如何延迟 swift 逐个显示子视图

Question

首先，我刚刚开始 swift 的工作。

我正在 for 循环中创建图像视图，并尝试通过一些延迟逐一显示它们。我试图在 viewDidAppear 函数中实现这一点，但是所有图像视图都显示在一起，没有任何延迟，即使我使用以下函数：

func delay(delay:Double, closure:()->()) {
    dispatch_after(
        dispatch_time(
            DISPATCH_TIME_NOW,
            Int64(delay * Double(NSEC_PER_SEC))
        ),
        dispatch_get_main_queue(), closure)
}

var i = 1

    var backgroundQueue:dispatch_queue_t =  dispatch_queue_create("SerialQueue", DISPATCH_QUEUE_SERIAL)

    for award in (awards){

        //dispatch_async(backgroundQueue, { () -> () in

            var awardView = AwardView(imageName: award, sideLength: awardSize)

            var pointX: CGFloat = xOffset + CGFloat(i-1) * (awardSize + COIN_MARGIN)
            var pointY: CGFloat = yOffset

            awardView.center = CGPointMake( pointX, pointY)

            //dispatch_async(dispatch_get_main_queue(), { () -> () in

                self.pointsContainerView.addSubview(awardView)

                audioController.playEffect(SOUND_DING)
            //})

        //});

        i++
    }

我不确定我是否在尝试以正确的方式执行此操作 (viewDidAppear)。

在此先感谢您的帮助。

Answer 1

我想你想按顺序加载子视图。这会在后台连续运行线程，一旦它获得 UIView，它就会更新屏幕并等待一秒钟，然后再加载下一个 UIView。你可以试试这个方法希望对你有帮助

var awards:NSArray=NSArray(objects: "1.jpg","2.jpg","3.jpg")
    var x:CGFloat=10.00
    var y:CGFloat=100.00
    var backgroundQueue:dispatch_queue_t =  dispatch_queue_create("SerialQueue", DISPATCH_QUEUE_SERIAL)
    for award in awards{
    dispatch_async(backgroundQueue, { () -> () in
        // do some task

        dispatch_async(dispatch_get_main_queue(), { () -> () in

            var image:UIImage=UIImage(named: award as String)!
            var awardView :UIImageView = UIImageView(image:image)
            awardView.frame=CGRectMake(x, y, 300, 400);
            self.view.addSubview(awardView);
             x=x+310.00;

        })
        sleep(1);

    });

}

如何延迟 swift 逐个显示子视图

How to show subviews one by one with delay on swift

delay

imageview

ios

swift