Python：如何生成一个随机的phone数？

Question

不是 Making random phone number xxx-xxx-xxxx

的副本

我的项目使用 python-phonenumbers and django-phonenumber-field 进行 phone 数字验证。在项目中有大量自定义验证规则，像这样的天真方法是不够的：

>>> import functools
>>> import random
>>> a = functools.partial(random.randint, 0, 9)
>>> gen = lambda: "+{}-{}{}{}-{}{}{}-{}{}{}{}".format(a(), a(), a(), a(), a(), a(), a(), a(), a(), a(), a())
>>> gen()
'+2-758-702-0180'  # Obviously wrong
>>> gen()
'+1-911-555-0180'  # Obviously wrong, it has 911 in it

因此，在不求助于没有上限的强力 while 循环，并且不为此类微不足道的问题引入上限的情况下，有什么更好的方法来生成有效的 phone 数字接受验证者本身？

from phonenumber_field.validators import validate_international_phonenumber
from django.core.exceptions import ValidationError

def generate_valid_number():
    while True:  # While loops are not desired, even with an upper bound!
        try:
            number = gen()
            validate_international_phonenumber(number)
            return number
        except ValidationError:
            pass

Answer 1

我认为 davidn 给 this question 的答案应该有效，尤其是因为您已经在使用 python-phonenumbers

I would recommend to use the phonenumbers package which is a python port of Google's libphonenumber which includes a data set of mobile carriers now:
import phonenumbers 
from phonenumbers import carrier
from phonenumbers.phonenumberutil import number_type

number = "+49 176 1234 5678"
carrier._is_mobile(number_type(phonenumbers.parse(number))) 
This will return True in case number is a mobile number or False otherwise. Note that the number must be a valid international number or an exception will be thrown. You can also use phonenumbers to parse phonenumber given a region hint.

Answer 2

如果您使用的是包 faker，您可以编写一个可以在您的项目中重复使用的自定义提供程序。

import phonenumbers
from faker.providers.phone_number.en_US import Provider

class CustomPhoneProvider(Provider):
    def phone_number(self):
        while True:
            phone_number = self.numerify(self.random_element(self.formats))
            parsed_number = phonenumbers.parse(phone_number, 'US')
            if phonenumbers.is_valid_number(parsed_number):
                return phonenumbers.format_number(
                    parsed_number,
                    phonenumbers.PhoneNumberFormat.E164
                )

与factory_boy一起使用：

import factory
from faker import Faker

from .models import User
from .providers import CustomPhoneProvider

fake = Faker()
fake.add_provider(CustomPhoneProvider)

class UserFactory(factory.DjangoModelFactory):
    class Meta:
        model = User

    first_name = factory.Faker('first_name')
    last_name = factory.Faker('last_name')
    phone_number = factory.LazyAttribute(lambda _: fake.phone_number())

Python：如何生成一个随机的phone数？

Python: How to generate a random phone number?

python

phone-number