我怎样才能使用 scanf 来改变这个算法

Question

如何使用 Scanf 改变组合？

Write a program that prompts the user for a five digit lab access code, read it in as an unsigned integer then print to the screen each of the five digit access codes (with possible leading zeroes) that are equivalent (there are 32). Be aware that 1 and 2 are on the same button, as are 3 and 4, etc. 9 and 0 are on the same button, as well. The picture below is an example of a key access device that has 0 and 1 on the first button, 2 and 3 on the next button and so on.

0|_|{1,2}

1|_|{3,4}

2|_|{5,6}

3|_|{7,8}

4|_|{9,0}

#include <stdio.h>

int main(void) {
#define foreach( intpvar, intary ) int* intpvar; for( intpvar=intary; intpvar < (intary + (sizeof(intary)/sizeof(intary[0]))) ; intpvar++)
    int a1[]={1,2};
    int a2[]={3,4};
    int a3[]={5,6};
    int a4[]={7,8};
    int a5[]={9,0};
    foreach (p1, a1) {
        foreach (p2, a2) {
            foreach (p3, a3) {
                foreach (p4, a4) {
                    foreach (p5, a5) {
                         printf("%d %d %d %d %d\n",*p1,*p2,*p3,*p4, *p5);
                        }
                }
            }
        }
    }
    return 0;
}

Answer 1

since 5 sets of 2 only gives me 10 combinations.

不，它给你 2^5 = 32 种组合，因为你可以选择两个值之一，五次。假设代码是 13579 - 等效代码是：

所有这些代码都对应于按顺序按下五个按钮。总之：你的算法基本上是：

foreach option in group 0
  foreach option2 in group 1
     foreach option3 in group 2
       foreach option4 in group 3
         foreach option5 in group 4
           print option option2 option3 option4 option5

我怎样才能使用 scanf 来改变这个算法

How can I use scanf to alter this algorithm

algorithm

permutation

pseudocode

discrete-mathematics

0|_|{1,2}

1|_|{3,4}

2|_|{5,6}

3|_|{7,8}

4|_|{9,0}