无法在 python3 上分配运算符

Question

我正在学习 python 并尝试使我的代码发挥作用。

## set total sticks number
stick_left = 20
## Given hints, this for statement shows sticks
for _ in range(5): print('|  '*stick_left)
## this condition lasts until stick = 0
while stick_left>0:
    ## first player
    first_player=input('Player1: please pick sticks up to 3 ')
    if first_player>3 or first_player<0:
        print('Please pick between 1-3 stick(s)')
    else:
        stick_left-=first_player
        if stick_left<=0:
            print ('Player1 lost')
            break
        else:
            print('There is %d stick(s) left' %stick_left) ## print how many sticks left
            for _ in range(5): print('|  ' * stick_left)
    ## second player
    second_player = input('Player2: Please pick sticks up to 3 ')
    if second_player > 3 or second_player < 0:
        print('Please pick between 1-3 stick(s)')
    else:
        stick_left -= second_player
        if stick_left <= 0:
            print ('Player2 lost')
            break
        else:
            print('There is %d stick(s) left' % stick_left)
            for _ in range(5): print('|  ' * stick_left)

这是我的代码包含函数

player =0
def player():
    for i in 2:
        player%d %i= input('Player %d:  Please pick sticks up to 3' %i)
        if player >3 or player <0:
            print('Please pick between 1-3 stick(s)')

在第 4 行，我想让它打印 player1 player2，但我只是注意到我不能那样分配运算符。我试过 player_%d %i 但没有成功。有人可以给我建议吗？谢谢！

Answer 1

您不能像这样即时定义变量名。使用字典。

players = {}
def player():
    for i in range(2):
        players[i] = input("Player %d: Please pick sticks up to 3" % (i,))
        # etc

Answer 2

exec() 函数将为您工作。请参考以下代码。

player =0
def player():
    for i in range(1,3):
        exec("player%d = input('Player%d =  Please pick sticks up to 3 ')" %(i,i))
player()

以下是o/p.

Player1 = Please pick sticks up to 3 1

Player2 = Please pick sticks up to 3 2

无法在 python3 上分配运算符

Cannot assign operator on python3

python

operator-keyword