圆环图 python

Question

所以我使用这段代码创建了一个带 python 的圆环图（灵感来自这个圆环图 recipe）：

def make_pie(sizes, text,colors,labels):
    import matplotlib.pyplot as plt
    import numpy as np

    col = [[i/255. for i in c] for c in colors]

    fig, ax = plt.subplots()
    ax.axis('equal')
    width = 0.35
    kwargs = dict(colors=col, startangle=180)
    outside, _ = ax.pie(sizes, radius=1, pctdistance=1-width/2,labels=labels,**kwargs)
    plt.setp( outside, width=width, edgecolor='white')

    kwargs = dict(size=20, fontweight='bold', va='center')
    ax.text(0, 0, text, ha='center', **kwargs)
    plt.show()

c1 = (226,33,7)
c2 = (60,121,189)

make_pie([257,90], "Gender (AR)",[c1,c2],['M','F'])

这导致：

我的问题是现在我想要各自的百分比。为此，我只是添加了参数：

autopct='%1.1f%%'

像这样：

kwargs = dict(colors=col, startangle=180,autopct='%1.1f%%')

但这会导致以下错误：

Traceback (most recent call last):
  File "draw.py", line 30, in <module>
    make_pie([257,90], "Gender (AR)",[c1,c2],['M','F'])
  File "draw.py", line 13, in make_pie
    outside, _ = ax.pie(sizes, radius=1, pctdistance=1-width/2,labels=labels,**kwargs)
ValueError: too many values to unpack

所以，我做错了什么？

Answer 1

来自文档字符串：

If *autopct* is not *None*, return the tuple (*patches*,
  *texts*, *autotexts*), where *patches* and *texts* are as
  above, and *autotexts* is a list of
  :class:`~matplotlib.text.Text` instances for the numeric
  labels.

因此，如果您想使用 autopct 解压 pie() 的结果，您需要 3 个值：

kwargs = dict(colors=col, startangle=180, autopct='%1.1f%%')
outside, _, _ = ax.pie(sizes, radius=1, pctdistance=1-width/2,
                       labels=labels,**kwargs)

或者它可能在不解包的情况下更健壮，所以它可以使用或不使用 autopct:

outside = ax.pie(sizes, radius=1, pctdistance=1-width/2,
                 labels=labels,**kwargs)[0]

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