如何用两个textview和一个toggle Button创建Listview?

How to create Listview with two textview and one toggle Button?

我创建了带有两个文本视图作为名称的列表视图,phone 没有。和这个切换按钮的前面。当我点击切换按钮时,我应该得到名字。但它给出了错误

'02-17 06:49:53.170: E/AndroidRuntime(1425): java.lang.ClassCastException: android.widget.TextView cannot be cast to android.widget.ToggleButton 02-17 06:49:53.170: E/AndroidRuntime(1425): at com.example.comparearray.MainActivity.onItemClick(MainActivity.java:85) 02-17 06:49:53.170: E/AndroidRuntime(1425): at android.widget.AdapterView.performItemClick(AdapterView.java:299) 02-17 06:49:53.170: E/AndroidRuntime(1425): at android.widget.AbsListView.performItemClick(AbsListView.java:1113) 02-17 06:49:53.170: E/AndroidRuntime(1425): at android.widget.AbsListView$PerformClick.run(AbsListView.java:2904) 02-17 06:49:53.170: E/AndroidRuntime(1425): at android.widget.AbsListView.run(AbsListView.java:3638) 02-17 06:49:53.170: E/AndroidRuntime(1425): at android.os.Handler.handleCallback(Handler.java:733) 02-17 06:49:53.170: E/AndroidRuntime(1425): at android.os.Handler.dispatchMessage(Handler.java:95) 02-17 06:49:53.170: E/AndroidRuntime(1425): at android.os.Looper.loop(Looper.java:136) 02-17 06:49:53.170: E/AndroidRuntime(1425): at android.app.ActivityThread.main(ActivityThread.java:5017) 02-17 06:49:53.170: E/AndroidRuntime(1425): at java.lang.reflect.Method.invokeNative(Native Method) 02-17 06:49:53.170: E/AndroidRuntime(1425): at java.lang.reflect.Method.invoke(Method.java:515) 02-17 06:49:53.170: E/AndroidRuntime(1425): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:779) 02-17 06:49:53.170: E/AndroidRuntime(1425): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:595) 02-17 06:49:53.170: E/AndroidRuntime(1425): at dalvik.system.NativeStart.main(Native Method)

下面是我的代码

 lvCountries = (ListView) findViewById(R.id.lv_countries);

OnItemClickListener itemClickListener = new OnItemClickListener() {
 @Override

public void onItemClick(AdapterView<?> lv, View item, int position, long id) {

     ListView lView = (ListView) lv;

     SimpleAdapter adapter = (SimpleAdapter) lView.getAdapter();

     HashMap<String,Object> hm = (HashMap) adapter.getItem(position);

     /** The clicked Item in the ListView */
     RelativeLayout rLayout = (RelativeLayout) item;

     /** Getting the toggle button corresponding to the clicked item */
    ToggleButton tgl = (ToggleButton) rLayout.getChildAt(1);


     String strStatus = "";
     if(tgl.isChecked()){
         tgl.setChecked(false);
         strStatus = "Off";
         status[position]=false;
     }else{
         tgl.setChecked(true);
         strStatus = "On";
         status[position]=true;
     }
     Toast.makeText(getBaseContext(), (String) hm.get("txt") + " : " + strStatus, Toast.LENGTH_SHORT).show();
 }

};

lvCountries.setOnItemClickListener(itemClickListener);

请帮助我,我被困在这里了。

它清楚地表明您正在尝试在切换按钮中投射 textview,因此请首先检查布局中的切换位置。这里的索引 1 上有 textview rLayout.getChildAt(1); .

不使用静态索引从选定的行布局中获取 ToggleButton,而是使用 instanceof 检查视图是 ToggleButton 还是 TextView:

RelativeLayout rLayout = (RelativeLayout) arg1;
for (int index = 0; index < rLayout.getChildCount(); index++) {
     View view=rLayout.getChildAt(index);
     if(view instanceof ToggleButton){      
        ToggleButton tgl = (ToggleButton)view;       
         //... do task here...
        break;
     }
}

错误显示 "TextView cannot be cast to android.widget.ToggleButton",因此,方法“rLayout.getChildAt(1)”显然不适合您。 你可以在 XML 中设置 id,然后从你的 "rLayout".

中找到它

更改以下行

ToggleButton tgl = (ToggleButton) rLayout.getChildAt(1);

ToggleButton tgl = (ToggleButton) rLayout.getChildAt(2);

注意:如果不起作用,请清理您的项目并重试。

希望对您有所帮助。

您正在将 TextView 转换为 ToggleButton。问题出在这一行:

ToggleButton tgl = (ToggleButton) rLayout.getChildAt(1);

出于某种原因,1 处的子项是 TextView 而不是预期的 ToggleButton。

我鼓励您使用 findViewById 而不是 getChildAt,这样您可以通过 ID 而不是在布局中的位置找到它们。它将避免这些与小部件顺序相关的错误。