2D 距离（“<->”运算符；几何）和 ST_Distance（地理）排序顺序之间的 PostGIS 不匹配

Question

使用 PostgreSQL 9.5.2、PostGIS 2.2，给定以下地理坐标：

'SRID=4326;POINT(24.8713597 60.1600568)'   -- Origin
'SRID=4326;POINT(24.87717970 60.19824480)' -- Destination A
'SRID=4326;POINT(24.91281220 60.15821350)' -- Destination B
'SRID=4326;POINT(24.91404950 60.16373390)' -- Destination C
'SRID=4326;POINT(24.91552820 60.16129280)' -- Destination D

按 "geographical" 距离排序 (ST_Distance method):

select name, st_distance('SRID=4326;POINT(24.8713597 60.1600568)'::geography, geo)
from (select 'SRID=4326;POINT(24.87717970 60.19824480)'::geography as geo, 'A' as name
      union select 'SRID=4326;POINT(24.91281220 60.15821350)'::geography as geo, 'B' as name
      union select 'SRID=4326;POINT(24.91404950 60.16373390)'::geography as geo, 'C' as name
      union select 'SRID=4326;POINT(24.91552820 60.16129280)'::geography as geo, 'D' as name) tmp
order by 2;

结果：

B,2311.075069284
C,2405.58508757
D,2456.504535795
A,4266.971129052

而按 "geometrical" 二维距离 (<-> Operator) 排序：

select name, 'SRID=4326;POINT(24.8713597 60.1600568)'::geometry <-> geom
from (select 'SRID=4326;POINT(24.87717970 60.19824480)'::geometry as geom, 'A' as name
      union select 'SRID=4326;POINT(24.91281220 60.15821350)'::geometry as geom, 'B' as name
      union select 'SRID=4326;POINT(24.91404950 60.16373390)'::geometry as geom, 'C' as name
      union select 'SRID=4326;POINT(24.91552820 60.16129280)'::geometry as geom, 'D' as name) tmp
order by 2;

结果：

A,0.03862894955858695
B,0.041493463474867306
C,0.042847871457636175
D,0.04418579056948194

...我希望顺序完全相同。

我错过了什么？

Answer 1

您正在 60 度纬度处进行计算。这里的纬度比经度大得多。具体地，在60度纬度处，纬度为111.412km，而经度为55.800km。这意味着经度值的分离比纬度值的分离重要得多。

A 24.87717970 - 24.8713597 = 0.006...
B 24.91281220 - ... = 0.041...
C 24.91404950 - ... = 0.043...
D 24.91552820 - ... = 0.044

这与您的结果非常吻合。

2D 距离（“<->”运算符；几何）和 ST_Distance（地理）排序顺序之间的 PostGIS 不匹配

PostGIS mismatch between 2D Distance ("<->" operator; geometry) and ST_Distance (geography) sorting orders

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