回溯迷宫算法在 C 中开始错误
Backtracking Maze Algorithm Starts off Wrong in C
过去一周一直在处理这个项目。
除了 initialization/mallocing 和 step 函数之外的所有内容都是我的教授事先提供给我的...
我们的目标不是创造迷宫,而是解决迷宫。
我第一次编译它时,它似乎 运行 很好,并且会稍微通过它...然后,它会开始做一些时髦的事情并跳过一堵墙然后停在那里...
尝试修复它并通过它。最终它没有迈出现在应该迈出的第一步。试图了解我做错了什么或为什么我现在没有做正确的第一步
在我的 maze_client...//provided 但如果需要我可以稍微改变一下
#include <stdio.h>
#include "maze.h"
int main(int argc, char **argv)
{
FILE *fp = fopen(argv[1], "r");
Maze maze = initializeMaze(fp);
findPath(maze);// first step.. It was provided to me. It basically calls step()
displayMaze(maze);
return 0;
}
Step 函数...我做了另一个不是 for 循环的,我试着看看我是否也能摆脱这些废话。没有工作只是让它在其他地方随机开始第一步...第二个文件完成尝试我屏蔽了每个功能...它似乎在我的 if(getBottom)
声明中...我可以写下我的如果需要,我希望它执行的逻辑步骤...
static int step(Maze maze, int row, int column)
{
//TODO: FINISH THE BACKTRACKING ALGORITHM
int i,j;
//int st;
int successful;
//maze->maze[row][column] = st;
if(getVisit(maze, row, column) == maze->maze[maze->finishX][maze->finishY])
{
displayMaze(maze);
return 1;
}
displayMaze(maze);
getchar();
// getVisit(maze, row, column);//gets pos
for(i = -2; i <= 2; ++i)
{
for(j = -2; j <= 2; ++j)
{
//i*i != j*j dont move in diagonal
//row+i >= 0 && row + i < n, bounds checking
//col+j >= 0 && col+j < n, bounds checking
if(i*i != j*j && row+i >= 0 && column+j >= 0 )
{
getVisit(maze, row, column);//Gets position
if(getCellHasTop(maze, row, column + 1) != 1)//Wall check, Zero meaning NO WALL
{
//++st;
//gets that position and sees if it is unvisited...
//need a test if it is visited.. if it has been visited before.. Set current spot as BAD_PATH
if(getVisit(maze,row,column+j) == UNVISITED)
{
setVisit(maze, row, column+1, GOOD_PATH);
successful = step(maze, row, column + 1);
}
// if(getVisit(maze, row, column+j) == GOOD_PATH)
// {
// setVisit(maze, row-i, column, BAD_PATH);
// successful = step(maze, row, column+j);
// }
if(successful)
return 1;
}
if(getCellHasLeft(maze,row - 1,column) != 1)
{
if(getVisit(maze, row-1, column) == UNVISITED)
{
setVisit(maze, row-1, column, GOOD_PATH);
successful = step(maze, row-1, column);
}
// if(getVisit(maze, row-i, column) == GOOD_PATH)
// {
//setVisit(maze, row-i, column, BAD_PATH);
// successful = step(maze, row-i, column);
// }
//++st;
if(successful)
return 1;
}
if(getCellHasRight(maze,row + 1, column) != 1)
{
if(getVisit(maze, row+1, column) == UNVISITED)
{
setVisit(maze, row+1, column, GOOD_PATH);
successful = step(maze, row+1, column);
}
// if(getVisit(maze, row+i, column) == GOOD_PATH)
// {
// setVisit(maze, row+i, column, BAD_PATH);
// successful = step(maze, row+i, column);
// }
//++st;
if(successful)
return 1;
}
if(getCellHasBottom(maze, row, column - 1) != 1)
{
if(getVisit(maze, row, column-1) == UNVISITED)
{
setVisit(maze, row, column-1, GOOD_PATH);
successful = step(maze, row, column-1);
}
// if(getVisit(maze, row, column-j) == GOOD_PATH)
// {
// setVisit(maze, row, column-j, BAD_PATH);
// successful = step(maze, row, column-j);
// }
//++st;
if(successful)
return 1;
}
//PART 2
//Do not do else if because then each one would require... That is last resort
if(getCellHasTop(maze, row, column + 1) == 0)//Wall check
{
//++st;
//a test if it is visited.. if it has been visited before.. Set current spot as BAD_PATH
if(getVisit(maze,row, column+1) == GOOD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row, column + 1);
}
if(successful)
return 1;
}
if(getCellHasLeft(maze,row - 1,column) == 0)
{
if(getVisit(maze, row-1, column) == GOOD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row-1, column);
}
//++st;
if(successful)
return 1;
}
if(getCellHasRight(maze,row + 1, column) == 0)
{
if(getVisit(maze, row+1, column) == GOOD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row+1, column);
}
//++st;
if(successful)
return 1;
}
if(getCellHasBottom(maze, row, column - 1) == 0)
{
if(getVisit(maze, row, column-1) == GOOD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row, column-1);
}
//++st;
if(successful)
return 1;
}
//Part 3
if(getCellHasRight(maze, row + 1, column) != 0 && getCellHasLeft(maze,row - 1, column) != 0)// If there is a wall at those locationsZZ
{
if(getVisit(maze,row, column+1) == BAD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row, column-1);
}
if(successful)
return 1;
}
if(getCellHasTop(maze, row, column + 1) != 0 && getCellHasBottom(maze, row, column - 1) != 0)
{
if(getVisit(maze, row-1, column) == BAD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row+1, column);
}
if(successful)
return 1;
}
if(getCellHasTop(maze, row, column +1) != 0 && getCellHasBottom(maze, row, column - 1) != 0)
{
if(getVisit(maze, row+1, column) == BAD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row-1, column);
}
if(successful)
return 1;
}
}
}
}
displayMaze(maze);
getchar();
return 0;
}
- 函数的完整代码:http://pastebin.com/PtAncpqS
- Header 文件(已提供):http://pastebin.com/zYdCFMfX
- 扫描仪(已提供):http://pastebin.com/4nQdnXTP
- 扫描器header:http://pastebin.com/KjpFf83R
- 第二次尝试:http://pastebin.com/8qyuqtEv
我认为你的问题在于这样的代码:
if(getCellHasTop(maze, row, column + 1) != 1)//Wall check, Zero meaning NO WALL
{
//++st;
//gets that position and sees if it is unvisited...
//need a test if it is visited.. if it has been visited before.. Set current spot as BAD_PATH
if(getVisit(maze,row,column+j) == UNVISITED)
{
setVisit(maze, row, column+1, GOOD_PATH);
successful = step(maze, row, column + 1);
}
// if(getVisit(maze, row, column+j) == GOOD_PATH)
// {
// setVisit(maze, row-i, column, BAD_PATH);
// successful = step(maze, row, column+j);
// }
if(successful)
return 1;
}
首先,您从 -2 迭代到 +2。但我认为迷宫单元是连续的,所以你不应该那样做。相反,做这样的事情:
首先,测试 row,col 以确保它们是迷宫中的有效位置。接下来,测试当前单元格的位以查看是否允许您向上或任何方向。然后测试目标单元格是否有效。然后测试目标单元格是否被您已经经过它的路径阻挡。那就跳进去吧。
enum {
TOP_BLOCKED = 0x01,
RIGHT_BLOCKED = 0x02,
BOTTOM_BLOCKED = 0x04,
LEFT_BLOCKED = 0x08,
};
#define ABOVE(r,c) (r),((c)+1)
#define BELOW(r,c) (r),((c)-1)
#define LEFT_OF(r,c) ((r)-1),(c)
#define RIGHT_OF(r,c) ((r)+1),(c)
#define IN_MAZE(m,r,c) ((r)>=0 && (c)>=0 && (r)<(m)->rows && (c)<(m)->cols)
#define CELL(m,r,c) ((m)->maze[(r)][(c)])
#define TOP_OPEN(m,r,c) (in_maze(m, r, c) \
&& !(CELL(m,r,c) & TOP_BLOCKED)
&& in_maze(m,ABOVE(r,c)))
#define VISITED(m,r,c) (getVisit(m,r,c) != UNVISITED)
// ... later, in your step function ...
#define POS row,column
setVisit(maze, POS, GOOD_PATH);
if (TOP_OPEN(maze, POS) && !VISITED(maze, ABOVE(POS)) && step(maze, ABOVE(POS))) {
// We found a successful path! Stop looking.
return 1;
}
if (RIGHT_OPEN(maze, POS) ... && step(maze, RIGHT_OF(POS))) {
return 1;
}
if (BOTTOM_OPEN ...
if (LEFT_OPEN ...
return 1;
}
// There is no path from here that solves the maze.
setVisit(maze, POS, UNVISITED);
#undef POS
return 0;
过去一周一直在处理这个项目。 除了 initialization/mallocing 和 step 函数之外的所有内容都是我的教授事先提供给我的...
我们的目标不是创造迷宫,而是解决迷宫。 我第一次编译它时,它似乎 运行 很好,并且会稍微通过它...然后,它会开始做一些时髦的事情并跳过一堵墙然后停在那里...
尝试修复它并通过它。最终它没有迈出现在应该迈出的第一步。试图了解我做错了什么或为什么我现在没有做正确的第一步 在我的 maze_client...//provided 但如果需要我可以稍微改变一下
#include <stdio.h>
#include "maze.h"
int main(int argc, char **argv)
{
FILE *fp = fopen(argv[1], "r");
Maze maze = initializeMaze(fp);
findPath(maze);// first step.. It was provided to me. It basically calls step()
displayMaze(maze);
return 0;
}
Step 函数...我做了另一个不是 for 循环的,我试着看看我是否也能摆脱这些废话。没有工作只是让它在其他地方随机开始第一步...第二个文件完成尝试我屏蔽了每个功能...它似乎在我的 if(getBottom)
声明中...我可以写下我的如果需要,我希望它执行的逻辑步骤...
static int step(Maze maze, int row, int column)
{
//TODO: FINISH THE BACKTRACKING ALGORITHM
int i,j;
//int st;
int successful;
//maze->maze[row][column] = st;
if(getVisit(maze, row, column) == maze->maze[maze->finishX][maze->finishY])
{
displayMaze(maze);
return 1;
}
displayMaze(maze);
getchar();
// getVisit(maze, row, column);//gets pos
for(i = -2; i <= 2; ++i)
{
for(j = -2; j <= 2; ++j)
{
//i*i != j*j dont move in diagonal
//row+i >= 0 && row + i < n, bounds checking
//col+j >= 0 && col+j < n, bounds checking
if(i*i != j*j && row+i >= 0 && column+j >= 0 )
{
getVisit(maze, row, column);//Gets position
if(getCellHasTop(maze, row, column + 1) != 1)//Wall check, Zero meaning NO WALL
{
//++st;
//gets that position and sees if it is unvisited...
//need a test if it is visited.. if it has been visited before.. Set current spot as BAD_PATH
if(getVisit(maze,row,column+j) == UNVISITED)
{
setVisit(maze, row, column+1, GOOD_PATH);
successful = step(maze, row, column + 1);
}
// if(getVisit(maze, row, column+j) == GOOD_PATH)
// {
// setVisit(maze, row-i, column, BAD_PATH);
// successful = step(maze, row, column+j);
// }
if(successful)
return 1;
}
if(getCellHasLeft(maze,row - 1,column) != 1)
{
if(getVisit(maze, row-1, column) == UNVISITED)
{
setVisit(maze, row-1, column, GOOD_PATH);
successful = step(maze, row-1, column);
}
// if(getVisit(maze, row-i, column) == GOOD_PATH)
// {
//setVisit(maze, row-i, column, BAD_PATH);
// successful = step(maze, row-i, column);
// }
//++st;
if(successful)
return 1;
}
if(getCellHasRight(maze,row + 1, column) != 1)
{
if(getVisit(maze, row+1, column) == UNVISITED)
{
setVisit(maze, row+1, column, GOOD_PATH);
successful = step(maze, row+1, column);
}
// if(getVisit(maze, row+i, column) == GOOD_PATH)
// {
// setVisit(maze, row+i, column, BAD_PATH);
// successful = step(maze, row+i, column);
// }
//++st;
if(successful)
return 1;
}
if(getCellHasBottom(maze, row, column - 1) != 1)
{
if(getVisit(maze, row, column-1) == UNVISITED)
{
setVisit(maze, row, column-1, GOOD_PATH);
successful = step(maze, row, column-1);
}
// if(getVisit(maze, row, column-j) == GOOD_PATH)
// {
// setVisit(maze, row, column-j, BAD_PATH);
// successful = step(maze, row, column-j);
// }
//++st;
if(successful)
return 1;
}
//PART 2
//Do not do else if because then each one would require... That is last resort
if(getCellHasTop(maze, row, column + 1) == 0)//Wall check
{
//++st;
//a test if it is visited.. if it has been visited before.. Set current spot as BAD_PATH
if(getVisit(maze,row, column+1) == GOOD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row, column + 1);
}
if(successful)
return 1;
}
if(getCellHasLeft(maze,row - 1,column) == 0)
{
if(getVisit(maze, row-1, column) == GOOD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row-1, column);
}
//++st;
if(successful)
return 1;
}
if(getCellHasRight(maze,row + 1, column) == 0)
{
if(getVisit(maze, row+1, column) == GOOD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row+1, column);
}
//++st;
if(successful)
return 1;
}
if(getCellHasBottom(maze, row, column - 1) == 0)
{
if(getVisit(maze, row, column-1) == GOOD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row, column-1);
}
//++st;
if(successful)
return 1;
}
//Part 3
if(getCellHasRight(maze, row + 1, column) != 0 && getCellHasLeft(maze,row - 1, column) != 0)// If there is a wall at those locationsZZ
{
if(getVisit(maze,row, column+1) == BAD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row, column-1);
}
if(successful)
return 1;
}
if(getCellHasTop(maze, row, column + 1) != 0 && getCellHasBottom(maze, row, column - 1) != 0)
{
if(getVisit(maze, row-1, column) == BAD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row+1, column);
}
if(successful)
return 1;
}
if(getCellHasTop(maze, row, column +1) != 0 && getCellHasBottom(maze, row, column - 1) != 0)
{
if(getVisit(maze, row+1, column) == BAD_PATH)
{
setVisit(maze, row, column, BAD_PATH);
successful = step(maze, row-1, column);
}
if(successful)
return 1;
}
}
}
}
displayMaze(maze);
getchar();
return 0;
}
- 函数的完整代码:http://pastebin.com/PtAncpqS
- Header 文件(已提供):http://pastebin.com/zYdCFMfX
- 扫描仪(已提供):http://pastebin.com/4nQdnXTP
- 扫描器header:http://pastebin.com/KjpFf83R
- 第二次尝试:http://pastebin.com/8qyuqtEv
我认为你的问题在于这样的代码:
if(getCellHasTop(maze, row, column + 1) != 1)//Wall check, Zero meaning NO WALL
{
//++st;
//gets that position and sees if it is unvisited...
//need a test if it is visited.. if it has been visited before.. Set current spot as BAD_PATH
if(getVisit(maze,row,column+j) == UNVISITED)
{
setVisit(maze, row, column+1, GOOD_PATH);
successful = step(maze, row, column + 1);
}
// if(getVisit(maze, row, column+j) == GOOD_PATH)
// {
// setVisit(maze, row-i, column, BAD_PATH);
// successful = step(maze, row, column+j);
// }
if(successful)
return 1;
}
首先,您从 -2 迭代到 +2。但我认为迷宫单元是连续的,所以你不应该那样做。相反,做这样的事情: 首先,测试 row,col 以确保它们是迷宫中的有效位置。接下来,测试当前单元格的位以查看是否允许您向上或任何方向。然后测试目标单元格是否有效。然后测试目标单元格是否被您已经经过它的路径阻挡。那就跳进去吧。
enum {
TOP_BLOCKED = 0x01,
RIGHT_BLOCKED = 0x02,
BOTTOM_BLOCKED = 0x04,
LEFT_BLOCKED = 0x08,
};
#define ABOVE(r,c) (r),((c)+1)
#define BELOW(r,c) (r),((c)-1)
#define LEFT_OF(r,c) ((r)-1),(c)
#define RIGHT_OF(r,c) ((r)+1),(c)
#define IN_MAZE(m,r,c) ((r)>=0 && (c)>=0 && (r)<(m)->rows && (c)<(m)->cols)
#define CELL(m,r,c) ((m)->maze[(r)][(c)])
#define TOP_OPEN(m,r,c) (in_maze(m, r, c) \
&& !(CELL(m,r,c) & TOP_BLOCKED)
&& in_maze(m,ABOVE(r,c)))
#define VISITED(m,r,c) (getVisit(m,r,c) != UNVISITED)
// ... later, in your step function ...
#define POS row,column
setVisit(maze, POS, GOOD_PATH);
if (TOP_OPEN(maze, POS) && !VISITED(maze, ABOVE(POS)) && step(maze, ABOVE(POS))) {
// We found a successful path! Stop looking.
return 1;
}
if (RIGHT_OPEN(maze, POS) ... && step(maze, RIGHT_OF(POS))) {
return 1;
}
if (BOTTOM_OPEN ...
if (LEFT_OPEN ...
return 1;
}
// There is no path from here that solves the maze.
setVisit(maze, POS, UNVISITED);
#undef POS
return 0;