类型 'AnyObject' 不符合协议 'sequenceType'

Question

所以这是我的代码，我在以下行中收到错误，说 "Type 'AnyObject' does not conform protocol 'sequenceType'":

for bar in allBars {

我尝试了此处提出的解决方案 (Type 'AnyObject' does not conform to protocol 'SequenceType')，但它导致 Xcode 出现错误

我对 IOS 很陌生，所以这可能是一些愚蠢的东西

func loadBars(){
    let path = NSBundle.mainBundle().pathForResource("donnes", ofType: "json")
    let filename: String = "donnees.json"

    do{
        let data = try NSData(contentsOfFile: path!, options: NSDataReadingOptions.DataReadingMapped)
        do{
            let bars: AnyObject? = try NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions())
            if let bars = bars as? Dictionary<String, AnyObject> {
                print(bars)

                let allBars = bars["bars"]

                for bar in allBars {

                    let nouveauBar = Bar(id: bar["id"], name: bar["name"], adress: bar["adress"], url: bar["url"], image_url: bar["image_url"], tags: bar["tags"], longitude: bar["longitude"], latitude: bar["latitude"])

                    bars += nouveauBar
                }

            } else {
                print("Level file '\(filename)' is not valid JSON")
            }
        }catch {
            print("Level file '\(filename)' is not valid JSON: \(error)")
        }


    }catch {
        print("Could not load level file: \(filename), error: \(error)")
    }

}

这里是 .json 文件的开头：

{
"code": 200,
"bars": [{
    "id": 1627,
    "address": "100 Rue Saint-Martin, 75004 Paris, France, Opera and Les Halles, Paris",
    "name": "Caf\u00e9 Beaubourg",
    "url": "/bar/paris/opera-and-les-halles/cafe-beaubourg",
    "image_url": "https://prh-wbb-prod.s3.amazonaws.com/generic_640_480/WBB%20holding%20image3_54abcf7d218d1_55b8d2128eabb.jpg",
    "tags": "Bar, Gay, Cafe, Dinner, Lunch",
    "latitude": 48.860033826521,
    "longitude": 2.3508920416641
}, {
    "id": 1259,
    "address": "19 Rue Beaubourg, 75004 Paris, France, Bastille and the Marais, Paris",
    "name": "Georges",
    "url": "/bar/paris/bastille-and-the-marais/georges",
    "image_url": "https://prh-wbb-prod.s3.amazonaws.com/generic_640_480/WBB%20holding%20image4_54abcf6d1f68d_55b8d2015bb13.jpg",
    "tags": "Serves Food, Great View, Rooftop, Terrace, Rock",
    "latitude": 48.8603,
    "longitude": 2.35097
}]

}

Answer 1

而不是

if let bars = bars as? Dictionary<String, AnyObject> {

你可以写

if let bars = bars as? [String: AnyObject],
    let allBars = bars["bars"] as? [[String: AnyObject]] {

这已经为您提供了 allBars 数组。然后编译器知道 allBars 中的每个 bar 将具有类型 [String: AnyObject]（Dictionary<String, AnyObject> 的缩写），这允许您将 bar 用作字典。您仍然需要解包 id 和 name 等属性，您可以像我上面的代码那样执行此操作。

类型 'AnyObject' 不符合协议 'sequenceType'

Type 'AnyObject' does not conform protocol 'sequenceType'

xcode

ios

swift

anyobject