改进 python csv 处理循环

Improve python csv processing loop

我有一个 csv 文件,我需要从中导出多列数据。第 4 列包含线名。每当此列中的值发生变化时,我正在导出的数据都需要写入一个新的单独文件。以下代码有效,但速度很慢。关于如何改进这一点的任何提示?

加法:数据样本:

Altitude,Date,Db,Depth,Linename,Qmag,TF,TF_HP,X,X_ob,X_org,Y,Y_ob,Y_org
10.87,10/2/2015,148,21.8342,10,1316,48831.936,0.060026123,506479.5515,506479.46,506479.46,5726744.3,5726743.73,5726743.73
10.84,10/2/2015,148,21.8342,11,1316,48831.969,0.092713686,506479.7927,506479.77,506479.77,5726744.443,5726744.2,5726744.2
10.85,10/2/2015,148,21.8669,11,1313,48832.014,0.137400275,506479.9672,506479.77,506479.77,5726744.741,5726744.2,5726744.2
10.82,10/2/2015,148,21.8342,12,1311,48831.969,0.092093953,506480.1677,506479.92,506479.92,5726744.945,5726744.44,5726744.44
10.83,10/2/2015,148,21.8669,12,1309,48831.969,0.091807708,506480.326,506480.08,506480.08,5726745.195,5726744.68,5726744.68

Python代码:

import glob,csv,os, itertools

list_of_files = glob.glob('C:/test/*.csv')

directory = 'C:/test/conv/'
if not os.path.exists(directory):
     os.makedirs(directory)

for filename in list_of_files:

    with open(filename,"r") as source:
        header_line = next(source)
        rdr= csv.reader( source, delimiter = ',',lineterminator='\n' )

        x=0

        for row in itertools.islice(rdr,0,None):
            itemRow4 = row[4]
            outfileName=directory+itemRow4+'.csv'

            with open(outfileName,"a") as result:

                wtr=csv.writer(result, lineterminator='\n')

                if x == 0:
                    previousitemRow4 = row[4]
                    x = x+1                 

                if previousitemRow4 == itemRow4: 
                    wtr.writerow((row[8],row[11],row[6],row[0]))
                    previousitemRow4 = itemRow4
                if previousitemRow4 != itemRow4:
                    wtr.writerow((row[8],row[11],row[6],row[0]))
                    print 'next line'
                    previousitemRow4 = itemRow4

使用标准 Unix shell 工具 cut, sort, uniq, and grep:

$ cut -d, -f5 < in.csv | sort | uniq | while read lineno
do
  grep ",${lineno}," in.csv > out-${lineno}.csv
done
$ ls out-*.csv
out-10.csv  out-11.csv  out-12.csv out-Linename.csv

可能 grep 表达式不够复杂,因为 lineno 可能出现在其他列中,但第 5 列除外。在这种情况下,可以使用一个简单的正则表达式使 grep 仅在第 5 列中找到 lineno。

根据Eumiro的建议,我想出了这个解决方案。我尝试使用列表词典,但无法正常工作。以下解决方案有效并且速度非常快。谢谢大家的帮助!

import glob,csv,os, itertools

list_of_files = glob.glob('C:/test/*.csv')
print 'By the Power of the Python, Split these here files!'  

directory = 'C:/test/conv/'
if not os.path.exists(directory):
    os.makedirs(directory)

for filename in list_of_files:
    storage = []
    specialStorage = []
    with open(filename,"r") as source:
        header_line = next(source)
        rdr= csv.reader( source, delimiter = ',',lineterminator='\n' )
        x=0
        resetValue = 0

        for row in itertools.islice(rdr,0,None):
            itemRow4 = row[4]

            if x == 0:
                previousitemRow4 = row[4]
                x = x+1

            outfileName=directory+previousitemRow4+'.csv'        

            if previousitemRow4 == itemRow4:                 

                storage.append((row[8],row[11],row[6],row[0]))
                previousitemRow4 = itemRow4

            if previousitemRow4 != itemRow4:

                with open(outfileName,"a") as result:

                    wtr=csv.writer(result, lineterminator='\n')
                    previousitemRow4 = itemRow4

                    if len(specialStorage) !=0:
                        wtr.writerow(specialStorage)
                    wtr.writerows(storage)
                    storage = []

                specialStorage=(row[8],row[11],row[6],row[0])

        else:
            with open(outfileName,"a") as result:

                    wtr=csv.writer(result, lineterminator='\n')
                    previousitemRow4 = itemRow4
                    wtr.writerow(specialStorage)
                    wtr.writerows(storage)
                    storage = []

            print 'end of file reached'