变量共享
Variable Sharing
我有一个应用程序,当在原始视图上按下按钮时,会弹出另一个视图。基本上,我希望能够从原始视图中的文本字段中获取文本,并将其粘贴到新视图中的标签上。我已经看到了一堆 Obj-c 的答案,但是 none swift。感谢您的帮助!
您可以使用 prepareForSegue
将数据从一个视图传递到另一个视图。
这是相关代码:
ViewController.swift
import UIKit
class ViewController: UIViewController {
@IBOutlet weak var txt: UITextField!
override func viewDidLoad() {
super.viewDidLoad()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if segue.identifier == "goNext" {
let nextView :nextViewController = segue.destinationViewController as nextViewController
nextView.passedData = self.txt.text
}
}
}
下一个ViewController.swift
import UIKit
class nextViewController: UIViewController {
@IBOutlet weak var lbl: UILabel!
var passedData = String()
override func viewDidLoad() {
super.viewDidLoad()
self.lbl.text = self.passedData
}
}
我在这里创建了一个示例项目供您参考:https://github.com/DharmeshKheni/pass-Data-with-prepareForSegue-in-swift
我有一个应用程序,当在原始视图上按下按钮时,会弹出另一个视图。基本上,我希望能够从原始视图中的文本字段中获取文本,并将其粘贴到新视图中的标签上。我已经看到了一堆 Obj-c 的答案,但是 none swift。感谢您的帮助!
您可以使用 prepareForSegue
将数据从一个视图传递到另一个视图。
这是相关代码:
ViewController.swift
import UIKit
class ViewController: UIViewController {
@IBOutlet weak var txt: UITextField!
override func viewDidLoad() {
super.viewDidLoad()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if segue.identifier == "goNext" {
let nextView :nextViewController = segue.destinationViewController as nextViewController
nextView.passedData = self.txt.text
}
}
}
下一个ViewController.swift
import UIKit
class nextViewController: UIViewController {
@IBOutlet weak var lbl: UILabel!
var passedData = String()
override func viewDidLoad() {
super.viewDidLoad()
self.lbl.text = self.passedData
}
}
我在这里创建了一个示例项目供您参考:https://github.com/DharmeshKheni/pass-Data-with-prepareForSegue-in-swift