使用 jquery 隐藏 td 标签的值
Hide the values of a td tag using jquery
这是我的 fiddle https://jsfiddle.net/tuc1faug/1/
在这里,我使用 jquery 为颜色分配了特定值。
每个颜色都会被打乱 time.Now 我希望这些值隐藏在单元格中,我希望所有这些值都按照打乱的顺序存储到数组中
Html:
<table border="5px" width="500px" height="50px" align="center">
<tr id="colors">
<td height="50px" orderId="1" bgcolor="red"></td>
<td height="50px" orderId="6" bgcolor="brown"></td>
<td height="50px" orderId="5" bgcolor="pink" ></td>
<td height="50px" orderId="0" bgcolor="blue" ></td>
<td height="50px" orderId="7" bgcolor="black"></td>
<td height="50px" orderId="2" bgcolor="green"></td>
<td height="50px" orderId="4" bgcolor="orange" ></td>
<td height="50px" orderId="3" bgcolor="yellow"></td>
</tr>
</table>
jQuery:
var arr=[];
var colorCells =document.getElementById('colors').getElementsByTagName('td');
var colors = ["blue","red","green","yellow","orange","pink","brown","black"];
for(var i = 0; i < colorCells.length; i++) {
$(colorCells[i]).attr("bgColor", colors.splice(Math.random() * (colors.length),1)) ;
arr.push(colorCells[i].style.backgroundColor);
}
var colorValues = {"red": 2, "blue":3, "green": 4, "yellow":"1", "orange":5, "black":1, "brown":6, "pink":5};
$("table td").each(function() {
$(this).html(colorValues[$(this).attr("bgColor")]);
});
添加 - $(this).text('');在循环的最后,比如:
var colorValues = {"red": 2, "blue":3, "green": 4, "yellow":"1", "orange":5, "black":1, "brown":6, "pink":5};
$("table td").each(function() {
$(this).html(colorValues[$(this).attr("bgColor")]);
$(this).text('');
});
它将删除 td 文本;
这是您需要的代码:
<script src="https://code.jquery.com/jquery-1.12.2.min.js"></script>
<script>
function shuffle(a) {
var j, x, i;
for (i = a.length; i; i -= 1) {
j = Math.floor(Math.random() * i);
x = a[i - 1];
a[i - 1] = a[j];
a[j] = x;
}
}
$(document).ready(function(){
var colors = ["blue", "red", "green", "yellow", "orange", "pink", "brown", "black"];
shuffle(colors);
for(var i=0;i<colors.length;i++) {
var td = $("#colors td").get(i);
$(td).html(colors[i]);
}
});
</script>
<table border="5px" width="500px" height="50px" align="center">
<tr id="colors">
<td height="50px"></td>
<td height="50px"></td>
<td height="50px"></td>
<td height="50px"></td>
<td height="50px"></td>
<td height="50px"></td>
<td height="50px"></td>
<td height="50px"></td>
</tr>
</table>
shuffle
函数来自这个答案:
用以下代码替换您的脚本。
td 中的值是隐藏的,并且存储在本地数组 tableContents
.
中
$(function() {
var arr=[];
var colorCells =document.getElementById('colors').getElementsByTagName('td');
var colors = ["blue","red","green","yellow","orange","pink","brown","black"];
for(var i = 0; i < colorCells.length; i++) {
$(colorCells[i]).attr("bgColor", colors.splice(Math.random() * (colors.length),1)) ;
arr.push(colorCells[i].style.backgroundColor);
}
var tableContents=[];
var colorValues = {"red": 2, "blue":3, "green": 4, "yellow":"1", "orange":5, "black":1, "brown":6, "pink":5};
$("table td").each(function() {
$(this).html(colorValues[$(this).attr("bgColor")]);
tableContents.push($(this).text());
$(this).text('');
})
});
我已经编辑了你的函数。如果我理解你的问题是正确的,你需要颜色的随机数应该存储在数组中并且你应该从显示中隐藏数字。
如果是,下面是代码
$(function() {
var arr=[];
// New array for adding the color number
var colorNumber = [];
var colorCells =document.getElementById('colors').getElementsByTagName('td');
var colors = ["blue","red","green","yellow","orange","pink","brown","black"];
for(var i = 0; i < colorCells.length; i++) {
var randomColor = Math.random() * (colors.length);
$(colorCells[i]).attr("bgColor", colors.splice(Math.random() * (colors.length),1)) ;
arr.push(colorCells[i].style.backgroundColor);
}
var colorValues = {"red": 2, "blue":3, "green": 4, "yellow": 7, "orange":5, "black":1, "brown":6, "pink":8};
$("table td").each(function() {
// Get the color value from the array and add it in colour numbers array.
colorNumber.push(colorValues[$(this).attr("bgColor")]);
// Hide it from display.
//$(this).html(colorValues[$(this).attr("bgColor")]);
});
// Your colorNumber array.
alert(colorNumber);
});
查看编辑后的 Fiddle。
这是我的 fiddle https://jsfiddle.net/tuc1faug/1/ 在这里,我使用 jquery 为颜色分配了特定值。 每个颜色都会被打乱 time.Now 我希望这些值隐藏在单元格中,我希望所有这些值都按照打乱的顺序存储到数组中 Html:
<table border="5px" width="500px" height="50px" align="center">
<tr id="colors">
<td height="50px" orderId="1" bgcolor="red"></td>
<td height="50px" orderId="6" bgcolor="brown"></td>
<td height="50px" orderId="5" bgcolor="pink" ></td>
<td height="50px" orderId="0" bgcolor="blue" ></td>
<td height="50px" orderId="7" bgcolor="black"></td>
<td height="50px" orderId="2" bgcolor="green"></td>
<td height="50px" orderId="4" bgcolor="orange" ></td>
<td height="50px" orderId="3" bgcolor="yellow"></td>
</tr>
</table>
jQuery:
var arr=[];
var colorCells =document.getElementById('colors').getElementsByTagName('td');
var colors = ["blue","red","green","yellow","orange","pink","brown","black"];
for(var i = 0; i < colorCells.length; i++) {
$(colorCells[i]).attr("bgColor", colors.splice(Math.random() * (colors.length),1)) ;
arr.push(colorCells[i].style.backgroundColor);
}
var colorValues = {"red": 2, "blue":3, "green": 4, "yellow":"1", "orange":5, "black":1, "brown":6, "pink":5};
$("table td").each(function() {
$(this).html(colorValues[$(this).attr("bgColor")]);
});
添加 - $(this).text('');在循环的最后,比如:
var colorValues = {"red": 2, "blue":3, "green": 4, "yellow":"1", "orange":5, "black":1, "brown":6, "pink":5};
$("table td").each(function() {
$(this).html(colorValues[$(this).attr("bgColor")]);
$(this).text('');
});
它将删除 td 文本;
这是您需要的代码:
<script src="https://code.jquery.com/jquery-1.12.2.min.js"></script>
<script>
function shuffle(a) {
var j, x, i;
for (i = a.length; i; i -= 1) {
j = Math.floor(Math.random() * i);
x = a[i - 1];
a[i - 1] = a[j];
a[j] = x;
}
}
$(document).ready(function(){
var colors = ["blue", "red", "green", "yellow", "orange", "pink", "brown", "black"];
shuffle(colors);
for(var i=0;i<colors.length;i++) {
var td = $("#colors td").get(i);
$(td).html(colors[i]);
}
});
</script>
<table border="5px" width="500px" height="50px" align="center">
<tr id="colors">
<td height="50px"></td>
<td height="50px"></td>
<td height="50px"></td>
<td height="50px"></td>
<td height="50px"></td>
<td height="50px"></td>
<td height="50px"></td>
<td height="50px"></td>
</tr>
</table>
shuffle
函数来自这个答案:
用以下代码替换您的脚本。
td 中的值是隐藏的,并且存储在本地数组 tableContents
.
$(function() {
var arr=[];
var colorCells =document.getElementById('colors').getElementsByTagName('td');
var colors = ["blue","red","green","yellow","orange","pink","brown","black"];
for(var i = 0; i < colorCells.length; i++) {
$(colorCells[i]).attr("bgColor", colors.splice(Math.random() * (colors.length),1)) ;
arr.push(colorCells[i].style.backgroundColor);
}
var tableContents=[];
var colorValues = {"red": 2, "blue":3, "green": 4, "yellow":"1", "orange":5, "black":1, "brown":6, "pink":5};
$("table td").each(function() {
$(this).html(colorValues[$(this).attr("bgColor")]);
tableContents.push($(this).text());
$(this).text('');
})
});
我已经编辑了你的函数。如果我理解你的问题是正确的,你需要颜色的随机数应该存储在数组中并且你应该从显示中隐藏数字。
如果是,下面是代码
$(function() {
var arr=[];
// New array for adding the color number
var colorNumber = [];
var colorCells =document.getElementById('colors').getElementsByTagName('td');
var colors = ["blue","red","green","yellow","orange","pink","brown","black"];
for(var i = 0; i < colorCells.length; i++) {
var randomColor = Math.random() * (colors.length);
$(colorCells[i]).attr("bgColor", colors.splice(Math.random() * (colors.length),1)) ;
arr.push(colorCells[i].style.backgroundColor);
}
var colorValues = {"red": 2, "blue":3, "green": 4, "yellow": 7, "orange":5, "black":1, "brown":6, "pink":8};
$("table td").each(function() {
// Get the color value from the array and add it in colour numbers array.
colorNumber.push(colorValues[$(this).attr("bgColor")]);
// Hide it from display.
//$(this).html(colorValues[$(this).attr("bgColor")]);
});
// Your colorNumber array.
alert(colorNumber);
});
查看编辑后的 Fiddle。