在 Erlang 中将字符串转换为元组
Converting string to tuple in Erlang
如何在 Erlang 中将字符串转换为元组?
A = "{"hi","how"}"
我想把它转换成
B = {"hi","how"}.
当我调用函数 list_to_tuple(A)
时,它给出输出:
{123,60,60,34,106,105,100,34,62,62,44,34,104,105,34,125}
而不是 {"hi","how"}
.
您应该使用 erl_scan module to tokenize the string and erl_parse 将标记转换为 erlang 术语。
% Note the '.' at the end of the expression inside string.
% The string has to be a valid expression terminated by a '.'.
1> Str = "{\"x\",\"y\"}.".
"{\"x\",\"y\"}."
2> {ok, Ts, _} = erl_scan:string(Str).
{ok,[{'{',1},
{string,1,"x"},
{',',1},
{string,1,"y"},
{'}',1},
{dot,1}],
1}
3> {ok, Tup} = erl_parse:parse_term(Ts).
{ok,{"x","y"}}
4> Tup.
{"x","y"}
如何在 Erlang 中将字符串转换为元组?
A = "{"hi","how"}"
我想把它转换成
B = {"hi","how"}.
当我调用函数 list_to_tuple(A)
时,它给出输出:
{123,60,60,34,106,105,100,34,62,62,44,34,104,105,34,125}
而不是 {"hi","how"}
.
您应该使用 erl_scan module to tokenize the string and erl_parse 将标记转换为 erlang 术语。
% Note the '.' at the end of the expression inside string.
% The string has to be a valid expression terminated by a '.'.
1> Str = "{\"x\",\"y\"}.".
"{\"x\",\"y\"}."
2> {ok, Ts, _} = erl_scan:string(Str).
{ok,[{'{',1},
{string,1,"x"},
{',',1},
{string,1,"y"},
{'}',1},
{dot,1}],
1}
3> {ok, Tup} = erl_parse:parse_term(Ts).
{ok,{"x","y"}}
4> Tup.
{"x","y"}