Python 模块取消

Question

我知道您可以在 Python 中调用模块本身，但是您也可以在其内部取消它吗？此代码应该只显示一次找到该名称。它会继续打印，直到我中断程序并从 IDLE 中获取 KeyboardInterrupt。关于我应该添加或更改的内容，我能得到一些帮助吗？ P.S.: 我有 Python 3.4.2

from array import *
s = ["Turner", "Philips", "Stevenson", "Jones", "Gonzalez",
"Whitaker", "Bruner", "Webster", "Foster", "Anderson",
"Klein", "Connors", "Rivers", "Wilson", "Duncan"]
g = [94, 82, 87, 78, 65,
90, 85, 97, 70, 100,
57, 88, 73, 92, 84]

s.sort()
for i in range(15):
    idx = int(i)

    studentList = s[idx]
    gradeList = g[idx]

    print(studentList, gradeList)

print("")
print("Student five: ", s[4], g[4])
print("Student ten: ", s[9], g[9])
print("Student fifteen: ", s[14], g[14])

gradeAverage = (g[0] + g[1] + g[2] + g[3] + g[4] + g[5] + g[6] + g[7] + g[8]
              + g[9] + g[10] + g[11] + g[12] + g[13] + g[14]) / 15

print("")
print("The average of the list of the grades is: ", gradeAverage)
print("The median of the list of grades is: ", g[7])
print("")

def byRank():
    studentFound = False
    index = 0
    searchValue = input("Student to be found: ")
    while(studentFound == False) & (index <= len(s) - 1):
        if s[index] == searchValue:
            studentFound == True
            print("Name", searchValue, "was found at index", index)
        else:
            index = index + 1
            print("Name not found. Searching...")
    print("Name is not in the array.")

byRank()

Answer 1

studentFound == True 不会改变 studentFound 的值。使用单个 = 进行赋值。或者只使用 break 来处理像这样的简单情况。

您通常不会使用 while 循环来迭代 Python 中的序列 - 相反，如果您不想使用内置的 index方法：

for index, candidate in enumerate(s):
    if candidate == searchValue:
        print("Name", searchValue, "was found at index", index)
        break

但一次一个问题。

Answer 2

实现 byRank() 功能的正确方法是使用专为此目的而制作的 list.index() 方法。试试更像：

def byRank():
    searchValue = input("Student to be found: ")
    try:
        index = s.index(searchValue)
    except ValueError:
        print("Name is not in the array.")
    else:
        print("Name", searchValue, "was found at index", index)

Answer 3

您的代码中有几个错误。最大的错误是你的 while 循环测试。这是修复程序

def byRank():
    studentFound = False
    index = 0
    searchValue = raw_input("Student to be found: ")
    while not studentFound and index < len(s):
        if s[index] == searchValue:
            studentFound = True
            print("Name ", searchValue, " was found at index ", index)
        else:
            index += 1
            print("Name not found. Searching...")
    print("Name is not in the array.")

仅供参考 -- 如果您愿意放弃您的工作，Tom Hunt 的回答是编写代码的更好方法。

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