HTTP POST 中的表单：Curl 到 pyCurl

Question

我正在尝试转换以下 Curl 片段：

-F "model={
name: 'myapp',
targets: [ { identity: [ 'servers', 'server_name' ] } ]
}" \
-F "sourcePath=@/deployments/MyApp/app/MyApp.ear"

进入 pyCurl:

targets_list = list()
targets_list.append(json.dumps({ 'identity': ['servers', 'server_name'] }, ensure_ascii=False))
model = json.dumps({"name": 'myapp', \
                            "targets": targets_list } )
sourcePath = "/deployments/MyApp/app/MyApp.ear"
send = [("model", model), ('sourcePath', \
                (pycurl.FORM_FILE, sourcePath)),]
curl_agent.setopt(pycurl.HTTPPOST, send)

但我收到 500 HTTP 错误：

{
    "detail": "JSONArray[0] is not a JSONObject.", 
    "status": 500
}

问题肯定出在 'targets' 列表上...有什么想法吗？

编辑：这是完整的 Python 脚本：

import pycurl, json

url = "http://localhost:7001/some_context"
agent = pycurl.Curl()
agent.setopt(pycurl.POST, 1)
targets_list = list()
targets_list.append(json.dumps({ 'identity': ['servers', 'server_name'] }, ensure_ascii=False))
model = json.dumps({"name": 'myapp', \
                        "targets": targets_list } )
sourcePath = "/deployments/MyApp/app/MyApp.earr"
send = [("model", model), ('sourcePath', \
            (pycurl.FORM_FILE, sourcePath)),]
agent.setopt(pycurl.HTTPPOST, send)
agent.setopt(pycurl.URL, url)
agent.setopt(pycurl.HTTPHEADER, ['Accept: application/json',
                         'X-Requested-By:MyClient',
                         'Content-Type:multipart/form-data',
                         'Content-Length:'])
agent.setopt(pycurl.VERBOSE, 1)
agent.setopt(pycurl.USERPWD, "user:XXXXXX")
agent.perform()

Answer 1

好的。

应该是：

targets_list.append({ 'identity': ['servers', 'server_name'] })

而不是：

targets_list.append(json.dumps({ 'identity': ['servers', 'server_name'] }, ensure_ascii=False))

现在可以了:)

HTTP POST 中的表单：Curl 到 pyCurl

Form in HTTP POST: Curl to pyCurl

python

curl

http-post

pycurl