在 GAS 中合并 2 JSON 个对象（没有 jquery）

Question

如何像这样合并 2 个（结构相同的）JSON 个对象（在 Google 电子表格脚本中）？

{"records":[{"id":28100988,"work_text_reviews_count":13,"average_rating":"3.10"},{"id":10280687,"work_text_reviews_count":80,"average_rating":"3.87"}]}

{"records":[{"id":16135639,"work_text_reviews_count":0,"average_rating":"0.00"},{"id":17978337,"work_text_reviews_count":2414,"average_rating":"3.76"{"id":360721218,"work_text_reviews_count":4924,"average_rating":"3.98"}]}

合并后的结果应该是：

{"records":[{"id":28100988,"work_text_reviews_count":13,"average_rating":"3.10"},{"id":10280687,"work_text_reviews_count":80,"average_rating":"3.87"},{"id":16135639,"work_text_reviews_count":0,"average_rating":"0.00"},{"id":360721218,"work_text_reviews_count":4924,"average_rating":"3.98"}]}

因为在 Google 电子表格中我无法使用 JQuery，而且我花了一整天的时间尝试 javascript 解决方案，但我无法在没有错误的情况下工作。

Answer 1

你可以使用 concat:

var json1 = {
  "records": [{
    "id": 28100988,
    "work_text_reviews_count": 13,
    "average_rating": "3.10"
  }, {
    "id": 10280687,
    "work_text_reviews_count": 80,
    "average_rating": "3.87"
  }]
}

var json2 = {
  "records": [{
    "id": 16135639,
    "work_text_reviews_count": 0,
    "average_rating": "0.00"
  }, {
    "id": 17978337,
    "work_text_reviews_count": 2414,
    "average_rating": "3.76"
  }, {
    "id": 360721218,
    "work_text_reviews_count": 4924,
    "average_rating": "3.98"
  }]
}


var json3 = json1.records.concat(json2.records);

在 GAS 中合并 2 JSON 个对象（没有 jquery）

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