Swift 2.2 NSMenuItem 中的选择器

Question

我在 swift 中有一个简单的单文件菜单栏应用程序：

import Cocoa

class StatusBarApp : NSObject {

  func buildMenu() {
    let statusItem = NSStatusBar.systemStatusBar().statusItemWithLength(NSVariableStatusItemLength)
    statusItem.title = "StatusBarApp"

    let menu = NSMenu()

    let aboutMenuItem = NSMenuItem()
    aboutMenuItem.title = "About"
    aboutMenuItem.target = self
    aboutMenuItem.action = #selector(about)
    menu.addItem(aboutMenuItem)

    statusItem.menu = menu
  }

  func about() {
    print("XXX")
  }
}

NSApplication.sharedApplication()
StatusBarApp().buildMenu()
NSApp.run()

我无法将 "About" 菜单栏项连接到 about() 函数。当我运行应用程序时，"About" 项目被禁用。

如何在 Swift 2.2 中将选择器传递给菜单项操作？谢谢

Answer 1

更新操作

aboutMenuItem.action = Selector("about")

并添加

aboutMenuItem.enabled = true

Answer 2

考虑一下：

import Cocoa

class StatusBarApp : NSObject {

    func buildMenu() {
        let statusItem = NSStatusBar.systemStatusBar().statusItemWithLength(NSVariableStatusItemLength)
        statusItem.title = "StatusBarApp"

        let menu = NSMenu()

        let aboutMenuItem = NSMenuItem()
        aboutMenuItem.title = "About"
        aboutMenuItem.target = self
        aboutMenuItem.action = #selector(about)
        menu.addItem(aboutMenuItem)

        statusItem.menu = menu
    }

    func about() {
        print("XXX")
    }
}


let app = StatusBarApp()
NSApplication.sharedApplication()
app.buildMenu()
NSApp.run()

Answer 3

选择器应该有一个参数（NSMenuItem 实例）

aboutMenuItem.action = #selector(StatusBarApp.about(_:))

...

func about(sender : NSMenuItem) {
   print("XXX")
}

编辑：

解决方案是运行应用作为完整 Cocoa 应用包括其代理。
我添加了第二个菜单项来终止应用程序。

import Cocoa

class StatusBarApp : NSObject, NSApplicationDelegate {

  var statusItem : NSStatusItem!

  func applicationDidFinishLaunching(aNotification: NSNotification) {
    statusItem = NSStatusBar.systemStatusBar().statusItemWithLength(NSVariableStatusItemLength)
    statusItem.title = "StatusBarApp"

    let menu = NSMenu()

    let aboutMenuItem = NSMenuItem(title:"About", action:#selector(StatusBarApp.about(_:)), keyEquivalent:"")
    aboutMenuItem.target = self
    let quitMenuItem = NSMenuItem(title:"Quit", action:#selector(StatusBarApp.quit(_:)), keyEquivalent:"")
    quitMenuItem.target = self
    menu.addItem(aboutMenuItem)
    menu.addItem(quitMenuItem)

    statusItem.menu = menu
  }

  func about(sender : NSMenuItem) {
    print("XXX")
  }

  func quit(sender : NSMenuItem) {
    NSApp.terminate(self)
  }
}

NSApplication.sharedApplication()
let statusBarApp = StatusBarApp()
NSApp.delegate = statusBarApp
NSApp.run()

Swift 2.2 NSMenuItem 中的选择器

Swift 2.2 selector in NSMenuItem

cocoa

nsmenuitem

nsstatusbar

swift