C# XML 非嵌套序列化 arrays/list

Question

我正在编写一个 C# WinForm 应用程序，它应该读取一个预先存在的 XML 文件。我需要解析 XML 文件并建立一个数据结构来反映 XML 文件内容。我在 XML 序列化方面有一些经验，因此我想使用 .NET XML.Serialization 功能。我陷入了一个奇怪的 XML 结构，我无法在 class 中匹配（通过属性、元素等）：

<sheet number="1" name="/" tstamps="/">
  <title_block>
    <title>ECC Push-Pull</title>
    <company/>
    <rev>0.1</rev>
    <date>Sat 21 Mar 2015</date>
    <source>ecc83-pp.sch</source>
    <comment number="1" value=""/>
    <comment number="2" value=""/>
    <comment number="3" value=""/>
    <comment number="4" value=""/>
  </title_block>
</sheet>

其中的 'weird' 部分是评论列表。我习惯于使用 XmlArray 指令对 list/array 元素进行序列化，从而找到此类 'repeating' 项。无论如何使用这种方法都会引入一个包围标签来包含项目列表。在这种情况下我怎样才能'reflect'这个结构呢？这是我应该使用的代码（没有 'missing' 注释）：

[XmlRoot("sheet")]
public class Sheet
{
    [XmlAttribute("number")]
    public int Number { get; }

    [XmlAttribute("name")]
    public string Name { get; set; }

    [XmlAttribute("tstamps")]
    public UInt32 TimeStamps { get; set; }

    [XmlElement]
    public SheetTitle Title { get; set; }

    public Sheet()
    {
        Title = new SheetTitle();
    }
}


[XmlRoot("title_block")]
public class SheetTitle
{
    [XmlElement("title")]
    public string Title { get; set; }

    [XmlElement("company")]
    public string Company { get; set; }

    [XmlElement("rev")]
    public string Revision { get; set; }

    [XmlElement("date")]
    public DateTime Date { get; set; }

    [XmlElement("source")]
    public string Source { get; set; }

    public SheetTitle()
    {
        Date = DateTime.Now;
    }
}

[XmlRoot("comment")]
public class Comment
{
    [XmlAttribute("number")]
    public int Number { get; set; }

    [XmlAttribute("value")]
    public string Value { get; set; }
}

我还有另一个问题。反映此结构的最佳 class 层次结构是： a) 以与 xml 元素相同的方式嵌套 classes b) 将所有 classes 保持在同一级别（没有层次结构）？有副作用需要考虑吗？

Answer 1

您可以按如下方式定义 C# 对象。

[XmlRoot(ElementName="comment")]
public class Comment {
    [XmlAttribute(AttributeName="number")]
    public string Number { get; set; }
    [XmlAttribute(AttributeName="value")]
    public string Value { get; set; }
}

[XmlRoot(ElementName="title_block")]
public class Title_block {
    [XmlElement(ElementName="title")]
    public string Title { get; set; }
    [XmlElement(ElementName="company")]
    public string Company { get; set; }
    [XmlElement(ElementName="rev")]
    public string Rev { get; set; }
    [XmlElement(ElementName="date")]
    public string Date { get; set; }
    [XmlElement(ElementName="source")]
    public string Source { get; set; }
    [XmlElement(ElementName="comment")]
    public List<Comment> Comment { get; set; }
}

[XmlRoot(ElementName="sheet")]
public class Sheet {
    [XmlElement(ElementName="title_block")]
    public Title_block Title_block { get; set; }
    [XmlAttribute(AttributeName="number")]
    public string Number { get; set; }
    [XmlAttribute(AttributeName="name")]
    public string Name { get; set; }
    [XmlAttribute(AttributeName="tstamps")]
    public string Tstamps { get; set; }
}

现在我们可以使用这些实体 Deserialize 给定 Xml。

XmlSerializer serializer = new XmlSerializer(typeof(Sheet));

StreamReader reader = new StreamReader(filepath);
var sheet = (Sheet)serializer.Deserialize(reader);
reader.Close();

检查这个 Demo code

Answer 2

试试这个...

使用

using System.Collections.Generic;
using System.IO;
using System.Text;
using System.Xml;
using System.Xml.Serialization;

类

[XmlRoot(ElementName = "comment")]
public class Comment
{
    [XmlAttribute(AttributeName = "number")]
    public string Number { get; set; }
    [XmlAttribute(AttributeName = "value")]
    public string Value { get; set; }
}

[XmlRoot(ElementName = "title_block")]
public class Title_block
{
    [XmlElement(ElementName = "title")]
    public string Title { get; set; }
    [XmlElement(ElementName = "company")]
    public string Company { get; set; }
    [XmlElement(ElementName = "rev")]
    public string Rev { get; set; }
    [XmlElement(ElementName = "date")]
    public string Date { get; set; }
    [XmlElement(ElementName = "source")]
    public string Source { get; set; }
    [XmlElement(ElementName = "comment")]
    public List<Comment> Comment { get; set; }
}

[XmlRoot(ElementName = "sheet")]
public class Sheet
{
    [XmlElement(ElementName = "title_block")]
    public Title_block Title_block { get; set; }
    [XmlAttribute(AttributeName = "number")]
    public string Number { get; set; }
    [XmlAttribute(AttributeName = "name")]
    public string Name { get; set; }
    [XmlAttribute(AttributeName = "tstamps")]
    public string Tstamps { get; set; }
}

代码

try
{
    XmlDocument xmlDoc = new XmlDocument();
    xmlDoc.Load("xml.xml");

    string XML = xmlDoc.InnerXml.ToString();
    byte[] BUFXML = ASCIIEncoding.UTF8.GetBytes(XML);
    MemoryStream ms1 = new MemoryStream(BUFXML);

    XmlSerializer DeserializerPlaces = new XmlSerializer(typeof(Sheet));
    using (XmlReader reader = new XmlTextReader(ms1))
    {
        Sheet dezerializedXML = (Sheet)DeserializerPlaces.Deserialize(reader);

    }// Put a break-point here, then mouse-over dezerializedXML and you should have you values
}
catch (System.Exception)
{
    throw;
}

此代码从一个文件（在应用程序 *.exe 文件夹中称为 xml.xml）中读取您的 xml，然后将其反序列化为一个名为 dezerializedXML 的对象....

C# XML 非嵌套序列化 arrays/list

C# XML Serialization un-nested arrays/list

c#

xml

xml-serialization