MySql

Question

我有一个 table 测试

TestNumber (int primary key)
InactiveBitwise (int)

我执行以下命令：

UPDATE tests SET CASE
        WHEN TestNumber = 2 THEN InactiveBitwise = (InactiveBitwise | 4)
        WHEN TestNumber = 3 THEN InactiveBitwise = (InactiveBitwise | 8)
END WHERE TestNumber IN (2, 3)

但它给出错误

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CASE WHEN TestNumber = 2 THEN InactiveBitwise = (InactiveBitwise |'

TestNumber = 2 和 3 都存在，因为我之前通过调用数据库获得了它们。

有谁知道它不喜欢什么？

Answer 1

您需要指定要更改的列的值，大小写将仅确定返回值：

UPDATE tests SET InactiveBitwise = CASE
        WHEN TestNumber = 2 THEN (InactiveBitwise | 4)
        WHEN TestNumber = 3 THEN (InactiveBitwise | 8)
     END
WHERE TestNumber IN (2, 3)

MySql - Update/Case

MySql - Update/Case

sql-update

case-when