有一个数组到字符串的转换错误

Question

$conn = mysqli_connect("$host", "$username", "$password")or die("cannot connect"); 
mysqli_select_db($conn,"$db_name")or die("cannot select DB");

下面的代码试图获取 MYSQL table 并为 table 创建 headers 和列以在 pdf 页面上打印。

 $result=mysqli_query($conn,"select Employee_number,date_start,date_end,Days_taken,Sick,Study,Annual,compassionate_leave,Other,Details,Status,approved_by from $tbl_name ");

$number_of_products = mysqli_num_rows($result);

//Initialize the 3 columns and the total
$column_Employee_number = "";
$column_date_start = "";
$column_date_end = "";
$column_Days_taken = "";
$column_Sick = "";
$column_Study = "";
$column_Annual = "";
$column_compassionate_leave = "";
$column_Other = "";
$column_Details = "";
$column_Status = "";
$column_approved_by = "";

$total = 0;

//For each row, add the field to the corresponding column
while($row = mysqli_fetch_array($result))
{
    $Employee_number = $row["Employee_number"];
    $date_start = $row["date_start"];
    $date_end = $row["date_end"];
    $Days_taken = $row["Days_taken"];
    $Sick = $row["Sick"];
    $Study = $row["Study"];
    $Annual = $row["Annual"];
    $compassionate_leave = ["compassionate_leave"];
    $Other = $row["Other"];
    $Details = $row["Details"];
    $Status = $row["Status"];
    $Other = $row["Other"];
    $approved_by =$row["approved_by"];


   $column_Employee_number =$column_Employee_number.$Employee_number."\n";
   $column_date_start =  $column_date_start.$date_start."\n";
   $column_date_end = $column_date_end.$date_end."\n";
    $column_Days_taken = $column_Days_taken.$Days_taken."\n";
$column_Sick = $column_Sick.$Sick."\n";
$column_Study = $column_Study.$Study."\n";
$column_Annual = $column_Annual.$Annual."\n";
$column_compassionate_leave = $column_compassionate_leave.$compassionate_leave."\n";
$column_Other = $column_Other.$Other."\n";
$column_Details = $column_Details.$Details."\n";
$column_Status = $column_Status.$Status."\n";
$column_approved_by = $column_approved_by.$approved_by."\n";

}

从上面的代码我得到一个错误说

Notice: Array to string conversion in C:\xampp\htdocs\Namtax\leave_view.php on line 64

这是哪一行

$column_compassionate_leave = $column_compassionate_leave.$compassionate_leave."\n";

而且我似乎不明白为什么错误只显示那一行而不显示其他行以及如何解决它的任何帮助？

Answer 1

你有这个代码

 $compassionate_leave = ["compassionate_leave"];

其数组，改为

$compassionate_leave = $row["compassionate_leave"];

Answer 2

改变你的$compassionate_leave = ["compassionate_leave"];应该是$compassionate_leave = $row["compassionate_leave"];

Answer 3

$compassionate_leave = ["compassionate_leave"];

这一行将是

$compassionate_leave = $row["compassionate_leave"];

有一个数组到字符串的转换错误

having an array to string conversion error

php

mysql

pdf

fpdf