如何在 C# 中序列化-反序列化 DigitalPersona u.ere.u 4500 的指纹并保存到数据库
How to Serialize-Deserialize the fingerprint of DigitalPersona u.ere.u 4500 in C# and saved to a database
你能帮帮我吗?
我想在 mysql 上保存指纹,这是我使用的代码。
private void enrollment_OnEnroll(DPCtlUruNet.EnrollmentControl enrollmentControl, DataResult<Fmd> result, int fingerPosition)
{
if (enrollmentControl.Reader != null)
{
ShowMessage("OnEnroll: " + enrollmentControl.Reader.Description.Name + ", finger " + fingerPosition);
}
else
{
ShowMessage("OnEnroll: lector no conectado, finger " + fingerPosition);
}
if (result != null && result.Data != null)
{
//valor de la huella serializada
string valores = Fmd.SerializeXml(result.Data);
MySqlConnection conexion = new MySqlConnection(_sender.cadena);
String sql = String.Format("insert into cliente (clave_cuenta, huella) values('{0}','{1}')", textBox1.Text, valores );
MySqlCommand comando = new MySqlCommand(sql, conexion);
try {
conexion.Open();
comando.ExecuteNonQuery();
conexion.Close();
MessageBox.Show("La huella se guardo satisfactoriamente","Almacenada",buttons:MessageBoxButtons.OK);
} catch (Exception ex) {
MessageBox.Show(ex.Message);
throw;
}
conexion.Close();
_sender.Fmds.Add(fingerPosition, result.Data);
}
btnCancel.Enabled = false;
// _sender.btnApruebaCompra.Enabled = true;
}
这存储在 mysql
<?xml version="1.0" encoding="UTF-8"?><Fid><Bytes>Rk1SACAyMAAA8gAz/v8AAAFlAYgAxADEAQAAAFYjQIEAZmBkQIEARl5kQMoBKE1jgM8BA0RhgMwAg0tcgNYAZKZcQIIBFB5bgOYA00FaQM8BQFVZQKAAtV9YgLUBEVFYgGUApXNWQOQBIkRUQL0A00RUgPoAckxTQLQAeKVTgG4AcwRTQQMAoKFSQMsA5ptQgMsA65tQQFAAk2xQQREAq0dQgHkA0RhOQEYAoxdCgI8A7Hg/gOEBP00+QFUA4B48gEoAwnQ6QJkA3aA2gJwBAXU2AQMA7UE1AJ0BE2szAQgA7EEuAJwBDqwtAQ4AY6MqAAA=</Bytes><Format>1769473</Format><Version>1.0.0</Version></Fid>
它应该是口蹄疫,但我不能return它的原始形式。
作为 return 到它的正常形状?
string x = Fmd.SerializeXml(fmd);
将 x 作为字符串存储在数据库中。
检索字符串并传入
Fmd val = Fmd.DeserializeXml
(从数据库中检索字符串);
使用 val 与您当前的输入进行比较。
在我的例子中使用 Fmd.DeserializeXml()
给了我这个错误
'\' is an unexpected token. The expected token is '"' or '''. Line 1, position 15
所以我分别使用了下面的序列化和反序列化
Fid.SerialiseXml(CaptureResult.data);
Fid.DeserializeXml(xml string retrieved from db);
你能帮帮我吗? 我想在 mysql 上保存指纹,这是我使用的代码。
private void enrollment_OnEnroll(DPCtlUruNet.EnrollmentControl enrollmentControl, DataResult<Fmd> result, int fingerPosition)
{
if (enrollmentControl.Reader != null)
{
ShowMessage("OnEnroll: " + enrollmentControl.Reader.Description.Name + ", finger " + fingerPosition);
}
else
{
ShowMessage("OnEnroll: lector no conectado, finger " + fingerPosition);
}
if (result != null && result.Data != null)
{
//valor de la huella serializada
string valores = Fmd.SerializeXml(result.Data);
MySqlConnection conexion = new MySqlConnection(_sender.cadena);
String sql = String.Format("insert into cliente (clave_cuenta, huella) values('{0}','{1}')", textBox1.Text, valores );
MySqlCommand comando = new MySqlCommand(sql, conexion);
try {
conexion.Open();
comando.ExecuteNonQuery();
conexion.Close();
MessageBox.Show("La huella se guardo satisfactoriamente","Almacenada",buttons:MessageBoxButtons.OK);
} catch (Exception ex) {
MessageBox.Show(ex.Message);
throw;
}
conexion.Close();
_sender.Fmds.Add(fingerPosition, result.Data);
}
btnCancel.Enabled = false;
// _sender.btnApruebaCompra.Enabled = true;
}
这存储在 mysql
<?xml version="1.0" encoding="UTF-8"?><Fid><Bytes>Rk1SACAyMAAA8gAz/v8AAAFlAYgAxADEAQAAAFYjQIEAZmBkQIEARl5kQMoBKE1jgM8BA0RhgMwAg0tcgNYAZKZcQIIBFB5bgOYA00FaQM8BQFVZQKAAtV9YgLUBEVFYgGUApXNWQOQBIkRUQL0A00RUgPoAckxTQLQAeKVTgG4AcwRTQQMAoKFSQMsA5ptQgMsA65tQQFAAk2xQQREAq0dQgHkA0RhOQEYAoxdCgI8A7Hg/gOEBP00+QFUA4B48gEoAwnQ6QJkA3aA2gJwBAXU2AQMA7UE1AJ0BE2szAQgA7EEuAJwBDqwtAQ4AY6MqAAA=</Bytes><Format>1769473</Format><Version>1.0.0</Version></Fid>
它应该是口蹄疫,但我不能return它的原始形式。
作为 return 到它的正常形状?
string x = Fmd.SerializeXml(fmd);
将 x 作为字符串存储在数据库中。
检索字符串并传入
Fmd val = Fmd.DeserializeXml
(从数据库中检索字符串);
使用 val 与您当前的输入进行比较。
在我的例子中使用 Fmd.DeserializeXml()
给了我这个错误
'\' is an unexpected token. The expected token is '"' or '''. Line 1, position 15
所以我分别使用了下面的序列化和反序列化
Fid.SerialiseXml(CaptureResult.data);
Fid.DeserializeXml(xml string retrieved from db);