来自 InputStream 的 AudioInputStream(从资源目录加载)

AudioInputStream from InputStream ( load from resource directory)

在 IDE 中试用我的应用程序时,我尝试从我的资源文件夹加载我的声音。

对于使用 InputStreams 的图像和其他内容,我使用此方法:

@Override
public InputStream readAsset(String fileName) throws IOException {
    ClassLoader classloader = Thread.currentThread().getContextClassLoader();
    InputStream is = classloader.getResourceAsStream(fileName);
    return is;
}

这让我可以打开一个输入流,我可以从中提取图像。

当我尝试将此 InputStream 转换为 Audio InputStream 时,我收到了错误。另外,如果我尝试制作一个新的 AudioInputStream 将上述 InputStream 作为参数传递。

这是我目前从外部路径加载声音的方式:

public class JavaSound implements Sound {

private Clip clip;


public JavaSound(String fileName){
    try {
        File file = new File(fileName);
        if (file.exists()) {

            //for external storage Path
            AudioInputStream sound = AudioSystem.getAudioInputStream(file);

            // load the sound into memory (a Clip)
            clip = AudioSystem.getClip();
            clip.open(sound);
        }
        else {
            throw new RuntimeException("Sound: file not found: " + fileName);
        }
    }
    catch (MalformedURLException e) {
        e.printStackTrace();
        throw new RuntimeException("Sound: Malformed URL: " + e);
    }
    catch (UnsupportedAudioFileException e) {
        e.printStackTrace();
        throw new RuntimeException("Sound: Unsupported Audio File: " + e);
    }
    catch (IOException e) {
        e.printStackTrace();
        throw new RuntimeException("Sound: Input/Output Error: " + e);
    }
    catch (LineUnavailableException e) {
        e.printStackTrace();
        throw new RuntimeException("Sound: Line Unavailable Exception Error: " + e);
    }


}

@Override
public void play(float volume) {

    // Get the gain control from clip
    FloatControl gainControl = (FloatControl) clip.getControl(FloatControl.Type.MASTER_GAIN);

    // set the gain (between 0.0 and 1.0)
    float gain = volume;
    float dB = (float) (Math.log(gain) / Math.log(10.0) * 20.0);
    gainControl.setValue(dB);

    clip.setFramePosition(0);  // Must always rewind!
    clip.start();
}

@Override
public void dispose() {
    clip.close();
}
}

我如何交换 AudioInputStream 部分以像第一个代码一样工作,将文件从我的资源目录中拉出?

编辑: 这种通过传递 InputStream

创建新 AudioInputStream 的方式
File file = new File(fileName);
        if (file.exists()) {
            ClassLoader classloader = Thread.currentThread().getContextClassLoader();
            InputStream is = classloader.getResourceAsStream(fileName);

            //for external storage Path
            AudioInputStream sound = new AudioInputStream(is);

            // load the sound into memory (a Clip)
            clip = AudioSystem.getClip();
            clip.open(sound);
}

甚至在 运行 之前也会抛出错误

您不能将 InputStream 转换为 AudioInputStream(您可以反过来)。 Clip.open() 想要一个 AudioInputStream。

by this answer here 建议的一种方法是使用 .getResource() 调用中的 URL,而不是尝试打开 InputStream 然后将其传入。

因此,尝试:

URL soundURL = classloader.getResource(fileName);
AudioInputStream ais = AudioSystem.getAudioInputStream(soundURL);

这使它在我上面的代码中起作用:

public JavaSound(String fileName){
    try {

        ClassLoader classloader = Thread.currentThread().getContextClassLoader();
        InputStream is = classloader.getResourceAsStream(fileName);
        AudioInputStream sound = AudioSystem.getAudioInputStream(new BufferedInputStream(is));

        // load the sound into memory (a Clip)
        clip = AudioSystem.getClip();
        clip.open(sound);
    }
    catch (MalformedURLException e) {
        e.printStackTrace();
        throw new RuntimeException("Sound: Malformed URL: " + e);
    }
    catch (UnsupportedAudioFileException e) {
        e.printStackTrace();
        throw new RuntimeException("Sound: Unsupported Audio File: " + e);
    }
    catch (IOException e) {
        e.printStackTrace();
        throw new RuntimeException("Sound: Input/Output Error: " + e);
    }
    catch (LineUnavailableException e) {
        e.printStackTrace();
        throw new RuntimeException("Sound: Line Unavailable Exception Error: " + e);
    }


}

只需用我的 inputStream 启动一个新的 bufferedInputStream 来获得 AudioInputStream...:D 仍然非常感谢 ;)