Python：如何在00:00和23:59获取第二天的unix时间戳？

Question

我的代码中有一个这样的矩阵，带有 unix 时间戳：

event_sequences = [ 
  [1368136883, 1368137089], #The first event is never empty
  [1368214777, 1368214966],
  [],
    .... There are the perfect number of days (empty arrays) in the gaps between the existing events.
  [],
  [1368747495, 1368747833],
  [1368830501, 1368831869]
]

对于 event_sequences 中的每个事件，我知道它的开始和结束（开始 = event_sequences[n][0] 和结束 = event_sequences[n][1]）。如您所见，有些事件是空的，我必须采取的方法是将这些空事件的开始和结束设置为最后一个事件记录后的第二天的 00:00 和 23:59 .喜欢

[ 
 [start, end],
 [start, end],
 [the day after the last event at 00:00, the day after the last event at 23:59]
]

空事件的开始和结束也需要是unix时间戳。我怎样才能在 python 中做到这一点？

Answer 1

以下应该可以解决问题。不过，有一些 questions/things 需要注意：

如果 event_sequences 中的第一个元素是一个空列表
event_sequences 中的天数应该有间隔吗？例如，您将在下面的输出中看到在 5/12/2013 和 5/16/2013 之间的序列中存在间隙，即使在填充空白条目之后也是如此。
如果您有两个连续的空白条目，我假设您希望第二个空白条目是第一个空白条目之后的第二天

代码：

from datetime import datetime, timedelta
import time

event_sequences = [
  [1368136883, 1368137089],
  [1368214777, 1368214966],
  [],
  [],
  [1368747495, 1368747833],
  [1368830501, 1368831869]
]

#take the last_day recorded date as a datetime object from the event_sequences and return a 2-element list
#with the unix timestamps for 00:00 and 23:59
def getNextDay(last_day):
    next_day = last_day + timedelta(days=1)
    next_day_start = next_day.replace(hour=0,minute=0,second=0)
    next_day_end = next_day.replace(hour=23,minute=59,second=0)
    return [int(next_day_start.strftime("%s")), int(next_day_end.strftime("%s"))]

def fillEmptyDates(event_list):
    new_event_list = []
    #note: this will fail if the first element in the list of event_sequences is blank
    last_day = int(time.time())
    for x in event_sequences:
        if len(x) == 0:
            next_day = getNextDay(last_day)
            last_day = datetime.utcfromtimestamp(next_day[1])
        else:
            next_day = x
        last_day = datetime.utcfromtimestamp(next_day[1])
        new_event_list.append(next_day)
    return new_event_list  

new_event_sequence = fillEmptyDates(event_sequences)

print new_event_sequence

#[[1368136883, 1368137089], [1368214777, 1368214966], [1368230400, 1368316740], [1368316800, 1368403140], [1368747495, 1368747833], [1368830501, 1368831869]]

for event in new_event_sequence:
    print str(datetime.utcfromtimestamp(event[0]))+ ' and '+str(datetime.utcfromtimestamp(event[1]))

#2013-05-09 22:01:23 and 2013-05-09 22:04:49
#2013-05-10 19:39:37 and 2013-05-10 19:42:46
#2013-05-11 00:00:00 and 2013-05-11 23:59:00
#2013-05-12 00:00:00 and 2013-05-12 23:59:00
#2013-05-16 23:38:15 and 2013-05-16 23:43:53
#2013-05-17 22:41:41 and 2013-05-17 23:04:29

Python：如何在00:00和23:59获取第二天的unix时间戳？

Python: How to get the next day of unix timestamps at 00:00 and 23:59?

python

timestamp

unix-timestamp