Redux 通用减速器

Question

我有一个包含许多实体的应用程序，这些实体是从 API 请求的。我想添加一种通用方法来获取任何实体，因为这样我就不需要创建数百个文件，而且我还可以制作一些通用组件（例如 table 显示实体值）在 redux 中执行此操作的最佳做法是什么，或者可能有一些 npm 包。为了清楚起见，我将介绍我是如何不断变化的：

我的通用商店：

var Api = require('../utils/api');
var Reflux = require('reflux');
var Actions = require('../actions');

module.exports = Reflux.createStore({
    listenables: [Actions],

    getEntities: function (entityName) {
        var url = "api/generic/" + entityName;

        return Api.get(url)
            .then(function (json) {
              this.triggerChange(entityName, json);
            }.bind(this));
    },
    triggerChange: function (entityName, json) {
        this.trigger('change', {entity: entityName, value: json});
    },

updateEntity: function (body, entityName) {
  var url = "api/generic/" + entityName + "/edit";
  return Api.post(url, body)
      .then(function (json) {
          this.getEntities(entityName);
      }.bind(this)).catch(this.getEntities(entityName));
},

deleteEntity: function (id, entityName) {
    var url = "api/generic/" + entityName + "/" + id;
    return Api.delete(url)
        .then(function (json) {
            this.getEntities(entityName);
        }.bind(this)).catch(this.getEntities(entityName));
  }

});
And my listener:
onChangeEntities: function (event, result) {
    if (event == "change"){
      var entityName = result.entity;
      var setState = this.setState;
      var dataContext = this.state.dataContext;
      var arr = [];
      dataContext.map(function (element) {
         arr.push(element);
      });
      var state = this.state;
      Entities.map(function (entity) {
         if (entity.name == entityName)
         {
             if (dataContext.filter(function (entity) {
                     return entity.entityName && entity.entityName == entityName;
                 }).length == 0)
             {
                 arr.push({entityName: entityName, value: result.value});
             }
             else{
                 var entity = dataContext.filter(function (entity) {
                     return entity.name && entity.name == entityName;
                 })[0];
                  var keys = Object.keys(dataContext);
                 keys.map(function (key) {
                     if (dataContext[key].entityName == entityName)
                     {
                         arr.splice(key, 1);
                     }
                 });
                 arr.push({entityName: entityName, value: result.value});
             }
         }
      });
      this.setState({dataContext: arr});
    }

Answer 1

您需要编写一个自定义中间件来简化从 api.
中获取数据的过程此方法在 redux 存储库的 real-world 示例中进行了描述。
或者你可以使用 redux-api-middleware 包。

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