将密码学 vb.net 转换为 C#
convert cryptography vb.net to c#
我在 Vb.net 中有一个密码学 class 可以正常工作,但我需要在 c# 代码中进行转换。
我的 Vb.net 方法是这样的:
Public Shared Function CryptSenha(ByVal strCdSenha As String) As String
Dim Chave As String
Const MIN_ASC = 48
Const MAX_ASC = 126
Const NUM_ASC = MAX_ASC - MIN_ASC + 1
Chave = 2001
Dim offset As Long
Dim str_len As Integer
Dim i As Integer
Dim ch As Integer
Dim to_text As String
Try
to_text = ""
offset = NumericPassword(Chave)
Rnd(-1)
Randomize(offset)
str_len = Len(strCdSenha)
For i = 1 To str_len 'Faça 1 até str_len
ch = Asc(Mid$(strCdSenha, i, 1))
'Início do If
If ch >= MIN_ASC And ch <= MAX_ASC Then
ch = ch - MIN_ASC
offset = Int((NUM_ASC + 1) * Rnd())
ch = ((ch + offset) Mod NUM_ASC)
ch = ch + MIN_ASC
to_text = to_text & Chr(ch)
End If
Next i
Return to_text
Catch ex As Exception
Throw ex
End Try
End Function
我的 C# 代码是这样的:
public static string CryptSenha(string strCdSenha)
{
string Chave = null;
const int MIN_ASC = 48;
const int MAX_ASC = 126;
const int NUM_ASC = MAX_ASC - MIN_ASC + 1;
Chave = "2001";
long offset = 0;
int str_len = 0;
int i = 0;
int ch = 0;
string to_text = null;
try
{
to_text = "";
offset = NumericPassword(Chave);
VBMath.Rnd(-1);
VBMath.Randomize(offset);
str_len = Strings.Len(strCdSenha);
for (i = 1; i <= str_len; i++)
{
ch = Strings.Asc(Strings.Mid(strCdSenha, i, 1));
if (ch >= MIN_ASC & ch <= MAX_ASC)
{
ch = ch - MIN_ASC;
offset = Convert.ToInt64((NUM_ASC + 1) * VBMath.Rnd());
ch = Convert.ToInt16((ch + offset) % NUM_ASC);
ch = ch + MIN_ASC;
to_text = to_text + Strings.Chr(ch);
}
}
return to_text;
}
catch (Exception ex)
{
throw ex;
}
}
所以当我在 vb.net 中使用我的函数时,像 'Igor' 这样的简单词等于 "iLCA"
并且在函数 c# 中,单词 'Igor' 等于 "iLDB",我猜想转换
在 c# 代码的这一行中:
offset = Convert.ToInt64((NUM_ASC + 1) * VBMath.Rnd());
有人可以帮助我吗?
您对 'Int' 的转换不正确 - 'Int' 被截断了。替换下面两行代码:
offset = Convert.ToInt32(Math.Floor(Convert.ToDouble((NUM_ASC + 1) * VBMath.Rnd())));
ch = (int)((ch + offset) % NUM_ASC);
我在 Vb.net 中有一个密码学 class 可以正常工作,但我需要在 c# 代码中进行转换。 我的 Vb.net 方法是这样的:
Public Shared Function CryptSenha(ByVal strCdSenha As String) As String
Dim Chave As String
Const MIN_ASC = 48
Const MAX_ASC = 126
Const NUM_ASC = MAX_ASC - MIN_ASC + 1
Chave = 2001
Dim offset As Long
Dim str_len As Integer
Dim i As Integer
Dim ch As Integer
Dim to_text As String
Try
to_text = ""
offset = NumericPassword(Chave)
Rnd(-1)
Randomize(offset)
str_len = Len(strCdSenha)
For i = 1 To str_len 'Faça 1 até str_len
ch = Asc(Mid$(strCdSenha, i, 1))
'Início do If
If ch >= MIN_ASC And ch <= MAX_ASC Then
ch = ch - MIN_ASC
offset = Int((NUM_ASC + 1) * Rnd())
ch = ((ch + offset) Mod NUM_ASC)
ch = ch + MIN_ASC
to_text = to_text & Chr(ch)
End If
Next i
Return to_text
Catch ex As Exception
Throw ex
End Try
End Function
我的 C# 代码是这样的:
public static string CryptSenha(string strCdSenha)
{
string Chave = null;
const int MIN_ASC = 48;
const int MAX_ASC = 126;
const int NUM_ASC = MAX_ASC - MIN_ASC + 1;
Chave = "2001";
long offset = 0;
int str_len = 0;
int i = 0;
int ch = 0;
string to_text = null;
try
{
to_text = "";
offset = NumericPassword(Chave);
VBMath.Rnd(-1);
VBMath.Randomize(offset);
str_len = Strings.Len(strCdSenha);
for (i = 1; i <= str_len; i++)
{
ch = Strings.Asc(Strings.Mid(strCdSenha, i, 1));
if (ch >= MIN_ASC & ch <= MAX_ASC)
{
ch = ch - MIN_ASC;
offset = Convert.ToInt64((NUM_ASC + 1) * VBMath.Rnd());
ch = Convert.ToInt16((ch + offset) % NUM_ASC);
ch = ch + MIN_ASC;
to_text = to_text + Strings.Chr(ch);
}
}
return to_text;
}
catch (Exception ex)
{
throw ex;
}
}
所以当我在 vb.net 中使用我的函数时,像 'Igor' 这样的简单词等于 "iLCA"
并且在函数 c# 中,单词 'Igor' 等于 "iLDB",我猜想转换
在 c# 代码的这一行中:
offset = Convert.ToInt64((NUM_ASC + 1) * VBMath.Rnd());
有人可以帮助我吗?
您对 'Int' 的转换不正确 - 'Int' 被截断了。替换下面两行代码:
offset = Convert.ToInt32(Math.Floor(Convert.ToDouble((NUM_ASC + 1) * VBMath.Rnd())));
ch = (int)((ch + offset) % NUM_ASC);