为 MemoryCache(或任何缓存)实现通用 Get<T>
Implement Generic Get<T> for MemoryCache (or any Cache)
我正在尝试编写 "simple" 通用 Get<T>
;扩展为
System.Runtime.MemoryCache
.
为什么 "simple"?因为通常我在缓存之前就知道对象的真实类型,所以当我从缓存中检索它时,我不会以不可预测的方式转换它。
例如:如果 boolean "true" 值以 cacheKey "id" 存储在缓存中,那么
Get<string>("id") == "true";
Get<int>("id") == 1; // any result > 0 is okay
Get<SomeUnpredictableType> == null; // just ignore these trouble conversions
这是我不完整的实现:
public static T DoGet<T>(this MemoryCache cache, string key) {
object value = cache.Get(key);
if (value == null) {
return default(T);
}
if (value is T) {
return (T)value;
}
// TODO: (I'm not sure if following logic is okay or not)
// 1. if T and value are both numeric type (e.g. long => double), how to code it?
// 2. if T is string, call something like Convert.ToString()
Type t = typeof(T);
t = (Nullable.GetUnderlyingType(t) ?? t);
if (typeof(IConvertible).IsAssignableFrom(value.GetType())) {
return (T)Convert.ChangeType(value, t);
}
return default(T);
}
非常感谢任何建议。
===================================
更新(2016 年 4 月 11 日):
对于给出的那些好的建议,我实现了我的第一个版本的 Get
public class MemCache {
private class LazyObject<T> : Lazy<T> {
public LazyObject(Func<T> valueFactory) : base(valueFactory) { }
public LazyObject(Func<T> valueFactory, LazyThreadSafetyMode mode) : base(valueFactory, mode) { }
}
private static T CastValue<T>(object value) {
if (value == null || value is DBNull) {
return default(T);
}
Type valType = value.GetType();
if (valType.IsGenericType && valType.GetGenericTypeDefinition() == typeof(LazyObject<>)) {
return CastValue<T>(valType.GetProperty("Value").GetValue(value));
}
if (value is T) {
return (T)value;
}
Type t = typeof(T);
t = (Nullable.GetUnderlyingType(t) ?? t);
if (typeof(IConvertible).IsAssignableFrom(t) && typeof(IConvertible).IsAssignableFrom(value.GetType())) {
return (T)Convert.ChangeType(value, t);
}
return default(T);
}
private MemoryCache m_cache;
public T Get<T>(string key) {
return CastValue<T>(m_cache.Get(key));
}
public void Set<T>(string key, T value, CacheDependency dependency) {
m_cache.Set(key, value, dependency.AsCacheItemPolicy());
}
public T GetOrAdd<T>(string key, Func<T> fnValueFactory, CacheDependency dependency) {
LazyObject<T> noo = new LazyObject<T>(fnValueFactory, LazyThreadSafetyMode.ExecutionAndPublication);
LazyObject<T> old = m_cache.AddOrGetExisting(key, noo, dependency.AsCacheItemPolicy()) as LazyObject<T>;
try {
return CastValue<T>((old ?? noo).Value);
} catch {
m_cache.Remove(key);
throw;
}
}
/* Remove/Trim ... */
}
提案:
public static T DoGet<T>(this MemoryCache cache, string key)
{
object value = cache.Get(key);
if (value == null) {
return default(T);
}
// support for nullables. Do not waste performance with
// type conversions if it is not a nullable.
var underlyingType = Nullable.GetUnderlyingType(t);
if (underlyingType != null)
{
value = Convert.ChangeType(value, underlyingType);
}
return (T)value;
}
用法(假设你在缓存中有一个int
类型的id):
int id = Get<int>("id");
int? mayBeId = Get<int?>("id");
string idAsString = Get<int?>("id")?.ToString();
double idAsDouble = (double)Get<int>("id");
我没有测试过。
基本工作是编写 CastValue 以将任何对象转换为所需类型。而且它不必处理非常复杂的情况,因为缓存中的对象类型对于程序员来说是可预测的。这是我的版本。
public static T CastValue<T>(object value) {
if (value == null || value is DBNull) {
return default(T);
}
if (value is T) {
return (T)value;
}
Type t = typeof(T);
t = (Nullable.GetUnderlyingType(t) ?? t);
if (typeof(IConvertible).IsAssignableFrom(t) && typeof(IConvertible).IsAssignableFrom(value.GetType())) {
return (T)Convert.ChangeType(value, t);
}
return default(T);
}
我正在尝试编写 "simple" 通用 Get<T>
;扩展为
System.Runtime.MemoryCache
.
为什么 "simple"?因为通常我在缓存之前就知道对象的真实类型,所以当我从缓存中检索它时,我不会以不可预测的方式转换它。
例如:如果 boolean "true" 值以 cacheKey "id" 存储在缓存中,那么
Get<string>("id") == "true";
Get<int>("id") == 1; // any result > 0 is okay
Get<SomeUnpredictableType> == null; // just ignore these trouble conversions
这是我不完整的实现:
public static T DoGet<T>(this MemoryCache cache, string key) {
object value = cache.Get(key);
if (value == null) {
return default(T);
}
if (value is T) {
return (T)value;
}
// TODO: (I'm not sure if following logic is okay or not)
// 1. if T and value are both numeric type (e.g. long => double), how to code it?
// 2. if T is string, call something like Convert.ToString()
Type t = typeof(T);
t = (Nullable.GetUnderlyingType(t) ?? t);
if (typeof(IConvertible).IsAssignableFrom(value.GetType())) {
return (T)Convert.ChangeType(value, t);
}
return default(T);
}
非常感谢任何建议。
===================================
更新(2016 年 4 月 11 日):
对于给出的那些好的建议,我实现了我的第一个版本的 Get
public class MemCache {
private class LazyObject<T> : Lazy<T> {
public LazyObject(Func<T> valueFactory) : base(valueFactory) { }
public LazyObject(Func<T> valueFactory, LazyThreadSafetyMode mode) : base(valueFactory, mode) { }
}
private static T CastValue<T>(object value) {
if (value == null || value is DBNull) {
return default(T);
}
Type valType = value.GetType();
if (valType.IsGenericType && valType.GetGenericTypeDefinition() == typeof(LazyObject<>)) {
return CastValue<T>(valType.GetProperty("Value").GetValue(value));
}
if (value is T) {
return (T)value;
}
Type t = typeof(T);
t = (Nullable.GetUnderlyingType(t) ?? t);
if (typeof(IConvertible).IsAssignableFrom(t) && typeof(IConvertible).IsAssignableFrom(value.GetType())) {
return (T)Convert.ChangeType(value, t);
}
return default(T);
}
private MemoryCache m_cache;
public T Get<T>(string key) {
return CastValue<T>(m_cache.Get(key));
}
public void Set<T>(string key, T value, CacheDependency dependency) {
m_cache.Set(key, value, dependency.AsCacheItemPolicy());
}
public T GetOrAdd<T>(string key, Func<T> fnValueFactory, CacheDependency dependency) {
LazyObject<T> noo = new LazyObject<T>(fnValueFactory, LazyThreadSafetyMode.ExecutionAndPublication);
LazyObject<T> old = m_cache.AddOrGetExisting(key, noo, dependency.AsCacheItemPolicy()) as LazyObject<T>;
try {
return CastValue<T>((old ?? noo).Value);
} catch {
m_cache.Remove(key);
throw;
}
}
/* Remove/Trim ... */
}
提案:
public static T DoGet<T>(this MemoryCache cache, string key)
{
object value = cache.Get(key);
if (value == null) {
return default(T);
}
// support for nullables. Do not waste performance with
// type conversions if it is not a nullable.
var underlyingType = Nullable.GetUnderlyingType(t);
if (underlyingType != null)
{
value = Convert.ChangeType(value, underlyingType);
}
return (T)value;
}
用法(假设你在缓存中有一个int
类型的id):
int id = Get<int>("id");
int? mayBeId = Get<int?>("id");
string idAsString = Get<int?>("id")?.ToString();
double idAsDouble = (double)Get<int>("id");
我没有测试过。
基本工作是编写 CastValue
public static T CastValue<T>(object value) {
if (value == null || value is DBNull) {
return default(T);
}
if (value is T) {
return (T)value;
}
Type t = typeof(T);
t = (Nullable.GetUnderlyingType(t) ?? t);
if (typeof(IConvertible).IsAssignableFrom(t) && typeof(IConvertible).IsAssignableFrom(value.GetType())) {
return (T)Convert.ChangeType(value, t);
}
return default(T);
}