使用 .open() 成员函数 C++ 的 ifstream 数组的错误访问代码

Question

我有一个相当简单的任务，其中我有两个包含 50 个名称的文本文件，我向用户查询文本文件 "girls names" 或 "boys name" 和一个名称，然后程序检查是否用户输入的名称在他们选择的文件中。我想我已经差不多明白了，但是当我试图打开第二个文件时，我得到了一个错误的访问代码。我读过有关内存分配的问题，我认为这是我的代码的问题，但答案超出了我的理解水平，所以我被困住了。

#include <iostream>
#include <fstream>
#include <string>

using namespace std;

int main() {

    // Declare Variables

    ifstream inFile[1]; // male and female file streams
    int inFileArrayVar = 0; // allows switching from female and male file streams
    string gender;
    string name[50];
    string inputName;
    int popular = 0;
    bool inputCondition = 1;
    bool progLoop = 1;

    // Welcome Message
    cout << "*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o" << '\n'
    << "    WELCOME TO THE GENDER BINARY MACHINE" << '\n'
    << "*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o*o" << '\n' << '\n'

    <<  "Enter a name and see if it is one of the most popular Canadian female or male names in 2015. " << '\n' << '\n';

    // Open Files

    inFile[0].open("GirlsNamesCanada2015.txt");
    inFile[1].open("BoysNamesCanada2015.txt");

    // User Query

    while (inputCondition == 1){

    cout << "Choose to query either the male or female database by entering 'f' or 'm' " << '\n';
    cin >> gender;

        if (gender == "f") {
            cout << "You have selected the female name database. Enter the name you'd like to search: " << '\n';
            inFileArrayVar = 0;
            inputCondition = 0;
        }
        else if (gender == "m"){
            cout << "You have selected the male name database. Enter the name you'd like to search: " << '\n';
            inFileArrayVar = 1;
            inputCondition = 0;
        }
        else
            inputCondition = 1;
    }

    while (progLoop == 1){

        cin >> inputName;

    for (int i = 0; i < 50; i++) {
        inFile[inFileArrayVar] >> name[i];
        if (inputName.compare(name[i]) == 0) {
            popular = 1;
            cout << inputName << " was one of the most popular names in 2015." << '\n' << '\n';
            i = 50;
        }
    }
            if (popular == 0){
                cout << inputName << " was not one of the most popular names is 2015." << '\n' << '\n';
            }

    cout << "If you want to contine, enter either 'f' or 'm', otherwise enter any other character. " << '\n';
        cin >> gender;


        if (gender == "f"){
            cout << "You have selected the female name database. Enter the name you'd like to search: " << '\n';
            inFileArrayVar = 0;
        }
        else if (gender == "m"){
            inFileArrayVar = 1;
            cout << "You have selected the male name database. Enter the name you'd like to search: " << '\n';
        }
        else
            progLoop = 0;


    }

    cout << "merci d'avoir choisi le GENDER BINARY MACHINE ******* pce out ******** " << '\n' << '\n';


    return 0;
}

Answer 1

ifstream inFile[1]; // male and female file streams

在这里，您声明了一个只有一个元素的数组。这个数组只有一个元素。这就是[1]的意思，这里

inFile[0].open("GirlsNamesCanada2015.txt");
inFile[1].open("BoysNamesCanada2015.txt");

然后您尝试访问数组中的元素 #0 和元素 #1，即这个元素数组中的第一个和第二个元素。可能会出什么问题？

声明数组时：

type array[n];

这意味着数组包含元素 #0 到元素 #n-1。

使用 .open() 成员函数 C++ 的 ifstream 数组的错误访问代码

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