将列表列表导出到 XML，反之亦然

Question

我正在尝试为我的 Visual C# 程序实现一个 "Open/Save" 函数。我需要保存的对象是列表列表。更具体地说，它是一个 List<List<Components>>，其中 Components 是我的习惯 class。我设法导出它并使用 XML reader 读取我的变量，但是当我将它导入回程序时，我得到了错误的变量。比如导出前的列表容量是2，导入后变成了4，有帮助吗？
如果您可以建议 "Open/Save" 功能的另一种方式，请随意。我只需要将自定义 class 的列表存储和恢复到一个文件中。

public void open_click(object send, EventArgs e)
        {
            XmlSerializer xml = new XmlSerializer(typeof(List<List<Components>>));
            OpenFileDialog oDialog = new OpenFileDialog();

            oDialog.Filter = "XML|*.xml";

            if (oDialog.ShowDialog() == DialogResult.OK)
            {
                Variables.compBuffer = new List<List<Components>>();
                using (FileStream s = File.OpenRead(oDialog.FileName))
                using (StreamReader sw = new StreamReader(s))
                {
                    Variables.compBuffer = (List<List<Components>>)xml.Deserialize(s);
                }
            }
        }

//

public void saveAs_click(object send, EventArgs e)
{
    XmlSerializer xml = new XmlSerializer(typeof(List<List<Components>>));
    SaveFileDialog sDialog = new SaveFileDialog();

    sDialog.FileName = "myLadder";
    sDialog.Filter = "XML|*.xml";
    sDialog.OverwritePrompt = true;

    if (sDialog.ShowDialog() == DialogResult.OK)
    {
        using (FileStream s = File.OpenWrite(sDialog.FileName))
        using (StreamWriter sw = new StreamWriter(s))
        {
            xml.Serialize(s, Variables.compBuffer);
        }
    }
}

//

    public class Components
    {
        //Private variables
        private string _type = "empty";
        private string _name = "";
        private int _time = 0;    //If it's a "timer" (in ms)
        private int _index = -1;
        private string _comment = "";
        private bool _output = false;

        public Components() { }

        public string Type
        {
            get { return this._type; }
            set { this._type = value; }
        }
        public string Name
        {
            get { return this._name; }
            set { this._name = value; }
        }
        public int Time
        {
            get { return this._time; }
            set { this._time = value; }
        }
        public int Index
        {
            get { return this._index; }
            set { this._index = value; }
        }
        public string Comment
        {
            get { return this._comment; }
            set { this._comment = value; }
        }
        public bool Output
        {
            get { return this._output; }
            set { this._output = value; }
        }

        public void reset()
        {
            _type = "empty";
            _name = "";
            _time = 0;               //If it's a "timer" (in ms)
            _index = -1;
            _comment = "";
            _output = false;
        }
    }
}

Answer 1

由于您没有研究 xml 特定的解决方案，我只是将其作为二进制表示形式序列化到一个文件中，然后将其恢复：

    using System.IO;

    [Serializable]    
    public class Components
    {
       ...
    }

    var components = new List<Components>();
    string pathToFile = @"c:\dev\components.bin";

    SerializeFile(pathToFile, components);
    var fetchComponents = DeserializeFile(pathToFile);

    private void SerializeFile(string file, IList<Components> data)
    {
        using (Stream stream = File.Open(file, FileMode.Create))
        {
           var formatter = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();
           formatter.Serialize(stream, data);
        }
    }

    private IList<Components> DeserializeFile(string file)
    {
        using (Stream stream = File.Open(file, FileMode.Create))
        {
            var formatter = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();
            return (List<Components>)formatter.Deserialize(stream);
        }
    }

此解决方案的缺点是您无法查看文件和浏览数据。进一步的改进是使用泛型，这样您就可以 serialize/deserialize 任何类型的数据。

不要忘记用 [Serializable]

属性标记您要保存的 class

将列表列表导出到 XML，反之亦然

Export list of list to XML and vice-versa

c#

nested

export

list

xml-serialization