun + 867 32 CoreFoundation 0x000000010508a0f8 CFRunLoopRunSpecific + 488 33 GraphicsServices 0x000000010726dad2 GSEventRunModal + 161 34 UIKit 0x0000000103aa4f09 UIApplicationMain + 171 35 Dhikr 0x0000000101f26282 main + 114 36 libdyld.dylib 0x00000001064c392d start + 1 ) libc++abi.dylib: terminating with uncaught exception of type NSException
我使用的代码是:
class ViewController: UIViewController, UITableViewDataSource, UITableViewDelegate {
let foodList:[String] = ["Bread", "Meat", "Pizza", "Other"]
let drinkList:[String] = ["Water", "Soda", "Juice", "Other"]
@IBOutlet weak var mySegmentedControl: UISegmentedControl!
@IBOutlet weak var myTableView: UITableView!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
}
func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
var returnValue = 0
switch(mySegmentedControl.selectedSegmentIndex) {
case 0:
returnValue = foodList.count
break
case 1:
returnValue = drinkList.count
break
default:
break
}
return returnValue
}
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let myCell = tableView.dequeueReusableCellWithIdentifier("myCells", forIndexPath: indexPath)
switch(mySegmentedControl.selectedSegmentIndex) {
case 0:
myCell.textLabel!.text = foodList[indexPath.row]
break
case 1:
myCell.textLabel!.text = drinkList[indexPath.row]
break
default:
break
}
return myCell
}
@IBAction func segmentedControlActionChanged(sender: AnyObject) {
myTableView.reloadData()
}
这里是main.Storyboard
我检查了很多次代码,但它不起作用。首先我不得不只使用 Table View
,看着这个教程 (https://www.youtube.com/watch?v=ABVLSF3Vqdg) 我认为它会像教程中那样使用 Segmented Control
。但还是不行。相同的代码,相同的错误。
有人可以帮助我吗?
您是否曾将 table 视图的名称从 "tableView" 更改为 "myTableView"?
您已将故事板设置为期待一个名为 tableView
的出口,但实际出口名称为 myTableView
。
如果删除情节提要中的连接并重新连接到正确的变量名,应该可以解决问题。