SQL FOR XML 嵌套行列表

Question

我有这个超长的 SQL 查询，现在这个查询所做的如下，创建第一级，即 Job_No...第二级的下一个获得所有'BaselineStart' 然而，这将每个 BaselineStart 与 baseOrSchedStartList 分开，我想要做的是为每个 Job_No 设置 1 个 baseOrSchedStartList，并在 baseOrSchedStartList 下设置每个 'string'。我希望这是有道理的。这是我的查询：

SELECT [Job_No] as '@Key',
(
        SELECT ISNULL(UserDate1,ScheduleTasks.BaselineStart) AS 'string' 

        FROM ScheduleTasks INNER JOIN Schedule ON ScheduleTasks.ScheduleID = Schedule.ScheduleID INNER JOIN V_CONSTAT_ACTUAL_DATES ON V_CONSTAT_ACTUAL_DATES.JOB_NUMBER = Schedule.Job_No WHERE Job_No IN (SELECT JOB_NUMBER
                        FROM V_CONSTAT_ACTUAL_DATES
                        WHERE AREA_DESC = 'Orchard Park'
                        AND (DATE_TO_END IS NOT NULL AND DATE_TO_END >= GETDATE())) AND
               (
                        LibraryTaskID <> 203
                        AND LibraryTaskID <> 204
                        AND LibraryTaskID <> 210
                        AND LibraryTaskID <> 211
                        AND LibraryTaskID <> 214
                        AND LibraryTaskID <> 215
                        AND LibraryTaskID <> 218
                        AND LibraryTaskID <> 219
                        AND LibraryTaskID <> 224
                        AND LibraryTaskID <> 227
                        AND LibraryTaskID <> 230
                        AND LibraryTaskID <> 231
                        AND LibraryTaskID <> 232
                        AND LibraryTaskID <> 233
                        AND LibraryTaskID <> 234
                        AND LibraryTaskID <> 235
                        AND LibraryTaskID <> 236
                        AND LibraryTaskID <> 237        
                        AND LibraryTaskID <> 238
                        AND LibraryTaskID <> 239
                        AND LibraryTaskID <> 240
                        AND LibraryTaskID <> 242
                        AND LibraryTaskID <> 243
                        AND LibraryTaskID <> 295
                        AND LibraryTaskID <> 299
                        AND LibraryTaskID <> 303
                        AND LibraryTaskID <> 304
                        AND LibraryTaskID <> 305
                        AND LibraryTaskID <> 313
                        AND LibraryTaskID <> 314
                        AND LibraryTaskID <> 321
                        AND LibraryTaskID <> 333

               )

            ORDER BY DATE_TO_END, SortOrder
            FOR XML PATH('baseOrSchedStartList'), Type
)
FROM ScheduleTasks INNER JOIN Schedule ON ScheduleTasks.ScheduleID = Schedule.ScheduleID INNER JOIN V_CONSTAT_ACTUAL_DATES ON V_CONSTAT_ACTUAL_DATES.JOB_NUMBER = Schedule.Job_No WHERE Job_No IN (SELECT JOB_NUMBER
                        FROM V_CONSTAT_ACTUAL_DATES
                        WHERE AREA_DESC = 'Orchard Park'
                        AND (DATE_TO_END IS NOT NULL AND DATE_TO_END >= GETDATE())) AND
               (
                        LibraryTaskID <> 203
                        AND LibraryTaskID <> 204
                        AND LibraryTaskID <> 210
                        AND LibraryTaskID <> 211
                        AND LibraryTaskID <> 214
                        AND LibraryTaskID <> 215
                        AND LibraryTaskID <> 218
                        AND LibraryTaskID <> 219
                        AND LibraryTaskID <> 224
                        AND LibraryTaskID <> 227
                        AND LibraryTaskID <> 230
                        AND LibraryTaskID <> 231
                        AND LibraryTaskID <> 232
                        AND LibraryTaskID <> 233
                        AND LibraryTaskID <> 234
                        AND LibraryTaskID <> 235
                        AND LibraryTaskID <> 236
                        AND LibraryTaskID <> 237        
                        AND LibraryTaskID <> 238
                        AND LibraryTaskID <> 239
                        AND LibraryTaskID <> 240
                        AND LibraryTaskID <> 242
                        AND LibraryTaskID <> 243
                        AND LibraryTaskID <> 295
                        AND LibraryTaskID <> 299
                        AND LibraryTaskID <> 303
                        AND LibraryTaskID <> 304
                        AND LibraryTaskID <> 305
                        AND LibraryTaskID <> 313
                        AND LibraryTaskID <> 314
                        AND LibraryTaskID <> 321
                        AND LibraryTaskID <> 333

               )
               GROUP BY [Job_No]
               FOR XML PATH('Job_No'), ROOT('Root')

此查询returns此数据：

<Root>
  <Job_No Key="ORC0023">
    <baseOrSchedStartList>
      <string>2015-09-11T08:00:00</string>
    </baseOrSchedStartList>
    <baseOrSchedStartList>
      <string>2015-08-10T16:00:00</string>
    </baseOrSchedStartList>
    <baseOrSchedStartList>
      <string>2015-08-11T16:00:00</string>
    </baseOrSchedStartList>
  </Job_No>
</Root>

我要找的是：

<Root>
  <Job_No Key="ORC0023">
    <baseOrSchedStartList>
      <string>2015-09-11T08:00:00</string>
      <string>2015-08-10T16:00:00</string>
      <string>2015-08-11T16:00:00</string>
    </baseOrSchedStartList>
  </Job_No>
</Root>

如有任何帮助，我们将不胜感激。

Answer 1

UPDATE 根据您的

如果你只是从 AS [@Key] 中拿走 @ 你会得到这个

DECLARE @tbl TABLE([Key] VARCHAR(10),DateValue DATETIME);
INSERT INTO @tbl VALUES ('ORC0023','2015-09-11T08:00:00')
                       ,('ORC0023','2015-08-10T16:00:00')
                       ,('ORC0023','2015-08-11T16:00:00')

DECLARE @UniqueKey VARCHAR(10)='ORC0023';
SELECT @UniqueKey AS [Key]
      ,(
        SELECT DateValue AS [string]
        FROM @tbl AS tbl 
        WHERE tbl.[Key]=@UniqueKey
        FOR XML PATH(''),TYPE
       ) AS baseOrSchedStartList
FOR XML PATH('Job_No'),ROOT('Root')

/*
<Root>
  <Job_No>
    <Key>ORC0023</Key>
    <baseOrSchedStartList>
      <string>2015-09-11T08:00:00</string>
      <string>2015-08-10T16:00:00</string>
      <string>2015-08-11T16:00:00</string>
    </baseOrSchedStartList>
  </Job_No>
</Root>
*/

UPDATE2 对于您的实际查询，这意味着（可能）

尝试将 as '@Key' 更改为 as Key

和

        ORDER BY DATE_TO_END, SortOrder
        FOR XML PATH('baseOrSchedStartList'), Type
)

到

        ORDER BY DATE_TO_END, SortOrder
        FOR XML PATH(''), Type
) AS baseOrSchedStartList

另一种选择是 - 正如 BateTech 在评论中指出的那样 - 将你的 "baseOrSchedStart" 作为 ,ROOT('baseOrSchedStart') 放在 FOR XML PATH('') 后面并让括号未命名...

上一个

没有您的 table 的结构和测试数据，很难完全理解您的查询（实际上超长 :-)）

因此我准备了一个简化的结构示例，希望您能理解该方法并将其转移到您的实际数据中

只需尝试以下操作：

DECLARE @tbl TABLE([Key] VARCHAR(10),DateValue DATETIME);
INSERT INTO @tbl VALUES ('ORC0023','2015-09-11T08:00:00')
                       ,('ORC0023','2015-08-10T16:00:00')
                       ,('ORC0023','2015-08-11T16:00:00')

DECLARE @UniqueKey VARCHAR(10)='ORC0023';

--This is structurally what you've got
SELECT @UniqueKey AS [@Key]
      ,(
        SELECT DateValue AS [string]
        FROM @tbl AS tbl 
        WHERE tbl.[Key]=@UniqueKey
        FOR XML PATH('baseOrSchedStartList'),TYPE
       )
FOR XML PATH('Job_No'),ROOT('Root')

/*
<Root>
  <Job_No Key="ORC0023">
    <baseOrSchedStartList>
      <string>2015-09-11T08:00:00</string>
    </baseOrSchedStartList>
    <baseOrSchedStartList>
      <string>2015-08-10T16:00:00</string>
    </baseOrSchedStartList>
    <baseOrSchedStartList>
      <string>2015-08-11T16:00:00</string>
    </baseOrSchedStartList>
  </Job_No>
</Root>
*/

现在试试这个

SELECT @UniqueKey AS [@Key]
      ,(
        SELECT DateValue AS [*]
        FROM @tbl AS tbl 
        WHERE tbl.[Key]=@UniqueKey
        FOR XML PATH('string'),TYPE
       ) AS baseOrSchedStartList
FOR XML PATH('Job_No'),ROOT('Root')

/*
<Root>
  <Job_No Key="ORC0023">
    <baseOrSchedStartList>
      <string>2015-09-11T08:00:00</string>
      <string>2015-08-10T16:00:00</string>
      <string>2015-08-11T16:00:00</string>
    </baseOrSchedStartList>
  </Job_No>
</Root>
*/

顺便说一句：这与此相同：

SELECT @UniqueKey AS [@Key]
      ,(
        SELECT DateValue AS [string]
        FROM @tbl AS tbl 
        WHERE tbl.[Key]=@UniqueKey
        FOR XML PATH(''),TYPE
       ) AS baseOrSchedStartList
FOR XML PATH('Job_No'),ROOT('Root')

SQL FOR XML 嵌套行列表

SQL FOR XML list of nested rows

sql

sql-server

xml

tsql

for-xml

UPDATE 根据您的

UPDATE2 对于您的实际查询，这意味着（可能）

上一个