Oracle SQL 和 XML 选择事物作为 XML 类型
Oracle SQL and XML Selecting things as an XMLType
我有这个table
CREATE TABLE Test_T (
COL_1 VARCHAR(30),
COL_2 XMLTYPE
);
里面有这个
INSERT INTO Test_T VALUES ('one', XMLType('<?xml version="1.0" encoding="UTF-8"?>
<breakfast_menu>
<food>
<name>Belgian Waffles</name>
<price>.95</price>
<description>Two of our famous Belgian Waffles with plenty of real maple syrup</description>
<calories>650</calories>
</food>
<food>
<name>Strawberry Belgian Waffles</name>
<price>.95</price>
<description>Light Belgian waffles covered with strawberries and whipped cream</description>
<calories>900</calories>
</food>
<food>
<name>Berry-Berry Belgian Waffles</name>
<price>.95</price>
<description>Light Belgian waffles covered with an assortment of fresh berries and whipped cream</description>
<calories>900</calories>
</food>
<food>
<name>French Toast</name>
<price>.50</price>
<description>Thick slices made from our homemade sourdough bread</description>
<calories>600</calories>
</food>
<food>
<name>Homestyle Breakfast</name>
<price>.95</price>
<description>Two eggs, bacon or sausage, toast, and our ever-popular hash browns</description>
<calories>950</calories>
</food>
</breakfast_menu>
'));
我想从这个 table select Name And description
其中 name
包含 Belgian
我从这个 select 语句开始,但它似乎不起作用
SELECT XMLTYPE FROM Test_T WHERE ('/breakfast_menu/food[contains(name, 'Belgian')]');
谁能给我指出正确的方向?
您正在寻找 XMLTABLE
。
下面是 SQL 语句与您的 XML -
的对比
SELECT name, description
FROM test_t,
XMLTABLE (
'/breakfast_menu/food[contains(name,"Belgian")]'
PASSING test_t.col_2
COLUMNS name VARCHAR2 (100) PATH 'name',
description VARCHAR2 (100) PATH 'description');
写同样东西的另一种方法是 -
SELECT name, description
FROM test_t,
XMLTABLE (
'/breakfast_menu/food'
PASSING test_t.col_2
COLUMNS name VARCHAR2 (100) PATH 'name',
description VARCHAR2 (100) PATH 'description')
WHERE name LIKE '%Belgian%';
根据各种因素,其中一种可能更有效。您可以 运行 诊断并确定哪种过滤最适合您的数据。
我有这个table
CREATE TABLE Test_T (
COL_1 VARCHAR(30),
COL_2 XMLTYPE
);
里面有这个
INSERT INTO Test_T VALUES ('one', XMLType('<?xml version="1.0" encoding="UTF-8"?>
<breakfast_menu>
<food>
<name>Belgian Waffles</name>
<price>.95</price>
<description>Two of our famous Belgian Waffles with plenty of real maple syrup</description>
<calories>650</calories>
</food>
<food>
<name>Strawberry Belgian Waffles</name>
<price>.95</price>
<description>Light Belgian waffles covered with strawberries and whipped cream</description>
<calories>900</calories>
</food>
<food>
<name>Berry-Berry Belgian Waffles</name>
<price>.95</price>
<description>Light Belgian waffles covered with an assortment of fresh berries and whipped cream</description>
<calories>900</calories>
</food>
<food>
<name>French Toast</name>
<price>.50</price>
<description>Thick slices made from our homemade sourdough bread</description>
<calories>600</calories>
</food>
<food>
<name>Homestyle Breakfast</name>
<price>.95</price>
<description>Two eggs, bacon or sausage, toast, and our ever-popular hash browns</description>
<calories>950</calories>
</food>
</breakfast_menu>
'));
我想从这个 table select Name And description
其中 name
包含 Belgian
我从这个 select 语句开始,但它似乎不起作用
SELECT XMLTYPE FROM Test_T WHERE ('/breakfast_menu/food[contains(name, 'Belgian')]');
谁能给我指出正确的方向?
您正在寻找 XMLTABLE
。
下面是 SQL 语句与您的 XML -
的对比SELECT name, description
FROM test_t,
XMLTABLE (
'/breakfast_menu/food[contains(name,"Belgian")]'
PASSING test_t.col_2
COLUMNS name VARCHAR2 (100) PATH 'name',
description VARCHAR2 (100) PATH 'description');
写同样东西的另一种方法是 -
SELECT name, description
FROM test_t,
XMLTABLE (
'/breakfast_menu/food'
PASSING test_t.col_2
COLUMNS name VARCHAR2 (100) PATH 'name',
description VARCHAR2 (100) PATH 'description')
WHERE name LIKE '%Belgian%';
根据各种因素,其中一种可能更有效。您可以 运行 诊断并确定哪种过滤最适合您的数据。